Just lovely. I can't stop being so amazed about how easy it is to spread information now a days. I can sit here in Denmark, with a hot cup of coffee, crying my eyes out over Laplace- and fourier-transforms due to an upcomming exam, and then some BRILLIANT australian saves the day. God bless the internet and Dr. Chris - thank you so very much.

Saved me hours of frustration trying to dissect the textbook. Thank you Dr.

wooow, this is just amazing, been struggling for a while now , but finally i got it. a big thank from Norway Dr.

Thank you for the great feedback!

Isn't this professor totally awesome?

@stianl575

9 жыл бұрын

For having bad notation, being stressed out? Not really ,no.

@DrChrisTisdell

9 жыл бұрын

***** Bad notation? Stressed out? Please explain.

@sjabaranks

9 жыл бұрын

Dr Chris Tisdell some people are born negative keep up the good work man.

Wow, these videos might just be some of the best teaching material I've been lucky enough to witness. Keep it up!

Your a life saver ...That just saved me hours of trying to figure it out with my text book ..Thank you

Cheers Chris, really appreciate these videos don't know what I'd have done!

Excellent lectures.Dr.Chris made it very easy

you are so organised i felt like it is a mold and you are injecting the information into it, i have bee straggling for apx 6 Hrs and i could not understand , but with one hour with i got it .. thank you thank you thank you

Thank you Sir for this and other great series of yours in the field of mathematics! Greetings from Trondheim, Norway!

Thanks for the great feedback.

respect from Jamaica DR

thanks so much Dr. Chris

Thank you so much sir...this thing really really helped...!

A big thank you from Canada

thanks Buddy it helps me a lot

Thank you so much sir....ur lecture helped me so much fr my math.......

that is just "perfect" , thanks very much

Dr may God bless you .

THANK YOU!!!! TY! TY! TY! You are awesome!

thx you very big knowledge. thailand

You are welcome!

Respect from India

hi Dr : can we solve laplace equation by lablace transformation ? thanks

Thank u

thanks a lottttt sir :-)

Hi Chris, at 3:40 at the bottom of the page in the proof of L(e^-at g(t)) = G(s + a), I don't understand how you get from the 2nd last and last bits - the way I do it gives me G((s + a)^-1) Many thanks Euan

It's my pleasure!

thanks:)

big thank u from south africa,that was awesome

@sjabaranks

9 жыл бұрын

7

sir one more question (t+1) ka whole square e power t ka first shifting property

It is my pleasure!

Sir u hve not written 2! factorial in calc. Remainig procedure is awesome.

What it is within a function i.e sin(te^(-2t))

could you please solve L[t square sinat] would be really, helpful thanks.

@vipuljoshi2662

8 жыл бұрын

+Hamza Kirax L{sinat} = a/(s^2+a^2) and L{t^2}=2!/s^(2+1) hence by first shifting...... L{t^2.sinat}= 2a/(s^2+a^2)^3

@classtobeproud

8 жыл бұрын

Ohh thank you sirr :)

Technically speaking in your second example, a is equal to 1, not negative 1; the negative sign comes with the e^ -at. If a was actually equal to -1 then e^-at = e^ - (-1)t = e^t and the original f(t) would be (t+1)^2*e^-t. Seemingly trivial perhaps but actually important, especially when the second shifting theorem doesn't have that sign change

4:18 example

Allah bless you a million times over....so nice...the one dislike was possibly error. Statistically speaking a dislike is bound to happen. Hehe see what I did there.

sir one more question (t+1) ka whole square e power t ka first shifting property