If only our professors/teachers could be as crystal clear as you! Thank God for your brilliant mind. Keep up the excellent work.

@PhysicsNinja

3 жыл бұрын

Thank you so much

@veronicanjovu8353

2 ай бұрын

Well explained thanks for your time

@hael3516

Ай бұрын

professors as in university... im in highschool learning this 😰

Wow, you saved my life. I’m forever indebted to you.

@aldrinjames2565

3 жыл бұрын

OA

@CallmeMizami

Ай бұрын

​@@aldrinjames2565Fsfs

First video about this subject that I actually understood, and, more importantly, learned something new!

Thank You so much for making this video. It really helped me in my online class, especially self study is not easy. Thank you for sharing your ideas that is very clear and so understandable. God bless and more power!

This is in fact the single most helpful video on the internet. Thank you.

@PhysicsNinja

Жыл бұрын

Glad you think so!

Great Job, thank you. Trying to explain it to my son and came across this video. It reminds me of my teacher

Thank you so much! This video really helped me see the breakdown of the equations used to find the specifics (time, max height, vertical height, etc.) Please keep making videos and thank you :)

This is the best projectile motion video of all time

I understand everything you said because you know how to reach us😊😊👍👍

Thanks alot sir, excellent way of explaining complicated stuff... I had huge doubts in projectile motion, i looked at many videos but only found this one useful and best...

@PhysicsNinja

3 жыл бұрын

Thank you so much!! Good luck with your studies. I wish you much success.

@ayushagrawal4275

3 жыл бұрын

@@PhysicsNinja thanks sir...

Thank you so much! the explanation is very nice and smooth thank you again sir have a great day ahead

thank you for your effort, patient and very precise explanation.

Such a lifesaver! Better than my professors

This video made the concept so much easier, i get it now

Every time I thought "why is he doing that??" you explained it perfectly.

Wow u are an amazing professor!! Easily understood

@PhysicsNinja

3 жыл бұрын

Thank you!

THANK YOU!!!!! it's so clear now, i was so confused. earned a sub

Great vid, in the last equation you can simplify 2 sin theta cos theta to -> sin2theta

This 20 mins video is clearer than our 1hr discussion-

This helped me on my exam ~thankyou from India

You are the reason I did not get an F in my midterm, thank you Physics Ninja

May i ask how did you simplify that ymax formula to its simplest form from that more complex ymax formula, i am just confused

The video is really helpful, thank you. But I feel like it would have been more clear if you used numbers on your examples, and can the final range formula be further simplified into (v initial^2*(sin teta*)2)/g because I assume the angles will be the same?

@MathPhysicsEngineering

2 жыл бұрын

If you are interested in an in-depth analysis of the geometry and the physics of projectile motion I recommend: kzread.info/dash/bejne/eoSZyqWOppnIdbw.html&ab_channel=Math%2CPhysics%2CEngineering

Thank you! you make my physics more easier.

Thank you now I understand this topic wayyy better

If you are interested in an in-depth analysis of the geometry and the physics of projectile motion I recommend: kzread.info/dash/bejne/eoSZyqWOppnIdbw.html&ab_channel=Math%2CPhysics%2CEngineering

Very clear explanation Thank you 😊

Now everything projectile seems like child's play. Dam easy. Thanks a million 🙏

bro thank god for this man

Really wish I could hear this video. Turned my TV volume all the way up on the chrome cast, tried AirPods, the sound is so low. I do appreciate the making of it tho! Just a remark

This helped, thank you.

this video was insanely helpful, thank you so much

Thank you so much. this is very helpful.

Thanks a lot, sir.

nice work but what about the angle at which the particle hits the ground?

Awesome video

Thank you so much sir i was studying for the MCAT and i was struggling with this concept but now i understood it properly and much more confident

@PhysicsNinja

3 жыл бұрын

Good luck with the MCAT

Very helpful!

Watching from Africa and this has made me think smart 😊💯💯💯

@PhysicsNinja

Жыл бұрын

I hope you succeed in your studies

omg so clear tysm 😊

Thank you teacher❤

you are damn good professor.

Wooow , tomorrow is my exam and you really saved my life , appreciate it ❤️❤️❤️❤️

@PhysicsNinja

Жыл бұрын

Best of luck!

If at a time T the direction of the velocity is at 90 degrees to the initial direction of the velocity is given in a problem what can you derive from that?

Thank you sensei, how may I repay you for your help.

is the initial height same as the maximum height? cuz i have only have the velocity and the angle, ive already solved for the max height but the time and range i cant seem to solve it because i need the int. height

for time up, the formula is velocity x divide by -9.8) , so the time will become -ve value. is it true?

Great vid but i have a small question, in my school book it says that time to reach maximum height= -vy divided by g, which is -9.8m/s2, is there a difference between this and the one in the video?

@PhysicsNinja

3 жыл бұрын

at 14:26 i write an equation for t_top=v_0*sin(theta)/g. This is the same as the equation you wrote. the vy in your equation is the initial y component of the velocity.

Nicely done my brother.

@PhysicsNinja

8 ай бұрын

Thank you kindly

This is 10/10

Very nice

I have the average speed and the time the projectile takes to reach the ground, I need to calculate the range and maximum height, please help

Legend

Thank you 😊

If the angle is not given, how would you go about solving the problem?

thank you so much!!!

@PhysicsNinja

6 ай бұрын

You're welcome!

Sir can you help me. I nedd a some biomechanics problems.( segmemt lenth segment mass , COM )

Thanks im using this for a program on a rocket

In real life world, would it be fair to assume that there would be a deceleration of the motion in x-axis due to air friction? or is it negligible? If negligible, does that mean if i plot the graph of horizontal distance covered over time it will be a straight line and straight to zero when the final Y is 0?

