Second shifting theorem: Laplace transforms

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The second shifting theorem of Laplace transforms. I show how to apply the ideas via examples and also provide a proof.

Пікірлер: 26

  • @zuhairalsaffar7001
    @zuhairalsaffar70012 жыл бұрын

    Sir I like your way of teaching you did your best to make it easy l understud it clearly thanks 😊 👍 😀 😄

  • @solomonobotidem9450
    @solomonobotidem945011 жыл бұрын

    thanks for the lecture

  • @maxamedcabdicige7568
    @maxamedcabdicige75683 жыл бұрын

    Thank we hope you good luck

  • @haimish26
    @haimish264 жыл бұрын

    Thank you !!!

  • @kasimbazihillaryclinton8774
    @kasimbazihillaryclinton8774 Жыл бұрын

    It's a good work madam

  • @jaxon.roller
    @jaxon.roller9 жыл бұрын

    THANK YOU

  • @DrChrisTisdell
    @DrChrisTisdell10 жыл бұрын

    Hi - which part of the video are you referring to? Please state the time.

  • @franciskwetey3894
    @franciskwetey3894 Жыл бұрын

    You are the best cos I understood it I really appreciate 🙏🙏

  • @DrChrisTisdell

    @DrChrisTisdell

    Жыл бұрын

    So glad you could understand it, Francis!

  • @svassell554
    @svassell5547 жыл бұрын

    At 35:20 I worked it and saw that -tu(t-4) + 4u(t-4) = -(t-4)u(t-4) but what is the proof?

  • @urshian1760
    @urshian176010 жыл бұрын

    uhmm at around 21:49, when you're drawing the graph, i'm just having a little trouble understanding the last part. if we have 1*g(t-a) when t>a , and in this case a=2 and g(t-a) = t-2 , wouldn't the graph be a constant -2 not +2 on the right side of the point of interest? because our equation would become t-t-2 = -2 no ? did I misunderstand something? any help is appreciated, thanks.

  • @gum1763
    @gum176310 жыл бұрын

    i hope you have all the six chapters in mathematics for engineering....

  • @u18sc11
    @u18sc119 жыл бұрын

    for the second shift theorem question why does g(t)=t^2 ?

  • @nataliegao1835
    @nataliegao18359 жыл бұрын

    i tried using both methods for your last question but i get 2 different answers. could you post the answer for it if you used tf(t) = -F'(s) method?

  • @solomonobotidem9450
    @solomonobotidem945011 жыл бұрын

    please how can i solve R L C using laplace transforms

  • @afifahali1520
    @afifahali152010 жыл бұрын

    at 34.53.. or could u explain why u did that?

  • @gerardguerra5003
    @gerardguerra500310 жыл бұрын

    At 35:20 you state "rebracket" (t-4)u(t-4), explain what happens to t and 4?

  • @DrChrisTisdell

    @DrChrisTisdell

    10 жыл бұрын

    Hi. -tu(t-4) + 4u(t-4) = -(t-4)u(t-4)

  • @irehman7

    @irehman7

    6 жыл бұрын

    i still don't get it like how does this rebracket happen

  • @irehman7

    @irehman7

    6 жыл бұрын

    i tried openig the brakets and solving it still doesn't work , like did this happen?

  • @nicksebasco3445
    @nicksebasco344510 жыл бұрын

    La place transform of (t-4)u(t-4) is e^(-4s) ((4s+1)/s^2-1/s) according to wolfram alpha

  • @dipbheenumandavimandavi1987
    @dipbheenumandavimandavi19873 жыл бұрын

    🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳very good 🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳

  • @zaeniakhmadmustofa4767
    @zaeniakhmadmustofa476710 жыл бұрын

    what your email andress? i have many question about applications of the second shifting thorema,inverse transform... help me please...

  • @pinakindeshmukh4006
    @pinakindeshmukh40069 жыл бұрын

    Sir,I think we should consider that 2 value also.for that f(t)=t[u(t)-u(t-4)]+2*delta(t-4).then apply algebra,table to get final transform!

  • @afifahali1520
    @afifahali152010 жыл бұрын

    i think u do a mistake. isn't the (t equal to 4) is 2. therefore 2 bracket u ( t - 4 )