How to Solve Inclined Plane Problems
Physics Ninja look at 3 inclined plane problems. 1) Determine the speed at the bottom of the ramp and the time is takes to get to the bottom. 2) Given an initial speed up the ramp find the max distance up the ramp (includes kinetic friction) 3) Find the tension in the rope if the block is in equilibrium.
Пікірлер: 80
Great explanation, teacher I was struggling so much with this kind of problems. The result at the end is not correctly evaluated though, it should be T = 19,67 N Thank you teacher. For more people like you in the world
Best video I've seen explain this. Should have so many more views.
Your explanations are excellent thank you very much.
I had to refresh before my final exams tomorrow and this was godsend. Thank you so much, I respect you sir deeply.
Third perspectives helps. Thanks.
I've been struggling with this for years lol thank you so much! but really to understand this video, I have to self study about angles first 😅
@PhysicsNinja
7 ай бұрын
You got this!
thanks for your motive and go ahead.
Great explanation sir, keep it up. Upload more video on physics.
can I ask.. how to get the angle if you have a mass 100kg , 5m long inclined plane and P.e of 2450J?
when you calculate acceleration in the first problem why do you use sin35 x 5.36? ive never learned it that way//used it like that with the sin component to find time...
When do you use sin vs cos? Thanks.
bless tysm
Is X at the front of the block or at the back of the block?
Why is the angle for calculating components x and y 35degree and no 55degree. Still learning this.
Using the relationship between Potential and Kinetic energy and solving for "h". "h" being the altitude necessary for block to gain the velocity 15 m/s. Why is equation h = v^2/2g incorrect when solving X = h/sin(35).
In problem 2 can you explain why the acceleration is down the incline when you have given an initial velocity upward?
@fredsmith6324
11 күн бұрын
slowing down, negative acceleration, or opposite the direction of the velocity. if acceleration is opposite the direction of motion, it indicates it's still moving in the original direction, but slowing down. equivalent to a negative acceleration.
Kinetic force should be opposite to Wx, right?
Thank you at least I have understood a bit
at 20:01 you wrote (ma = mgsin - umgcos) but on top you have (mgsin + uN = ma), why did it change from addition to subtracting?
@PhysicsNinja
Жыл бұрын
Because for this problem it’s sliding up the ramp and slowing down. Friction is in the opposite direction.
@rosalinechirishian5006
Жыл бұрын
@@PhysicsNinja but shouldnt Wx be negative as well since its in the same direction as the friction?
@captainplane398
Жыл бұрын
@@rosalinechirishian5006 i think so too
@noorsharma1284
Жыл бұрын
@@rosalinechirishian5006 that's what im saying too, so would the acceleration be negative -6,8m/s^2 ??
@owennkuna5802
11 ай бұрын
@@rosalinechirishian5006 i was also thinking that Wx and Fk both pointing in the negative direction .Hence shud both be -ve
@ 20:00 How did you go from mgsin(theta) "+" mu_kN = max, then substituted in N, mgcos(theta) to somehow get mgsin(theta) "-" mu_k(mgcos(theta)? How does substituting in N suddenly change the expression to "-"? And if I calculate (9.8)(sin35 "+" 0.15cos(35)) I get 6.83... If I use the negative expression you derived after subbing in the N, I get 4.41 m/s. Not sure what's going on here. Please elaborate?
@kkanyetrump
Жыл бұрын
I actually had the same question, but after solving, it was nothing but a typo
Bro , Plz do on thermodynamics and kinetics theory of gases
guys at 20.56 it was meant to be a + not -. Thats why you get 6.83
@captainplane398
Жыл бұрын
yes i thought so too
@owennkuna5802
11 ай бұрын
Fk and Wx are both -ve ,How is it meant to be +ve?
Ben affleck, my hero!
No, I didn't mean well. What force is applied to the inclined surface? It means that the force enters the inclined surface from behind and the inclined surface moves
why is the force in the x component downward is it not sliding up
@zanderman27
Жыл бұрын
I believe it's because the initial velocity is 15m/s which means initially, the net force is 0 since it is in constant velocity. Although, once it starts to slide up, it accelerates downward, which means the forces in the X direction are pointing downward.
at 19:58, shouldn't it be plus, not minus? both forces acting downhill. also, it wouldn't it be more intuitive to make your positive x direction uphill? (direction of motion, and what they are asking for). i realize either way works.
