Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Full 56 Minute Video: www.patreon.com/MathScienceTutor Direct Link to The Full Video: bit.ly/3WKkZrZ

@huyanhle

2 жыл бұрын

Dear Sir, Please clarify anything wrong here ? 3:41 - Triangle on the "right" compares to triangle on the "left" (the red line you have just drawn ==> Should it be x-line direction and the other one should be y-line direction (meaning other way around)? That is x = mg sin (theta) and y = mg cos (theta) ?

@huyanhle

2 жыл бұрын

Sir, Please compare carefully situation between 7:14 and 8:44. To me, it is "the same" Seem to me that you are treating object moving to the "Right-Hand-Side" direction is "+ve". Right? Hence, Fx = -ve as object moves Left-Hand-Side in 8.44 ==> ax = -ve ==> 7:14 = 8:44, that is, Fx = -Fg - Fk

@mohitforimprovement

2 жыл бұрын

@@huyanhle Yes, that's true. As long as we stick to one frame of reference. We should be getting the same answer. we should be getting both the magnitude and direction correct.

@ronellmavhungu1163

2 жыл бұрын

Hi. I know you deserve remuneration for your efforts but some of us cannot afford to pay for the patreon. I really wish there was another way because your videos are helpful and I really need them

Start 0:14 formulas,2:16 finding acceleration,5:20 friction then acceleration,7:18 sliding up,8:45 another sliding up problem,10:12 problem solution 1 ,14:15 problem solution 2

@andrea-op9cg

2 жыл бұрын

THANK YOU

@stephaniesguide8320

2 жыл бұрын

Hey thank you!

@menglimarrero4296

2 жыл бұрын

9:43 Sir how could it is sliding up in the left direction if the acceleration is going to the right(down)?

@brendanmeyers1301

7 ай бұрын

@@menglimarrero4296 there is a starting velocity that you didn't take into account

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@joser7376

3 жыл бұрын

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@nikhlreddy3534

3 жыл бұрын

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@faithjosiah8337

2 жыл бұрын

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@daiwikpathok5647

2 жыл бұрын

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@MoonlightMaggie

2 жыл бұрын

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The angle description to prove where theta is on the force triangle you gave is what I needed! Thank you!

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@steve4718

Жыл бұрын

this is 9th grade physics..

@Ace_v120

Жыл бұрын

@@steve4718 and people are taking it in college and its not easy for everyone

@ponycatty

11 ай бұрын

@@steve4718 its 11th grade physics for me :)

@steve4718

11 ай бұрын

@@ponycatty 9th grade for me

@ponycatty

11 ай бұрын

@@steve4718 thats cool, i wonder what physics youll learn in grade 11 then

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Professor Organic Chemistry Tutor, thank you for an awesome video/lecture on The Introduction to Inclined Planes in Physics/Engineering Physics. The free body diagrams are the heart and soul of solving inclined plane physics problems. All physics students must know how to draw and analyze free body diagrams in physics. This is an error free video/lecture on KZread TV with the Organic Chemistry Tutor.

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this is really helpful

For getting Fx why are you using sin instead of cos? I thought we would always use cos for x and sin for y like in kinematics?

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My exam is in 20 minutes and I'm watching all the math vector vids I can find LOLLLL I'm screwed.

@sweetpopcorn9579

7 ай бұрын

How did it go

@CalviNsiku

3 ай бұрын

And you still have time to comment 💔😂😂lol

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@jiwon9438

2 жыл бұрын

😆

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@lorymaljian6547

2 ай бұрын

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@ragdolldude3440

Ай бұрын

I have a test in 2 hours lol

@themax6589

19 күн бұрын

Haha so true

WELL DONE 100%

I love u pal u save my physics

Thanks for the explanation 🙏.. now how do you tell the direction which the free body diagram should face to give you a postive or a negative value for acceleration ? 😓😓

@spbros2497

10 ай бұрын

Sir, this is my doubt too

Omigosh, THANKS!!!

at 2:53 Fnet on y-axis should be zero to say that Fn=mg cos(angle), while the object is moving at an angle which means that it's moving with acceleration on x and y axes which means Fnet on y, is not equal to zero

God bless you sir...

MAN I LOVE YOU JULIO

20:38 this is debatable, making it come to a stop makes it seem like there is friction on the incline which is not included in calculations. gravity will ultimately pull the block back down. what i did was multiply the time it takes to get to its max height by 2, which is saying that it will reach a max height and then go back to where it started.

U are the best really