By far the most effective explanation of balancing redox reactions (along with your acidic solutions video). Thank you!

THANK YOU , THANK YOU, THANK YOU!!! I am so appreciative. My professor is SO HORRIBLE and this explanation makes so much sense, I completely understand this now! I am so grateful.

You definitely have the most helpful half reaction videos on KZread

I just spent my precious time on the right channel. Thank you!

You have no idea how much your videos help me in class! Thanks so much for taking the time to load them and open them to other students ;)

@ConnecticutSavvy You're welcome. It's funny - I started making these videos because I would blow through stuff quickly, my students would ask questions and I would look at them and say, "I already explained that three times."

It's done on a SmartBoard. Sometimes I prepare the pages in advance and narrate as I scroll through. When I'm in a hurry, I record it "live" and you may hear the pen on the board.

OMG after looking at so many videos i finally understand watching this one THANKS

Very helpful! My independent study unit is on this, and it's difficult to teach this stuff to yourself! I'm glad I found your videos!

holy crap batman. thank you so so much! you sir, have saved me from failing my chem test :')

Perfect. Very clear and straight forward

wow why couldn't my teacher have made it this simple? Thanks a lot!

THANK YOU! your 5 steps really helped me. it finally makes sense to me!

You are a god send to anyone taking AP Chem.

Thanks you. My professor blows through stuff so quickly and if we ask a question he looks at us as says, "I already explained that once." Nonsense!!

Thank you for posting this video. This is very helpful!!

Thank you so much! I was having the hardest time balancing these types of equations and now I finally understand it. just in time for finals!

Thank you, this video was a huge help!

Your videos helped me a lot. Thank you so much!

This is an outstanding explanation, thank-you.

thnakyou so much i have a midterm on wednesday. Your videos are really helpful

best explanation I have seen.

super helpful video - thanks so much!

Dude thank you so much, going to pass my AP chem test!

I love this video man

again, excellent!

Thank you SO MUCHH!! U saved my life!!!

great video, thank u for ur help!!!

fantastic teaching. thanks mate

Love the video. Just out of curiosity, what setup are you using to make these? It sounds like you're writing on a whiteboard.

I finally understand... Thank you!

thank you so much.... you are a gr8 teacher....

Great video thanks soo much!

thank you so much man!

i love you dude!

superb! easy to understand

thanks a lot...it help me so much !!!!!

because everybody has 13 minutes to waste on a question on a SAT chemistry test, though it is very informative, thank you :)

this helped me alot Thanks!!!!!! :D

thank you for you help . I have small question! what's happen if we don't get H atom in the final equation do we have to add OH atom in both sides?

very good explanations!

Thx alot thats was great !!

Very helpful!

H2O does not have a charge (it is electrically neutral). Therefore the equation is (3 x 0) + (1 x (-1)) = -1 I think the confusion came from the way I had the 3 H2O written on the board. The "+" sign shown next to the H2O is showing that we are adding H2O and the Br- ion in the reaction, just like we are adding the BrO3- plus the H+. I can see how you thought I meant it as a charge number.

great video!

Hi can someone help to derive eqn for cro2 disproportionation to cr2o7^2- and cr3+? My eqn is 3e- +h2o +3cro2→cr2o7^2-+cr3++2h+ and thats incorrect. Can you also explain the steps to get to the correct answer?

I was doing some other example and after neutralizing with the OH- ion and balancing out, the oxidation numbers didn't balance out on both sides. So, what can one do in such a case?

it's a big help for me....

how do you know exactly what side to add the electrons to?

@Chem2Farr Please tell me do you use this specific technique just when you get the full equations (i.e Mno4 + Br --> Mn0 + Br03 is given therefore you use your technique in video).What is the point of doing all these calculations if the formula is already on the right side? (i.e Mn0 + Br03). Would you use the same technique in the video if you were only given the Mno4 + Br and asked to balance it out on the right side? I am educating myself with chemisty and finding it very hard...

please read! how does the 3H20 charge of plus 3 added to bromide's negative 1 charge give us -1? isnt 3-1 equal 2?

thank you so much my good sir.

is there any way to know whether this reaction is a basic or acidic solution, in case this information is not given? thank you!

Excellent thank you

Very helpful :D

excellent!!!!!!

