Balancing Redox Reactions with Half Reaction Method

Using the half-reactions method to balance Redox reactions - examples in both acidic and basic solution are given.

Пікірлер: 52

  • @romainebrown5787
    @romainebrown57872 жыл бұрын

    I don't know if you still monitor this video but I am really thankful for your very straight forward explanation of this topic. By far the best I have seen. Thank you so much

  • @TokiBird
    @TokiBird7 жыл бұрын

    This is by far the best tutorial and I've been binge-watching a whole lot tonight. Helped me out so much. Thank you!

  • @aaronrobles9875
    @aaronrobles98757 жыл бұрын

    This was some pretty detailed info, but after watching this video about 7 times its easily understood. thanks

  • @phil1pd
    @phil1pd5 жыл бұрын

    Thank you for the excellent example problems and explanation!

  • @katierobey-bhamani4435
    @katierobey-bhamani44357 жыл бұрын

    wow thank you! I mean that from the bottom of my heart this is so helpful to me it being midnight and my test is tomorrow morning! needless to say I am cramming and this is one small part of one chapter and its a four chapter test! YIKES!

  • @vaibhavfsawasthi3909
    @vaibhavfsawasthi39097 жыл бұрын

    i viewed this just before my board exam , and i was sucessfull in balancing rxn of d block by this concept

  • @user-dl7eq2hr4p
    @user-dl7eq2hr4p7 жыл бұрын

    Thank you every much! Very satisfied with this video

  • @hhjggfffhkhjjf7800
    @hhjggfffhkhjjf78007 жыл бұрын

    thankyou so much for giving us such a good idea for balancing

  • @commodorekitty
    @commodorekitty7 жыл бұрын

    Very helpful. Thank you for explaining this topic clearly. 😁

  • @zacharykubersky5157
    @zacharykubersky51577 жыл бұрын

    greatest video of all time!!!!

  • @alenjohnson9873
    @alenjohnson98736 жыл бұрын

    Nice but want more examples

  • @aayataltamimi9325
    @aayataltamimi93257 жыл бұрын

    That's amazing, thank you so much!

  • @InfinityByTerry
    @InfinityByTerry7 жыл бұрын

    Thank you so much, you hav been extremely helpful!

  • @ruthyepez6220
    @ruthyepez62209 жыл бұрын

    This helped sooooo much, thank you!

  • @tomiwajohnson3456
    @tomiwajohnson34565 жыл бұрын

    it's 2018 and this video is still helpful

  • @wearenoless6732
    @wearenoless67327 жыл бұрын

    thanks a lot sir. it was indeed really helpful.

  • @jasonmaip1755
    @jasonmaip17558 жыл бұрын

    thank you sir,this video really helped.

  • @thesd828
    @thesd8288 жыл бұрын

    Outstanding, Thank you so much, never understood half reactions, your video is terrific why do you need to balance it like this other than for tests?

  • @howtheJunk15
    @howtheJunk158 жыл бұрын

    thanks man great help!!!

  • @viktamade
    @viktamade8 жыл бұрын

    from Tanzania.....this has helped me a lot...Hakuna matata tena.....God bless u

  • @yahyamohammed5418
    @yahyamohammed54187 жыл бұрын

    I wish I could like this video ten times :'D

  • @chempatenaude
    @chempatenaude9 жыл бұрын

    ambidex@med... after balancing in acidic solution as I've shown in the video, you could just add enough H2O to BOTH sides of the equation to convert all the H+ to H3O+. So in the example I show here, you would add 10 H2O to both sides ... resulting in 15 H2O on the left and 10 H3O+ on the right. When balancing in basic solution, just add enough OH- to neutralize all the H3O+ in your equation ... keeping in mind that OH- and H3O+ will make 2 H2O.

  • @suhaerosman2117

    @suhaerosman2117

    7 жыл бұрын

    Thank you sir!

  • @shrivathsajoisa
    @shrivathsajoisa6 жыл бұрын

    Thanks.....u have great experience

  • @benjamingabbal
    @benjamingabbal3 жыл бұрын

    Thank you so much!!

