Thank you! I came for a level mechanics and this is the best one yet explaining motion of displacement time graph😍

@MathematicsTutor

4 жыл бұрын

Thanks for appreciation. Here is related playlist: kzread.info/dash/bejne/X42mlcqEYpmpqqw.html

@am-cb8vn

4 жыл бұрын

@@MathematicsTutor thank you

Good sir

You have made my studying SAT physics easier!!! Thank you!

Excellent demonstration. I always come back whenever I'm going kinematics graphs.

@MathematicsTutor

5 жыл бұрын

Thanks a lot. All the Best!

@joytighosh2314

3 жыл бұрын

@@MathematicsTutor thank you

i am in sri lanka and i had many smALL but too much necessary points to know but i never found solutions untill i watch this vedio so absolutly thanks sir anil kumar for delivering succh sort of useful clip

Outstanding... Sir

anil kumar the GOAT

voice and video super sir

Amazing Video!

Nice explanation

Thank you so so so so soooooo much!

Awesome 😇

Super informative. Thanks!

Grt Work Sir

🔥🔥

Gd

Thank you, sir!

It was a beautiful lecture...Indeed

Can't express my feelings sir... ThaNK You so much i required this urgently!!!! 😭❤️🙏

perfect teaching

VERY HELPFUL!! THANK YOU SIR

Explained it better than my teacher thanks

makes sense sir, thank you!!

Very helpful!!

Awesome explaination sir

Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺

Just wowwwwwww wow amazing explanation sir....amazing!°!!!!!!

Thankyou

Absolutely amazing explanation, was struggling with this in both A-Level Maths & Physics, this video has helped me understand better than any of my teachers (:

Great teaching sir, thank you so much

Thank you very much

Superb class understood very well Thank you so much sir❤

thank you... it's very fun learning... it also makes me understand more

Really helpful sir Thank u May God bless u

Thank you so much sir!! Very helpful 🙏❤

Thank you, Sir.

Thank U sir...osm explanation.

Thank you a lot man!!!!

Thankyou sir for making it easier for us.

Thank u sir u really cleared our doubts, voice was really apperciable....& pls explain with any numericals...

thank you for your help w my physics homework!!! god bless u

@MathematicsTutor

5 ай бұрын

Best Wishes

Excellent

@MathematicsTutor

6 жыл бұрын

Thanks for appreciation. All the Best!

@samarbandodkar12

6 жыл бұрын

Anil Kumar thank you

v useful thanks

THANK YOU!

Thanks for the video Thank you

Thank you so much sir for helping me

Thanks sir u understand 👍

Thanks sir

thank you! this really helped

many thanks

thanks!

Thank you it helped me a lot

very nice!

@MathematicsTutor

6 жыл бұрын

Thanks for your time and appreciation.

Draw a displacement time graph and velocity time graph of a ball released at height of 8m and bounces on the group 3 times and each rising half the previous height

Thank you 🙂

Sir veryyyy thank you . I don't know how much I facing problem with that .

sir,so the zero in velocity-time graph is just a turning point and not mean the object stopped when at zero? unless no line is drawn behind the zero in velocity-time graph?

❤️❤️❤️❤️💯

Awesome could have been more amazing if added a t graph in all cases , BTW Awesome.

best explaination by far! Can u do a vid on bouncing ball accelation time graph

Excellent class sir...😊👌.Hope more from you...😊

well explained. thank you.

@MathematicsTutor

6 жыл бұрын

Thanks for appreciation and your time. Appreciate your name -- Eager to Learn, a true student!

It will better ,if example for each graph were given

@MathematicsTutor

3 жыл бұрын

Check this playlist: kzread.info/dash/bejne/ZXlos6t_d6vPmqg.html Thanks

May I ask the name of the black pen your using?? Thanks!!

What pen was used

Sir in 2nd graph how the slope is positive?? The slope is going towards the origin.. So how the slope is positive??

It is better to explain how slope is positive

Sir please clear my doubt. To get distance traveled we calculate the area under Velocity Time curve, which we usually do considering curve above X axis. But we could have compute the area under that curve with respect to Y axis. But why don't we do so? Please reply.

