Removing Intermediates from Rate Laws

Пікірлер: 17

  • @user-vr3jm8le6t
    @user-vr3jm8le6t Жыл бұрын

    thank you so much I’ve struggled a lot to understand this! Because in our slides it’s so complicated 😢it’s 3 AM and my final exam is at 12 PM and literally you saved my life I have fully understood this thanks Amanda❤

  • @dsoWrath
    @dsoWrath5 жыл бұрын

    Awesome video I finally understand rate laws

  • @Mistrael
    @Mistrael3 жыл бұрын

    You explained this so clearly, thank you!

  • @amandajoyholton8070

    @amandajoyholton8070

    3 жыл бұрын

    Glad it was helpful!

  • @TheCryypi
    @TheCryypi Жыл бұрын

    Thank you !

  • @shanthala1345
    @shanthala13452 жыл бұрын

    Thank you ma'am ❤️

  • @autumnwetsel2922
    @autumnwetsel29222 жыл бұрын

    this was so helpful ahh thank you

  • @LizardWizardLiz
    @LizardWizardLiz2 күн бұрын

    I doubt you're still responding to comments on this video but its worth a shot. I have a problem on my homework that I simply don't understand related to this because we did not cover it in class and it seems to be way beyond the scope of the course curriculum. We are meant to cross out the intermediates of a multistep rxn and also show the overall equation. This is where I am lost The problem is generic. It is: U ---> V V ---- W + X W + Y ----> Z (RDS) I believe the rate law is r= k[W][Y] and that it is a second order rxn. However, W seems like it should be an intermediate. We did not learn anything related to what is presented in your video during class. I have watched my professor's pre-recorded lecture IDK how many times and compared what she was saying to what you are saying. Is there something I am missing? Thank you :)

  • @farziakarim3087
    @farziakarim30876 жыл бұрын

    But Miss, what if the reaction A+B-->C is not reversible, could we have used the same reaction? What if A and B just formed the intermediate and the C reacted with D?

  • @amandajoyholton8070

    @amandajoyholton8070

    5 жыл бұрын

    Thats a very different issue and one that we don't cover in my classes since you need to have more information. Some general chemistry textbooks talk about it but in most case you'll need to get ahold of a junior level kinetics book.

  • @shanthala1345
    @shanthala13452 жыл бұрын

    Why can't intermediate be in rate law

  • @Matetas-gv8lj

    @Matetas-gv8lj

    2 жыл бұрын

    because technically its made up,

  • @shanthala1345

    @shanthala1345

    2 жыл бұрын

    @@Matetas-gv8lj auh?

  • @Matetas-gv8lj

    @Matetas-gv8lj

    2 жыл бұрын

    @@shanthala1345 that’s how I made it stick. But yeah it does exist but it’s formed in on step and consumed in the next, it’s not present right at the beginning but is formed after the reaction starts. This is why we can’t include it in the rate equation because in the overall reaction the intermediate isn’t there

  • @shanthala1345

    @shanthala1345

    2 жыл бұрын

    @@Matetas-gv8ljohh, thank you,very kind!! Last semester we learnt kinetics, i was learning "steady state approximation", i still don't entirely understand . What are you studying?

  • @Matetas-gv8lj

    @Matetas-gv8lj

    2 жыл бұрын

    @@shanthala1345 if I told you I completely understood it I’d be lying jajajaja. I’m a biotech major in Spain, going on to my last year.