  • @shaijuantony9293
    @shaijuantony92937 жыл бұрын

    nicely explained thanks a lot

  • @honeysingh6055
    @honeysingh60557 жыл бұрын

    very very helpful ...................

  • @boucanada
    @boucanada8 жыл бұрын

    thank you very much

  • @suhaerosman2117
    @suhaerosman21177 жыл бұрын

    Took me a while to apprehend it but completely worthwhile! You just explained to me something in 17 min which took my teacher almost a week.. well maybe because my teacher had taught be all the basics of oxidation and reduction state!😂

  • @suhaerosman2117

    @suhaerosman2117

    7 жыл бұрын

    That's why i was able to understand your examples^

  • @rinkisharma9734

    @rinkisharma9734

    6 жыл бұрын

    This video help me so much in balancing .I only want say thanks for this video

  • @Nicholas-ut1dw
    @Nicholas-ut1dw7 жыл бұрын

    thank you this helped me alot

  • @ambidex0med
    @ambidex0med9 жыл бұрын

    Hi. Is there a method for changing the equation into H30+ instead of H+? H3O+ is so much harder and my professor told me I had to use H3O+ method.

  • @volkansoylu3202
    @volkansoylu32026 жыл бұрын

    Man you're the bestt

  • @diamondakpanika9667
    @diamondakpanika96673 жыл бұрын

    Thank you so much☺

  • @adewaleoluwatimehin2696
    @adewaleoluwatimehin26967 жыл бұрын

    Thank you Sir!

  • @ummeruman1912
    @ummeruman19125 жыл бұрын

    Thank you so much ....

  • @hayatamna965
    @hayatamna9657 жыл бұрын

    thanks a lot for this good video ☺☺☺☺😊

  • @maximum0006
    @maximum00063 жыл бұрын

    Sir you missed 2 water molecules on right side of basic redox reaction

  • @ayeshakhan-hb6oy
    @ayeshakhan-hb6oy8 жыл бұрын

    thanxxx sir

  • @razanhalabi9384
    @razanhalabi93846 жыл бұрын

    Thanks Thanks Thanks !!!

  • @sunjidaakhter2090
    @sunjidaakhter20906 жыл бұрын

    thank u sir....

  • @ayeshahayat9151
    @ayeshahayat91514 жыл бұрын

    I was thinking that we balance basic by OH negative ions

  • @camerontraber4033
    @camerontraber40332 жыл бұрын

    So your electrons don’t have to be balanced at the end

  • @chempatenaude

    @chempatenaude

    2 жыл бұрын

    Hello Cameron. I’m not sure why you concluded that. The electrons must cancel out when we combine the 2 half-reactions. That means the number of electrons gained in the reduction half reaction must equal the number of electrons lost in the oxidation half reaction. This is achieved when you multiply each half reaction by a coefficient to make the electrons lost equal to the electrons gained. Right before you re-combine.

  • @shyedfarhan
    @shyedfarhan8 жыл бұрын

    in base ; how r u multiplying it by 2..

  • @chempatenaude

    @chempatenaude

    8 жыл бұрын

    Hey Farhan ... are you referring to about 13:20 in the video? If so, I multiply the top half reaction by 2 so that the two half reactions have equal numbers of electrons

  • @shyedfarhan

    @shyedfarhan

    8 жыл бұрын

    thanks...

  • @killah8309
    @killah83093 жыл бұрын

    Yo im grade 10 and im learning this college stuff wtf

  • @neelamarya1940
    @neelamarya19405 жыл бұрын

    In basic , don' t we have to add OH-

  • @chempatenaude

    @chempatenaude

    5 жыл бұрын

    Neelam Arya ... for basic solutions I first balance as though it is acidic. Then I add OH- to both sides to neutralize the acid and form H2O. Look at the example in the video. :)

  • @neelamarya1940

    @neelamarya1940

    5 жыл бұрын

    @@chempatenaude OK