Second shifting theorem: Laplace transforms
Free ebook bookboon.com/en/partial-diffe...
The second shifting theorem of Laplace transforms. I show how to apply the ideas via examples and also provide a proof.
Free ebook bookboon.com/en/partial-diffe...
The second shifting theorem of Laplace transforms. I show how to apply the ideas via examples and also provide a proof.
Пікірлер: 26
Sir I like your way of teaching you did your best to make it easy l understud it clearly thanks 😊 👍 😀 😄
thanks for the lecture
Thank we hope you good luck
Thank you !!!
It's a good work madam
THANK YOU
Hi - which part of the video are you referring to? Please state the time.
You are the best cos I understood it I really appreciate 🙏🙏
@DrChrisTisdell
Жыл бұрын
So glad you could understand it, Francis!
At 35:20 I worked it and saw that -tu(t-4) + 4u(t-4) = -(t-4)u(t-4) but what is the proof?
uhmm at around 21:49, when you're drawing the graph, i'm just having a little trouble understanding the last part. if we have 1*g(t-a) when t>a , and in this case a=2 and g(t-a) = t-2 , wouldn't the graph be a constant -2 not +2 on the right side of the point of interest? because our equation would become t-t-2 = -2 no ? did I misunderstand something? any help is appreciated, thanks.
i hope you have all the six chapters in mathematics for engineering....
for the second shift theorem question why does g(t)=t^2 ?
i tried using both methods for your last question but i get 2 different answers. could you post the answer for it if you used tf(t) = -F'(s) method?
please how can i solve R L C using laplace transforms
at 34.53.. or could u explain why u did that?
At 35:20 you state "rebracket" (t-4)u(t-4), explain what happens to t and 4?
@DrChrisTisdell
10 жыл бұрын
Hi. -tu(t-4) + 4u(t-4) = -(t-4)u(t-4)
@irehman7
6 жыл бұрын
i still don't get it like how does this rebracket happen
@irehman7
6 жыл бұрын
i tried openig the brakets and solving it still doesn't work , like did this happen?
La place transform of (t-4)u(t-4) is e^(-4s) ((4s+1)/s^2-1/s) according to wolfram alpha
🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳very good 🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳
what your email andress? i have many question about applications of the second shifting thorema,inverse transform... help me please...
Sir,I think we should consider that 2 value also.for that f(t)=t[u(t)-u(t-4)]+2*delta(t-4).then apply algebra,table to get final transform!
i think u do a mistake. isn't the (t equal to 4) is 2. therefore 2 bracket u ( t - 4 )