@PhysicsNinja
11 күн бұрын
I think I made an error on this problem. Sorry about that, was going too fast.
@fredsmith6324
11 күн бұрын
@@PhysicsNinja no prob, great vids! thanks a lot, really working for me and my son who is about to do the AP exam.
the shelf behind you is stressing me out
Hello, what force should be applied to the inclined surface so that the mass does not move
@BoxOfCurryos
5 ай бұрын
the block will not move if Fnet = 0N it is in static equillibrium (velocity and acceleration are 0)
Great teaching, but Force is vector quantity and you should stay within the coordinate system you define. Tension should be negative.
last question should be 19.67?
@kkanyetrump
Жыл бұрын
yes
@krissullivan593
Ай бұрын
He can't just go on and edit the video. He would have to create an entire new video and upload it to fix the answer. Hopefully, people will be able to realize that it's just a simple case of getting numbers mixed up in your head. I do this all the time, and according to everyone else that I talk to in the calculus/physics world, is something that almost everyone does.
You could of also calculate the time with Ep=Ek and a=v/t
@superhessu3
2 жыл бұрын
The time to go down the ramp i mean
@superhessu3
2 жыл бұрын
Since it is also frictionless so mechanical energy conserves
Isn't Tension = 19.7N in the last question?
@jairymwakapola2871
Жыл бұрын
My thought to
@italianplumber8859
Жыл бұрын
Same here. He misread the answer and switched the positions of 6 and 9. It is 19.7 N in 3 s.f. (19.69374694 N)
@owennkuna5802
11 ай бұрын
yes even in Problem acceleration should be 4.42m/s2
@owennkuna5802
11 ай бұрын
*Problem 2
Why is g positive and not negative 9.8?
@captainplane398
Жыл бұрын
normally g is negative because it goes in the opposite direction of whatever force is being calculated, here we consider g as positive because we consider the left direction of the hypotenuse as the positive direction, which is why we get a negative for things like our final displacement because thats in the opposite direction of g, so the right direction of the hypotenuse. It doesnt matter though, the signs only mean direction, so you can have negative g and get positive answers., as long as ur directions are consistent g
How to make a video like this 😢
In the first question I'm almost certain you got the distance wrong. The distance is essentially the hypotenuse of the plane, and you used the height instead of the calculated distance to evaluate the time it takes to reach the final position. And why are you calculating the acceleration twice in the kinematic equation? You have sin(35)•(5.62) but that isn't making sense.
@PhysicsNinja
4 ай бұрын
Thanks, I’ll fix it
@PhysicsNinja
4 ай бұрын
Just checked and first is correct. The sin35 comes from calculating the distance x=h/sin35
@GeraldBosley-cf8ng
4 ай бұрын
Okay, thanks for clarifying!
Does any one get tension 19.67
So when calculating time, we need to define a distance; here it ignores size of block 😂
Thank you but it is very very veryyyy veryyyyyy HARD!!
6:21 that isn't a right angle down by the Mg LMAO There are more errors in this than a Tour de France drug test
16:30 The time calculation is clearly wrong
21:00 accelaration is wrong
@PhysicsNinja
2 жыл бұрын
Expression is right, somehow I entered wrong in calculator.
@kevinbelza8294
2 жыл бұрын
@@PhysicsNinja We got the same answer sir, Its just that Wx and Ff must add up.
@redbitch3362
2 жыл бұрын
@@PhysicsNinja no
@JosephAMuniz-hm4jh
Жыл бұрын
@@kevinbelza8294 I also get the same 6.83 if I enter (9.8)(sin35 "+" .15cos35) Not sure how subbing in N changed it from sin(theta) "+" mu_kN =max turned it into sin(theta) "-" mu_kN = max? How the hell does that happen? I get 4.41 if I use (9.8)(sin35 "-" .15cos35)
@owennkuna5802
11 ай бұрын
@@JosephAMuniz-hm4jh i also got 4.41 using his expression with a "-"
wayyy complicated and confusing explanations...
@johnpatrickpenaflor5018
2 ай бұрын
It's understandable
@cocomatef
2 ай бұрын
it could be better...way better!@@johnpatrickpenaflor5018
Wrong!
@yusufabdalla1106
Жыл бұрын
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