Problem solving with Newton's Laws of Motion. Free Body Diagrams. Net Force, mass and acceleration
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Пікірлер: 31
@houseplant1016Ай бұрын
Heroes don't wear capes, they explain physics in a simple and quick way, big thanks from Belgium! ;)
@smithjomiddlesexmass
Ай бұрын
Wow, thanks!
@vivamoreali3885Ай бұрын
This guy is literally saving me in College Physics w/ Calc right now!! Sir, you're literally explaining better than any other video I've seen out there. Guys, look through his channel!! It's a game changer I promise!
@smithjomiddlesexmass
Ай бұрын
Thanks!
@DAIANESILVA-bp1me Жыл бұрын
You are great professor, thank you
@owenroldan2155 күн бұрын
AAAAA THIS HELPED ME SO MUCH IN MY FINALS
@smithjomiddlesexmass
5 күн бұрын
Great!
@ritik2028Ай бұрын
thanks man, i have a pilot assesment with an airline on 25th needed this to brush up
@smithjomiddlesexmass
Ай бұрын
Your welcome!
@SI-nm2jz3 ай бұрын
this video was super helpful, than you so much professor.
@smithjomiddlesexmass
Ай бұрын
You're very welcome!
@julypetrus8390 Жыл бұрын
Thank you sir
@Abdimalik_Educate4 ай бұрын
tnks professor
@venusbean63306 күн бұрын
I have a quiz tomorrow hopefully this will help me
@smithjomiddlesexmass
5 күн бұрын
Good luck!
@venusbean6330
5 күн бұрын
@@smithjomiddlesexmass I did very well ! 19/20 Thank you professor
@smithjomiddlesexmass
5 күн бұрын
Your welcome!
@julianagomez33423 ай бұрын
super helpful video thank you
@smithjomiddlesexmass
Ай бұрын
you're welcome!
@cagandemir2023 Жыл бұрын
At first quesiton, why we didn't use Fn for calculating acceleration.(NOT FNETX)
@Abdimalik_Educate
4 ай бұрын
cause at the y direction the acceleration is zero there is no acceleration there, that is why we did not use the Fn because Fn is in y direction
@ritik2028Ай бұрын
18:46 i though tension will be zero as from both sides 9.8 on the same rope but if we image the tension going upwards they will cancel each other out, can you clear my this doubt please
@smithjomiddlesexmass
Ай бұрын
Start by looking at just one mass. Since the mass is at rest (not accelerating) the net force on it must be zero from Newton's 2nd Law. Therefore the magnitude of the tension must be equal to the weight of the mass (mg). Think of the tension in the rope as the way the two masses communicate their presence with each other. So each mass is pulling up on the other mass with its weight.
@user-ry4qd1ys6w2 ай бұрын
Am not sure about acceleration on the second example
@smithjomiddlesexmass
2 ай бұрын
The blocks will move together, so they will have the same acceleration. Another way to think about it is to picture the two blocks together as one big mass of 30 kg. So the acceleration of both blocks together is equal to the applied force divided by the combined mass. This is what my solution shows.
@omerhaddad-uz3wg11 күн бұрын
in the 2nd example how does F12 = F21 while both have different masses
@smithjomiddlesexmass
9 күн бұрын
From Newton’s Third Law. The force that object one exerts on object two must be equal in magnitude to the force that object two exerts on object one
@mpshoxxsquare_pants72782 ай бұрын
😭😭what if you're required to calculate the pull force itself?
@smithjomiddlesexmass
Ай бұрын
You would have to be given the acceleration. Then you could calculate the pull force from that and the mass using Newton's 2nd Law.
@ritik2028Ай бұрын
23:56 why the tensions are equal the masses are different>???
@smithjomiddlesexmass
Ай бұрын
Think of the tension as the way each mass exerts a force on the other. So these have to be equal (think Newton's 3rd law). What will be different for each mass is the net force
Пікірлер: 31
Heroes don't wear capes, they explain physics in a simple and quick way, big thanks from Belgium! ;)
@smithjomiddlesexmass
Ай бұрын
Wow, thanks!
This guy is literally saving me in College Physics w/ Calc right now!! Sir, you're literally explaining better than any other video I've seen out there. Guys, look through his channel!! It's a game changer I promise!
@smithjomiddlesexmass
Ай бұрын
Thanks!
You are great professor, thank you
AAAAA THIS HELPED ME SO MUCH IN MY FINALS
@smithjomiddlesexmass
5 күн бұрын
Great!
thanks man, i have a pilot assesment with an airline on 25th needed this to brush up
@smithjomiddlesexmass
Ай бұрын
Your welcome!
this video was super helpful, than you so much professor.
@smithjomiddlesexmass
Ай бұрын
You're very welcome!
Thank you sir
tnks professor
I have a quiz tomorrow hopefully this will help me
@smithjomiddlesexmass
5 күн бұрын
Good luck!
@venusbean6330
5 күн бұрын
@@smithjomiddlesexmass I did very well ! 19/20 Thank you professor
@smithjomiddlesexmass
5 күн бұрын
Your welcome!
super helpful video thank you
@smithjomiddlesexmass
Ай бұрын
you're welcome!
At first quesiton, why we didn't use Fn for calculating acceleration.(NOT FNETX)
@Abdimalik_Educate
4 ай бұрын
cause at the y direction the acceleration is zero there is no acceleration there, that is why we did not use the Fn because Fn is in y direction
18:46 i though tension will be zero as from both sides 9.8 on the same rope but if we image the tension going upwards they will cancel each other out, can you clear my this doubt please
@smithjomiddlesexmass
Ай бұрын
Start by looking at just one mass. Since the mass is at rest (not accelerating) the net force on it must be zero from Newton's 2nd Law. Therefore the magnitude of the tension must be equal to the weight of the mass (mg). Think of the tension in the rope as the way the two masses communicate their presence with each other. So each mass is pulling up on the other mass with its weight.
Am not sure about acceleration on the second example
@smithjomiddlesexmass
2 ай бұрын
The blocks will move together, so they will have the same acceleration. Another way to think about it is to picture the two blocks together as one big mass of 30 kg. So the acceleration of both blocks together is equal to the applied force divided by the combined mass. This is what my solution shows.
in the 2nd example how does F12 = F21 while both have different masses
@smithjomiddlesexmass
9 күн бұрын
From Newton’s Third Law. The force that object one exerts on object two must be equal in magnitude to the force that object two exerts on object one
😭😭what if you're required to calculate the pull force itself?
@smithjomiddlesexmass
Ай бұрын
You would have to be given the acceleration. Then you could calculate the pull force from that and the mass using Newton's 2nd Law.
23:56 why the tensions are equal the masses are different>???
@smithjomiddlesexmass
Ай бұрын
Think of the tension as the way each mass exerts a force on the other. So these have to be equal (think Newton's 3rd law). What will be different for each mass is the net force