This is the best video I have found that explains and uses the 2nd TT with a practical example. And its not too easy or insanely difficult, so you really get the idea of how to use it. Thank you so much man, u rock

honestly you have some of the best videos i wish i could have you as my actual proffesor. what ever they pay they need to pay you more

You explained it very clear. Now i understand better my book. Thank you!

Thank you!!! Finally understood how to solve this

thank you sir

love this!

hi, could you help in explaining to me how to solve for the laplace of: 3cos(t)U(t-pi)

@carultch

7 ай бұрын

Given: 3*cos(t)*u(t - pi) When multiplying a function g(t) by the unit step function shifted by a distance of c to the right, u(t - c), the corresponding Laplace transform is: G(s)*e^(-c*s) This means the given function's Laplace transform will be: L{3*cos(t)} * e^(-pi*s) Now we just need to find L{3*cos(t)}. Since the Laplace transform is a linear operator, we can pull the 3 out in front, and get: 3*L{cos(t)}. The Laplace of cos(t) we an look up directly, which is s/(s^2 + 1). Construct all of the above to get the solution: [3*s/(s^2 + 1)]* e^(-pi*s)