@MathematicsTutor

5 жыл бұрын

We could do either way. Why we don't normally do - x is treated as an independent variable. Time is independent variable by default. Velocity is defined as rate of change of distance with respect to time -- so that explains. Hope it helps.

@kausarmalik9258

5 жыл бұрын

@@MathematicsTutor sir you ate amazing

hi,i have a question, for the fourth d-t graph,the object returned back to the original position twice(displacement=0m),but in the v-t graph,the velocity of the object is at zero when the d-t graph is in its minimum point(displacement is negative,but not zero),why is that so? And why the v-t graph was not drawn in a way that the the line touches the x-axis twice?(which means that velocity=0m/s)

@kakaliray4721

5 жыл бұрын

You have not at all understood the video..

make calculator over it for more easy calculation and direction 😎😎😎😎

Sir why the displacement and velocity time graph scatch are different from each other plz sir i have big confusion

@MathematicsTutor

5 жыл бұрын

Velocity is rate of change of displacement. So they should be different. Hope that helps

@thethuglife10

3 жыл бұрын

@@MathematicsTutor amount of change in position is called displacement Velocity is rate of change in position

I Like it, but isn't it "accelerating" , which is non-uniform/ not constant, if the line graph is Parabola?

@MathematicsTutor

6 жыл бұрын

at 6:12, The slope of a curve is constant; Curve is Velocity; Slope of this line is the acceleration. y = mx + b, m is a constant. Hope now you can see that the acceleration is constant for the parabola representing displacement. Thanks

@nkitydv

3 жыл бұрын

What is the difference between uniform and constant velocity please help me

@pritam1210

3 жыл бұрын

@@nkitydv both are same 🙄

HOW TO FIND SLOPE POSITIVE & NEGATIVE IN NATURE IN CASE OF LINE? pl explain

A special case where a body moving with constant velocity has constant acceleration. Is this true? My teacher said: It is true bcz acceleration=0 is also a constant quantity for acceleration and where a=0 velocity is constant But I don't get it....so plz explain...

@teresamariconda964

3 жыл бұрын

Maria hi because acceleration is change in velocity so if the body maintains a constant velocity of 0 then acceleration is 0 as there's no change in velocity so that is still constantly 0

Thanku sir

no curve is formed in any v-t graph?

@hirunisiriwardhane4361

3 жыл бұрын

why not when the velocity increasement(accelaration) increases with time we could get curves in v-t graphs too

What would be the vt graph if acceleration is non uniform??

@MathematicsTutor

6 жыл бұрын

Thanks. Will post a video for that. Here is some concept which can help: kzread.info/dash/bejne/eZloxJqIfZjfnbw.html

@MathematicsTutor

6 жыл бұрын

Here is an example for non-uniform acceleration: kzread.info/dash/bejne/p5yElJtshtLcerg.html Let me know if that helps. Thanks

Plz give example for each cases

@MathematicsTutor

5 жыл бұрын

Sure, will post a video on that soon. Thanks

How many pens u have?😄😄best video 👍👍👍

Great explanation!

@MathematicsTutor

6 жыл бұрын

Thanks a lot for appreciation! All the Best!

@roddamapm8401

5 жыл бұрын

Very good explanation

Sir of this answer2. Draw a plot between displacement v/s time for the retardation motion

is a position and time graph the same as a distance and time graph?

@Madeeha_

3 жыл бұрын

I might be late but yess

What is meaning of -disp, and - velocity

@MathematicsTutor

5 жыл бұрын

Thanks, will make a video on this soon. displacement is change in position velocity is rate of change of position.

@carultch

Жыл бұрын

Negative displacement means that the object is located in a direction from the starting point, that is opposite what we arbitrarily define as positive. Negative velocity means that the object is moving in a direction, that is opposite what we arbitrarily define as positive.

11:53

@MathematicsTutor

3 жыл бұрын

Let me know if all was clear. Thanks

Online class hota hai sir

@MathematicsTutor

4 жыл бұрын

Yes, send e-mail for details

Sir the last vt graph is not correct I think sooo

@MathematicsTutor

3 жыл бұрын

It is correct. Please check again. Thanks

some graphs are WRONG

Good sir

Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺

Nice explanation

@MathematicsTutor

5 жыл бұрын

Thanks

THANK YOU!!!!!!!

thank you sir