@dinukaherath7155

2 жыл бұрын

In the real world, you would need to include air resistance as it has a non-negligible deceleration on the x and y motion of the projectile. I can’t remember the formula for drag off the top of my head but it is necessary for the real world.

At 6:28 why above equation before g has 1/2 but below equation doesnt have?

I need help in calculating the trajectory length. Yes, it's the length of the parabola or projectile not the horziontal or vertical displacement. Any help?

@PhysicsNinja

2 жыл бұрын

You first need to write y vs x. You can do this by eliminating time. Then you will need to find the arc length. This is a standard math problem. I suggest googling it. It will involve integrating a square root function of dy/dx

What if the object is initially displaced upwards?

life saver :)

which quadratic equation satisfy this path ???

Thanx bro

شكرا جزيلا لك شرح ممتاز جدا

Great

Ur the best tnx

Hi can I just ask how to solve time in projectile motion? The t=1s t=2s t=3s

how would i do a question lik this A projectile is fired with an initial velocity of 120 ms-1. The projectile has a time of flight of 18.75s. Determine: a) The range of the projectile; b) The maximum height attained, and the time at which this height is attained;

Lovely

Helpful

You're an iron man, wow, that's great. Huge accomplishment. That jacket is cool.

@PhysicsNinja

3 жыл бұрын

There’s no greater accomplishment in life than finishing an Ironman.

@DonSimone1996

3 жыл бұрын

@@PhysicsNinja you're damn right, sir

You really make me proud sir I now know what I did not do

@PhysicsNinja

7 ай бұрын

You got this!

2 sin a cos a = sin 2a. Therefore, max range is when a = 45 degrees.

i heart you.

what if I have to find the time when the y displacement is 10 ?? considering there will be two answers

@duttroach8489

3 жыл бұрын

There are indeed two points where ∆y = 10. In this example, one answer will have a positive Vy and the other will have a negative Vy, assuming it isn't the top of the arc.

It s very clear

what if the projectile had acceleration, per say, a rocket. the rocket acceleration is in a changing direction. and the parabola is less circular (longer on the +y path and shorter on the -y). What would be added?

@coleflynn7538

22 күн бұрын

this equation is true for a cannon or snipers sake, but a rocket that dosent have one blast that sets it in motion (rather a continuous acceleration in its trajectory ) is written differently, How?

my physics exam is tomorrow and i still dont understand projectiles which will most definitely be there but theres so many other units to study theres no time 😭

What would happen if the initial velocity upon launch is 0? Or is that not possible?

@PhysicsNinja

4 жыл бұрын

That’s the easiest case- Maximum height=0, Range=0

@iamvan7243

4 жыл бұрын

Thank you! i get it now

sir I think v is not initial Velocity v is final Velocity and u is intial velocity...

I have the max height and range and need to find initial velocity, I’ve been stuck for ages send help

@PhysicsNinja

3 жыл бұрын

I will post a video tonight on a basketball problem that deals with this. Stay tuned!!

@guapdoctor4534

3 жыл бұрын

Physics Ninja thank you so much!

10Q keep it up

How come i now understand ballistic calculations but i still cant understand polar patterns being taught by my precal II teacher

I was told that range was |v|^2 * sin(2theta) / g, is this the same as 2Vo^2 * sin(theta) * cos(theta) / g?

@PhysicsNinja

8 ай бұрын

Same, using a trigonometric metric identity 2sinxcosx=sin2x

Great explanation, liked and subscribed. I can definitely use your equations when the next extinction asteroid strikes and rips away our atmosphere, or if I go to the moon where there is no air drag. How about a video with air drag of say a BB weighing 0.334 grams and Vo of 204.5 m/s and calculate for Vy and Range; else, it's all theoretical, but not of our reality, but very interesting and I highly appreciate what you have done in such an interesting and entertaining educational manner. Stay safe and God speed.

Can you make a video on the equation of trajectory of the projectile motion😊

@PhysicsNinja

9 ай бұрын

Yes, maybe this weekend

@tanmoydev

9 ай бұрын

@@PhysicsNinja thank you sir 🤗.

is dy the maximum height?

i love you bless you

Goood bro

Ahxante xan

❤

can total delta y displacement can be negative?

@PhysicsNinja

8 ай бұрын

Yes, if you drop inside a hole. Negative displacement simple tell you the direction. Negative would down relative to where you started.

@user-vb3xl9sx2x

8 ай бұрын

@@PhysicsNinja my problem is like this on the video "a ball has been thrown with initial velocity of 28m/s at 30° angle" my delta y displacement is negative did I answer it right? thank you sir

But what if there's no given angle? The only given are distance and time. How to find the maximum height?

@duttroach8489

3 жыл бұрын

Which time(s) and distance(s) are you given? If you have the ∆x for t(max), or position & time of impact, then you should have your Vx for when Vy = 0 because Vx is constant. If your starting height and impact height are the same, the parabola from start to finish will be symmetrical, therefore, its midway point will be half of t(max). Long story short, you have to work backwards, and your max height is tangeant to the highest point on the parabola.

@beymonbros2785

3 жыл бұрын

@@duttroach8489 what happens if you have no given angle but only have speed and distance/range how would you solve for Vy?

What about the X value when Y is at its max

@xinyinpianoanimemusic1697

2 жыл бұрын

1/2 of range, since it is symmetrical

CALCULATE THE VELOCITY WITH WHICH THE BALL LEAVESTHE PLAYER HAND IN 5 SECOND? WHEREBY NO DISPLACEMENT. HELP PLEASE

Examples would be really fucking helpful

@bananachipsyum636

3 жыл бұрын

Don’t be mean :/

🌷

G is pointing down so it negative but where’s the 1/2 gt square coming from

@anleal9587

3 жыл бұрын

the kinematic equation