Nucleophilic Aromatic Substitution - Benzyne Intermediate and Meisenheimer Complex

This organic chemistry video tutorial provides a basic introduction into nucleophilic aromatic substitution reactions. It discusses the conversion of para-chloronitrobenzene into para-nitrophenol using an addition elimination reaction mechanism that passes through a resonance stabilized carbanion intermediate known as the Meisenheimer complex. This video also discusses the conversion of para-bromotoluene into meta and para-methylaniline using an elimination addition reaction mechanism that passes through the benzyne intermediate.
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  • @Doc_McStuffins
    @Doc_McStuffins5 жыл бұрын

    You're my favorite chem guy. Thanks for all you do!!! You're consistently amazing.

  • @scoobydoo02
    @scoobydoo026 жыл бұрын

    Never quit. I love this!!!!

  • @PunmasterSTP
    @PunmasterSTP2 жыл бұрын

    Meisenheimer? More like my, so much higher...in educational value than almost every other video on KZread. Thanks again so much for making and sharing these!

  • @husseinfedilla6814
    @husseinfedilla68142 жыл бұрын

    Beautiful

  • @1BigMan.Tshepo
    @1BigMan.Tshepo Жыл бұрын

    W video man, big up.

  • @raiyanrahman79
    @raiyanrahman793 жыл бұрын

    In Chlorobenzene there should slight negative charges in Ortho and para position due to resonance. Then why does a Neucleophile attack the H in the ortho position? Wouldn't it make more sense if it attacked the H in meta position where the electron density is relatively lesser?

  • @tom_winguill
    @tom_winguill3 жыл бұрын

    9:40 3️⃣50 C

  • @dathuyadav8822
    @dathuyadav88226 жыл бұрын

    Nice

  • @musicmeister1313
    @musicmeister13132 жыл бұрын

    ok, but what are the other reagents that can go through the benzyne intermediate 😠😠?

  • @Spogeboii
    @Spogeboii5 жыл бұрын

    Will NAS occur if there is an activating group and a good leaving group? Or is this process restricted to a deactivated ring and a nucleophilic reagent?

  • @ansingh1338

    @ansingh1338

    4 жыл бұрын

    Same doubt...

  • @PunmasterSTP

    @PunmasterSTP

    2 жыл бұрын

    Doesn't the reaction starting at 14:56 have an activating group (methyl) and a good leaving group (bromo)?

  • @alexfrostbound4401
    @alexfrostbound44012 жыл бұрын

    You are a breathing miracle

  • @gerstensaft2936
    @gerstensaft29366 жыл бұрын

    In the last reaction. How's the ratio of meta to ortho and para? 1:2:1 (orto:meta:para) Or is para more likely to happen than ortho because of steric hindrance of the CH3 group?

  • @janrenehaak

    @janrenehaak

    6 жыл бұрын

    I think that the methyl-group isn´t so bulky, so their is no hindrance. Because of that I suggest, that the ratio ist 1:2:1 as you said. I hope this didn´t come too late :D

  • @deepamishal4683
    @deepamishal46833 жыл бұрын

    17:30 which one is major and minor

  • @tom_winguill

    @tom_winguill

    3 жыл бұрын

    fuck you

  • @tom_winguill

    @tom_winguill

    3 жыл бұрын

    F;U;C;K||||||Y;O;U

  • @VikasVerma-pn4rq
    @VikasVerma-pn4rq3 жыл бұрын

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  • @ramillucas2117
    @ramillucas21174 жыл бұрын

    will you marry me? organic chemistry tutor? HAHAHAHA

  • @PunmasterSTP

    @PunmasterSTP

    2 жыл бұрын

    From your asking that question, I take it you two have chemistry together?

  • @crenapun57
    @crenapun573 жыл бұрын

    tw

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