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Not all hero’s wear capes. Some just have a black screen with a microphone and color tools 😃. I speak for all of your viewers when I said this, WE are very grateful for the content you post.

@kanishkagunjiyal3237

3 жыл бұрын

yass

@bagumadouglas1648

Жыл бұрын

True bro

@moongaming9684

Жыл бұрын

Bruh you glazing chill

@bcziAmKira

8 ай бұрын

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Para-director? More like (you are a) perfect-director (of our learning)! But seriously, I've seen a lot of positive comments on KZread videos before, but never to this degree. I am thankful as are all the other commenters that I can see, and keep up your amazing work!

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I just accepted what was an ortho/para director but this actually explains why! Thanks!

at 8:00 , why did you move the double bond 2 carbons? shouldn't the double bonds be parallel?

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This also explains why certain substituents on the benzene make it more or less acidic. Thank you!!

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thanks mate! great explanation on nucleophilic and electrophilic nature of ortho and para carbon

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Thank you for this great video!! For the CH3 group, since it makes the ring more electrophilic, why it is an activator?

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Can I ask if I have a NH2 group in the para position to an ester group (for example benzocaine) would the NH2 group increase the rate of hydrolysis for the ester?

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@wandererrrrrr

3 жыл бұрын

ارميييي

@asmasabri1124

3 жыл бұрын

@@wandererrrrrr نعم😂

Thank you!

Is this the same for nucleophilic and electrophilic or does it change?

Thanks! ❤️

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But isnt ester a deactivating group

How does the withdrawing effect of e from benzene occurs by Br.

if already two groups are present in the ring? Sir! please discus about the third group entry in bi-substituted ring! Nobody interested to talk about that.

Not the hero we deserve, but the hero we need

thank you.

8:37 shouldn't the double bond on the third molecule be on the right, symmetrical to the other one???

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The para intermediate tertiary carbocation the electrophile attached carbon already had 5 bonds if we draw double bond at this position it becomes six how is it possible or by mistake

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@azyle2104

3 жыл бұрын

Google it , there's 1 picture of him up

@azyle2104

3 жыл бұрын

His face doesn't look as I imagined though 😂

wait... at 08:10 why did you put the double bond connecting to the electrophile at C-3 to C-4 instead of adding it to the single bond at C-2 to C-3?

@user-nz6rz9bb9o

3 ай бұрын

That was the next resonating structure

hey OH has a formal charge of 0 right ? 6-(1+5) why does it even attack the benzene ring ?

Thank you sir , may Allah bless you :)

8:20 is wrong no the double bond doesn’t go there ?

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Show all the reaction mechanism while stating the type of the mechanism involved

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hey man, at roughly 3:15 you say these groups are moderately activated and then you say they are ortho para. Then at roughly 13:00 you say moderately deactivated prefer meta. However the molecules look veryyyy similar. Can you explain?

@nicoletteschiavone5980

5 жыл бұрын

It's all depends on which atom is bonded to the benzene. The ester at 3:15 has the oxygen directly bonded to the benzene ring, thus it is a moderately activating group because oxygen has a lone pair and can donate electrons to the ring by resonance. The ester at 13:00 has the carbonyl carbon bonded to the benzene ring, NOT the oxygen, thus it is a moderately deactivating group because the carbonyl carbon has a partial positive charge and withdraws electrons by resonance.

@aenseidhe-93

4 жыл бұрын

Just remember this. Lone pairs - activators and o/p directors. Double bonds mean deactivators and meta directors. Halogens are also deactivators that o/p direct but they are an exception.

@diyashamoitra125

4 жыл бұрын

@@aenseidhe-93 thanks for this Sir! This is extremely helpful

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That's one fucked up benzene bro.