i cant believe how easy hess cycles are thanks to your explanation

Well said, well said (applause). You have single handedly saved the education system and future aspirations of 40,000 people. Good Job!

This is an Underrated channel, Thanks for saving my time and saving my grades in the exam, I hope the best for you and your channel, Keep going.

Wow, real eye opener, my teacher kept telling me other things i found confusing. Thank you very much sir.

after 2 years i finally understood it thank u sm

Absolutely amazing, thanks!

I had problem deciding the direction of the arrow and how to make a equation. Now I finally get it, thanks 😊.

TYSM, for this wonderful explanation.

Amazing video, you deserve a lot more!

Thanks man, you're a grade saver!

Thank you maj you really made me understand hess law now it doesnt confuse me anymore may God bless you

Excellent step by step tutorial

Thanks a lot sir, this is a very helpful video 😊

Thank you soooooooooo much 🎉

Thank u so much can't imagine how much u saved me ❤❤❤

most underrated channel

Besttt explanation ever 🤩

You have explained it so beautifully. Thank you for your work! Gudjob🩷

Thank you ❤

Wow !! This is extra ordinary. Please try to make more videos on redox as well

Thank you.

Thank you. You saved me big time….

Bro Saved me!!!!!!

youre a lifesaver

Thanks a million. I'm so confused about bond enthalpy cycle. Now it's clear for me.Can you upload other more examples for bond enthalpy cycles?

You deserve a million subscribers!! thank you for this!!

@Chemistorian

Жыл бұрын

Thanks, I'm glad you enjoyed it :)

@vortax521

9 ай бұрын

@@Chemistorian thank you man😁😁

You the best man 😇😇😇😇😇

good explanation

Thanks a lot this was really helpful....

@Islamicreminder19

3 ай бұрын

This was much more understandable than anything else I've been taught

Easiest explanationn🖤🖤🖤 love from pakistan

tysm man

u are amazinggg :)) understood

best vid on youtube explaining this topic

Thank u

thankyou bro

Thank you thank you 😊

Bruda fr I love ya

Please can you also do how you do the rearranging?🙏

hi do we have t use the arrow method? can i just use products-reactants

amazinggg

if some of the formation enthalpies of the compounds are not given for a combustion reaction, how do we go from there?

Legend

If we do it this way in the A-Levels, do we still get the full mark?

@Chemistorian

2 жыл бұрын

Absolutely! As long as you come out to the correct answer, you'll get the marks.

Could you upload more examples? i understood but wld be more confident with more practice

I mean if you think about it all the routes have to add up to 0 so you could also just add up the other 2 and work out the final one from that

Isn't rearranging just reversing the symbols, though i don't get the purpose of the extra step

Hi, I’m confused on the bond enthalpy section. Why do the arrows face downwards? Is it due to the reaction being combustion?

@xdbackflip

Ай бұрын

They actually point upwards but this guy's not smart so he's doing it a dumb way where the elements in their standard states are on the left. Because this guy is dense he failed to mention this.

would u consider making videos on rates of reaction / equilibriums bc i’ve always found it hard to tell what side the reaction would shift too if temp changes etc

@Chemistorian

2 жыл бұрын

Funnily enough, my next video (coming out in a couple of days) is going to be on equilibrium constants, but I can definitely make a longer video on rates & equilibria if it'll be helpful.

@bella-iu7bl

2 жыл бұрын

@@Chemistorian that’d be perfect thank u!

Thank you very much for your video tutorial. I have a couple of questions, why do you use H(c) when explaining the formation of the hess cycle, and during the combustion you use H(f). is it correct? we were taught that enthalpy change formation is H(f), and combustion is H(c)

@Chemistorian

6 ай бұрын

During the enthalpy of formation example, we have been given enthalpies of formation, and we use them to construct a FORMATION Hess cycle, in order to work out the enthalpy of combustion of methane. That reaction at the top could have been anything, but in this case, it shows the enthalpy of combustion of methane. We still construct a FORMATION Hess cycle here, because we've been given values of Hf, NOT Hc. For the second example, it's just the other way around. We've been given Hc values, so we construct a COMBUSTION Hess cycle to work out the enthalpy change for the reaction at the top, which happens to be the formation of benzene. So in the first example, we're using enthalpies of formation to work out the enthalpy of combustion of methane, and in the second example, we're using enthalpies of combustion to work out the enthalpy of formation of benzene.

Hi, just wanted to ask for the Hess cycle we can still use the top arrow as the biggest route can’t we when trying to figure out the enthalpy of combustion

@Chemistorian

5 ай бұрын

There is no “biggest route”. Hess’s law states that as long as you start at the same place and end at the same place, any route you take will have the exact same enthalpy change. So, you can take any route you want!

TYSM MAN, This literally saved my LIFE IN AS level, tysm😁😁😁😁

@Chemistorian

9 ай бұрын

Glad I could help!

In example 1, why were we able to use the delta hf of H2O even if the given is for gas and the reaction indicates that H2O is in liquid state

@Chemistorian

11 ай бұрын

That's because there's a mistake in the video that I hadn't noticed before. The Hf for water in the table is actually given for the liquid state, not the gas state. Thanks for pointing that out!

I still can't wrap my brain around the difference btwn q and H. Help! Is it that heat is transfer of energy btwn moleculesand H iis overall gain or loss of heat energy?

@Chemistorian

8 ай бұрын

When in doubt, check the units! Q is measured in J or kJ, so it’s just the amount of heat energy taken in/given out during a reaction. H is measured in kJ/mol, so it’s the amount of heat energy taken in/given out during a reaction, PER MOLE of reactant.

@elizabeth-ty3he

8 ай бұрын

@@Chemistorian thnx!

4:57 If they are asking for 1 mole shouldn't we half the the moles of H20. Can anyone please explain

@Chemistorian

6 ай бұрын

The combustion of 1 mole of CH4 results in the formation of 2 moles of H2O.

can u pls do a detailed video on Esters

@Chemistorian

2 жыл бұрын

I'll add it to the list, but I actually have a section on esterification in my first video - kzread.info/dash/bejne/lmSOyaZxncTFe9I.html.

@chanisperera103

2 жыл бұрын

@@Chemistorian ok thank you

wow

Why is water in the table for enthalpies of formation in a gaseous state if it’s meant to be in its standard state?

@Chemistorian

6 ай бұрын

Well spotted! There's a mistake in the video. Another commented pointed this out too. The Hf for water in the table is actually given for the liquid state, not the gas state.

@user-vn1fg2zj2g

6 ай бұрын

@@Chemistorian Thanks for the reply, much appreciated.

omg i dont know who you are omg i love u so much you made my day thank you so much

I still don't understand how you determine the direction the hess cycles arrows go

@Chemistorian

11 ай бұрын

It all depends on the type of Hess cycle. If it uses formation enthalpies, arrows go up from the box because the formation enthalpy is always going from the elements to the compounds. If it uses combustion enthalpies, arrows go down to the box because the combustion enthalpy is always going from the compounds to the combustion products. When you learn the definitions of the enthalpy changes, the directions of the arrows make sense logically.

@zaino9818

11 ай бұрын

@@Chemistorian ah okay. thanks for your help

Poor combustion explanation.

ummm, no!.. Next