Thank you (Y) very helpful

Hi, I have a question? When you were done with balancing, you multiplied the top rxn or middle line (05:57 in the video) by 2. My question is, could we multiply the middle rxn by 6 and then the bottom rxn by 3? If I do this would that be wrong? Thank you!

THANK YOU.

this is da bomb

Messy but informative, thanks!

is H ion usable when we are balancing basic media.....don't we use OH ion ?am lost please help

the question wants it to be basic at the end, meaning the ending equation must contain an OH- as opposed to an H+ (acids usually contain H+, while OH- corresponds to bases)

Thank you! Helped a lot! #GreatWork

Thank you sir.

Holy shit. Vielen Danke!

Thank youuu so much. I have a question how can we know if it`s a basic or acid solution?

Good stuff

If you did that, the equation would balance, but the coefficients would not be in the lowest, whole-number ratio. You would be multiplying all the coefficients by a factor of 3 that isn't necessary. In the end you would have to divide everything by 3 to make your final answer correct.

than you very much

awesome :D

how is the difference between a +5 and -1 is a 6 i don't get that! @ 4:59 please answer

@10:19. How did you end up with 2H2O molecules, when there is 2H+ and 2OH-? Im not seeing it clearly.

GOT IT!!! =)

thank u

if i could marry a video for helping me, I'd definitely marry this one.

thanks

That's puzzle! Is there another way to arrive at the same answer?

The last step doesn't make sense to me. Why would you want to get rid of the two water molecules if the chemical formula would be balanced as each side would have two water molecules. Why would you get rid of them to only have a single water molecule on both the reactant and product side?

First take the absolute value of + 5 which is just 5 and then take the absolute value of - 1 which is 1 then add the two absolute values together which is 6. You can also understand this better by drawing a number line and labeling the line with values and see that the difference between positive five and negative one is 6.

i love your username: chem 2 farr... the man who took chemistry too far.

What if there are no H+ at the end of my redox equation because they have been cancelled since they occur on both sides? This is for basic so I should add OH- but I don't know how to??

@ConnecticutSavvy I'm having the same problem, the Chem teacher has a TON of information to get through in a semester, it's up to us to get it sorted and stored unfortunately (redox is giving me fits, too)

same here

HELP DO YOU KNOW HOW TO BALANCE THIS EQUATION? 4Fe² + O2 → 4Fe + 2O²-

How do you know if it is acidic or basic?:$ you keep saying it's basic but how would you know that?

why are you add 6 H+ in right side

Did I just get taught chemistry by Obama

i still dont understand why you multiplied the first equation by 2

And that's when we silently cry inside and stop trying ;_;

i love you man, no homo.

lol man because first half was with 3 electrons and the other 6 electrons and u should have the same electrons in both of them so he multiplied the first half by 2!

@ConnecticutSavvy lol thats crappy for him to say

You said this was meant to be in a basic solution, so why is everything done as it was an acidic solution? You use OH- when doing basic, and H+ in an acidic solution...

@UthmanHamit_u_th_man_dammit

10 жыл бұрын

When doing "half reactions (basic solutions)" you have to first balance the reaction in acid, then you can add the OH- to neutralize those H+ ions, that would make it a basic solution :)

@walshy0001

9 жыл бұрын

Tara Schiumo you clearly didn't watch the entire video lol

@taraschiumo89

9 жыл бұрын

Well I was actually taught differently from what this video was showing me LOL.

HOLY CRAP!!!! I didn't know Barack Obama did chemistry tutorials!!! How does he have time for this! Well, at least he can balance chemical equations. We should have chemists working on the budget then!

yikes! But seriously, this helped

You use OH- when using a basic redox reaction.

@brockhays6032

8 жыл бұрын

+Brock Hays You literally made that problem 10x harder than it actually is.

l can't understand you .is it an acidic or basic reaction

@1996hanz

10 жыл бұрын

First, we need to do in acidic way..then we add OH- to neutralize H+ to make it in basic solution..don't you get it..

@muketemulango6477

10 жыл бұрын

Are we suppose to add H and OH anywhere or the is a rule

@1996hanz

10 жыл бұрын

1st we need to use H+ to balance hydrogen atom..at the end of the equation..add OH- in both sides to make it in basic..

@1996hanz

10 жыл бұрын

Number of mole of OH- is depend on the number of mole of H+ ....they must be the same in order to get water..

Mr Farr can i use the bathroom?

I never knew Obama used to be a teacher on youtube.