Chemistry 13.6a Balancing Redox by Half-reactions (Acidic)
Step by step instructions on how to balance a redox reaction in an acidic solution using the method of half-reactions.
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Пікірлер: 30
@RoTeReign8 жыл бұрын
i have been through tons videos that made me hate my life but when i came across this video and watched it ... i was like God blesss you man!!! thanks alot!!!!
@frankied.28283 жыл бұрын
Finally, a person who could explain something. I felt like I was receiving a scientific hug. Thank you.
@IsaacsTEACH11 жыл бұрын
I didn't "get rid" of the 6Cl-, it just happens to be part of the 16 HCl on that side. The reason that all 16 Cl- don't show up in the half-reactions is because many of them are spectator ions. Basically you don't need to use the coefficient for 6Cl- when going back to the original reaction. @10:06 is the relevant section
@TaekwonDana11 жыл бұрын
This is so helpful! You make studying for my Chemistry exam so much easier; I can't express how much I appreciate this video! :)
@bman94696 жыл бұрын
Thanks a lot, I was totally lost when it came to the spectator ions. This video helped
@ItsJustKasey149 жыл бұрын
this video has helped me so much! way simpler to understand than my college professor and his worksheets. Thank You!
@jacquil180710 жыл бұрын
Thank you so much!!!!!!! I always look at your videos for Chemistry! Best Chemistry videos ever!!!
@AaronFu11 жыл бұрын
This is truly amazing. Thank you so much for doing this.
@alexdeleeck76745 жыл бұрын
Thank you, really clear and straight forward!
@fongangraissa10 жыл бұрын
the best video on youtube thank you so much
@Stickmanzed10 жыл бұрын
This was an excellent and very informational guide on this rather confusing topic, you have helped me a lot! I liked and favourited this, hopefully it helps you out a bit. Thank you for helping me!
@redleopard19999 жыл бұрын
You have saved me! Thank you so much!
@SniperJAG099 жыл бұрын
Thanks!!!!!! cleared up a lot of things
@lauramazzocchitti850911 жыл бұрын
You are an incredible teacher - thank you so so so much :D
@brandonphan14376 жыл бұрын
thanks for doing more advanced style problems.
@nicoleluvdogs11 жыл бұрын
This video saved my life :) amazing teacher
@xokizza11 жыл бұрын
your way better than my teacher at teaching this!!!
@dhiEz0512 жыл бұрын
Thanks a lot! Been finding an example like this
@vajix8411 жыл бұрын
Great lesson, really helpful
@ybiangpaj396111 жыл бұрын
thank you so much...it's much clearer to me now. I just need to practice.
@tejiricoker84458 жыл бұрын
This was really helpful thank you
@lyndalandzeh976611 жыл бұрын
Could you pleae explain how you got reed of the 6cl- when balancing the orignal reaction with the half equations?because i noticed the equation is balance but you didnt use the coefficient of th 6cl-...thks
@Nacho70828 жыл бұрын
ahhh, because they are spectator ions, thank you!
@nathaliadiego65184 жыл бұрын
Thank you!!!!!!!!!!!!!!!!!!
@egaga-3 жыл бұрын
Thank you so much for the explanation, especially the latter one. The book Chemical Principles has problems that seemed incomprehensible to me with the procedure it gives to solve them. Complex redux reactions were not given as example, and it is frustrating as a self-learner without being able to ask help.
Пікірлер: 30
i have been through tons videos that made me hate my life but when i came across this video and watched it ... i was like God blesss you man!!! thanks alot!!!!
Finally, a person who could explain something. I felt like I was receiving a scientific hug. Thank you.
I didn't "get rid" of the 6Cl-, it just happens to be part of the 16 HCl on that side. The reason that all 16 Cl- don't show up in the half-reactions is because many of them are spectator ions. Basically you don't need to use the coefficient for 6Cl- when going back to the original reaction. @10:06 is the relevant section
This is so helpful! You make studying for my Chemistry exam so much easier; I can't express how much I appreciate this video! :)
Thanks a lot, I was totally lost when it came to the spectator ions. This video helped
this video has helped me so much! way simpler to understand than my college professor and his worksheets. Thank You!
Thank you so much!!!!!!! I always look at your videos for Chemistry! Best Chemistry videos ever!!!
This is truly amazing. Thank you so much for doing this.
Thank you, really clear and straight forward!
the best video on youtube thank you so much
This was an excellent and very informational guide on this rather confusing topic, you have helped me a lot! I liked and favourited this, hopefully it helps you out a bit. Thank you for helping me!
You have saved me! Thank you so much!
Thanks!!!!!! cleared up a lot of things
You are an incredible teacher - thank you so so so much :D
thanks for doing more advanced style problems.
This video saved my life :) amazing teacher
your way better than my teacher at teaching this!!!
Thanks a lot! Been finding an example like this
Great lesson, really helpful
thank you so much...it's much clearer to me now. I just need to practice.
This was really helpful thank you
Could you pleae explain how you got reed of the 6cl- when balancing the orignal reaction with the half equations?because i noticed the equation is balance but you didnt use the coefficient of th 6cl-...thks
ahhh, because they are spectator ions, thank you!
Thank you!!!!!!!!!!!!!!!!!!
Thank you so much for the explanation, especially the latter one. The book Chemical Principles has problems that seemed incomprehensible to me with the procedure it gives to solve them. Complex redux reactions were not given as example, and it is frustrating as a self-learner without being able to ask help.
excellent marvles
Omg!!
Summer School Students Approved!
Wish you were my teacher ._.