lovely, always find these trig ones difficult but theyre so worth the marks

Hi Mr.Astbury, just wanted to thank you for all the hard work you've put in to make incredibly useful maths content for us all! You will have without a doubt helped a number of students across the country secure top grades. I hope your channel can reach even more people in the years to come. Keep it up! Also, is there any way I could watch your Integration livestream, I couldn't find it on youtube this morning.

@txb_6713

Ай бұрын

The Integration event was a ticketed zoom call you had to sign up for in advance, the recording of it would've been sent to anyone attended. A similar thing will be happening on the 9th for Pure Maths Paper 2, see the first link in the description for details. :)

Very helpful! Thank you sir

thanks so much for the questions - very helpful

im so happy i found this i hate using cast diagrams so that sin cos tan thing helped so much 😭😭

H sir, where can I find your integration live from today?

8:12, im confused as to why we are subtracting 2 pi when you wrote down that for tan we do pi - first value

@M7RAA

25 күн бұрын

the rules at 6:34 are for finding other values for which you get the same solution. then when he adds 2pi, thats because the graphs go on forever, so sin30,390,750,1110 all give the same result and they are 2pi(360 degrees) out. Similarly, sin150, 510,870,1230 all give the same solution as the previous values. i found 150 by doing pi(180) minus 30

sir, does your method for finding values in the range with sin: pi - theta, cos: 2pi - theta and tan: pi + theta also work for both obtuse angles and negative values?

Hi I only knew of your paper 1 live session today and it was too late , is it possible if I can get the recording and if so how much would that be? Thank you so much for all your help!

1st term = 2cos2x/sin2x = 2cos2x/2sinxcosx = cos^2(x )- sin^2(x)/sinxcosx = cosx/sinx - sinx/cosx = cotx - tanx..QED

@rayzino3338

Ай бұрын

Where is ur 2sin2x?

@nandanpillai4675

Ай бұрын

​@@rayzino3338he made it 2sinxcosx

@sentheaS

Ай бұрын

The coefficient of sin2x is 1. 2cos(2x)/2sin(2x) = cos(2x)/sinx(2x); if your denominator is 2sin(2x) then you would have 2/2, which is just 1.

@sentheaS

Ай бұрын

And sin2x is 2sinxcosx, in case that’s why you are confused @rayzino3338. Sin(2x) = sinxcosx + sinxcosx = 2(sinxcosx).

@thepartycrusher1951

28 күн бұрын

genius

Cheers Sir!!!!!

Not too bad, I've gotten fairly decent at these. Still would have lost the final mark because I blanked the extra solutions for cotx but yea!

Very useful :))))

legend

Which player has played for: (no particular order) -Leeds United -Saint Etienne -AFC Bournemouth

@zeebeaats

Ай бұрын

Gradel

@alaziziomar_

Ай бұрын

lewis cook?

@CounterThePress

Ай бұрын

@@zeebeaats correcto

There are two more solutions to this which you didn't consider. Subtracting pi from 0.294 is in the range still, and so would -2.848+pi

@MrAstburyMaths

24 күн бұрын

They give the answers we already have

for a) how do you know what route to go down, because you could've written it as cos^x/ sin^x as well

@lilpurro6430

Ай бұрын

u get the same answer with using cos2x over sin2x

@ravjayakodi2746

Ай бұрын

@@lilpurro6430 ah right i didnt do it i was jw

@ZeroWinz

Ай бұрын

should work any way thats the way I did it and it worked for me, its just one way is more efficient than another often

@rayzino3338

Ай бұрын

@@ZeroWinzcould u explain what u did

sir I've seen this asked a lot. For the proof questions, can you do stuff to both sides of the equation and then meet in the middle? does that give marks, or do you have to go completely from one side to the other?

@da.jokarrr

Ай бұрын

ive been wondering the same thing aswell cuz ive seen it done like that once but never see it in markschemes

@stardreamix786

Ай бұрын

you can choose what side to start with, and no you cant move stuff from LHS to RHS - this is a proof question so you just have to pick a side and get it to the other using known facts. so yes get from one side to the other completely

@Hippogan

Ай бұрын

@@stardreamix786 no no no, you're misunderstanding me. you think I want to move stuff in-between sides. no, I'm asking if you can rearrange each side independently, to get the same thing on both sides, to prove that they're equal

@nandanpillai4675

Ай бұрын

​@Hippogan, yeah, you are allowed to do that, or if you're worried, just do that in ur working and lay it out pretending like you've done it using one side

@stardreamix786

Ай бұрын

@@Hippogan ahh ok - if im really stuck then i would do this, but remember when you end up getting to the middle on both sides of the proof, dont just leave it there - in a new space, since you know where they meet up, you can undo one of the sides and start from the beginning and fully show formally how to get fully to the other side. -t he exam board want you to show one side getting fully to the other side if you get me - but its a good rough working out to get them to the middle to know your going in the right direction

Goat 🐐

Why does it say solutions based on graphical technology are not acceptable

@styllonestiff7087

29 күн бұрын

u can just mash it into one of them graphics calculators and get the answer, no skill involved