1.9 free fall - graphs

High school physics

Пікірлер: 26

  • @kumarinickysinha3594
    @kumarinickysinha35944 жыл бұрын

    Thank you! You have defined everything very well.

  • @ylabarbera

    @ylabarbera

    3 жыл бұрын

    Thank you

  • @lattewikeke7165
    @lattewikeke71653 жыл бұрын

    It contains all the contents I wanted!! God bless u😘😘😘😘

  • @agal2662
    @agal26624 жыл бұрын

    NIcely explained !! Thank you

  • @nurtriki14
    @nurtriki143 жыл бұрын

    Love your accent!

  • @adityapatil836
    @adityapatil8364 ай бұрын

    WhT would ve velocity vs position graph for ground to ground motion

  • @faizanali9932
    @faizanali99323 жыл бұрын

    superp explaination

  • @nirmalkukreja9816
    @nirmalkukreja98162 жыл бұрын

    Thanku

  • @seemapandey4826
    @seemapandey48263 жыл бұрын

    Basically in graph system we are comparing velocity with acceleration and distance by velocity??

  • @Anjanikumar-vf7ps

    @Anjanikumar-vf7ps

    3 жыл бұрын

    Bhai just assume that in straight line average speed =Average velocity.

  • @randumdude8548
    @randumdude8548 Жыл бұрын

    how would a graph of time and position look like for a falling body if up was negative and down was positif

  • @dianalabarbera201

    @dianalabarbera201

    Жыл бұрын

    Slope is velocity. As the object moves up, it moves in the negative direction and the slope decreases, so it’s a downward curve. As it comes down, it should move upward with increasing slope, so it’s a upward curve. The graph of up & down motion is shaped like a bowl. I hope that helps.

  • @abdurrehman5574
    @abdurrehman55744 жыл бұрын

    difficult explaination how can we represent when a body is thrown from the ground

  • @dianalabarbera201

    @dianalabarbera201

    4 жыл бұрын

    Abdur Rehman that’s in another video, projectile motion

  • @vnssn
    @vnssn4 жыл бұрын

    You didn't tell the acceleration time graph of a free falling body

  • @ylabarbera

    @ylabarbera

    3 жыл бұрын

    acceleration is constant. so it is a horizontal line because it doesn't change with time.

  • @mohdzubair8607

    @mohdzubair8607

    3 жыл бұрын

    @@ylabarbera will that horizontal line break at the time when that freely falling body touches the ground ,i.e. will the graph be discontinuous at the time when the body touches ground please tell e.g. for a ball which is falling freely from a height and touches the ground and then rebounds to the same height please tellll

  • @physics9540
    @physics95404 жыл бұрын

    Very nice

  • @ylabarbera

    @ylabarbera

    3 жыл бұрын

    thank you

  • @ianloidbagtas2844
    @ianloidbagtas28443 жыл бұрын

    Do free falling objects possess constant velocity?

  • @dianalabarbera201

    @dianalabarbera201

    3 жыл бұрын

    No. All free falling objects accelerate downward, due to gravity which pulls everything down. The acceleration is has a constant magnitude (value) in downward direction but the speed is increasing in the downward direction.

  • @alluringorchid5725
    @alluringorchid57255 жыл бұрын

    Are a using NCERT or HC Verma

  • @geet6797

    @geet6797

    2 жыл бұрын

    Uhm don't you think they aren't Indian? So neither ig

  • @ria_05
    @ria_05 Жыл бұрын

    Explicit explanation

  • @alizasayyed8528
    @alizasayyed85283 жыл бұрын

    Why are you considering acceleration as -'ve 9.8m/s^2 for a free fall Acceleration is always +'ve and velocity always increases when an object freely falls downwards!!!!

  • @ylabarbera

    @ylabarbera

    3 жыл бұрын

    acceleration is downward. If upward is defined as positive, as we usually do, then acceleration is negative. the direction of acceleration is defined as the following: if an object speeds up, then acceleration and velocity are in the same direction. for example, if the object is moving in the positive direction, then acceleration is positive; if the object is moving in the negative direction, then the acceleration is negative. So, if I define downward as negative, then acceleration is negative. However, if I define downward as positive, then acceleration is positive.