Determine Rate Law from Reaction Mechanisms, Fast then Slow Step: Part I

How to determine the rate law (equation) using reaction mechanisms. This example has the fast step precede the slow step.
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  • @GoogleUser-qi1uj
    @GoogleUser-qi1uj3 жыл бұрын

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    @OldSchoolChemistry

    3 жыл бұрын

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    Жыл бұрын

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  • @Cheer750
    @Cheer7504 жыл бұрын

    WOW, THIS MADE IT SO CLEAR, WAS LOOKING FORWARDS FOR MORE EXAMPLES. THANK YOU. CURRENTLY TAKING GEN CHEM.

  • @asim6432
    @asim64322 жыл бұрын

    I loved your energy, and the way you explain things simply makes everything clear. Thank you and looking forward to watching more of you videos.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

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    @OldSchoolChemistry

    2 жыл бұрын

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    2 жыл бұрын

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    @clouded17183 жыл бұрын

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    @OldSchoolChemistry

    3 жыл бұрын

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    @rueb- Жыл бұрын

    I have been looking for this everywhere online and finallyyyy came across this video. Thank you so much!

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    @OldSchoolChemistry

    Жыл бұрын

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    @OldSchoolChemistry

    2 жыл бұрын

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    7 ай бұрын

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  • @lamicetilib3188
    @lamicetilib31883 жыл бұрын

    you really saved me!! i have a test on this later and i didnt know how to do this very well. thank you for posting. its late but i hope you have a great day as well!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Lamice, I am so glad. I hope the rest of your class goes well. Good job working hard!!😊

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    @OldSchoolChemistry

    2 ай бұрын

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    @Iconiccult196 Жыл бұрын

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    @OldSchoolChemistry

    Жыл бұрын

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  • @art3mis873
    @art3mis8732 жыл бұрын

    I realize this was posted two years ago, but thank you so much for this tutorial! My teacher uses a style where he teaches us the basics, and then throws us a quiz with a much more difficult problem that hasn’t been explained before, like this. This helped so much 💛

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    @OldSchoolChemistry

    2 жыл бұрын

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    @OldSchoolChemistry

    3 жыл бұрын

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    @OldSchoolChemistry

    23 күн бұрын

    Jason, thank you for that very kind and classy comment:)

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    @SCHCRSBYR4 ай бұрын

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    @OldSchoolChemistry

    4 ай бұрын

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    @Linda-ek4ii Жыл бұрын

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    Жыл бұрын

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    Жыл бұрын

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    @brendalopez1473 жыл бұрын

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    @OldSchoolChemistry

    Жыл бұрын

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    @OldSchoolChemistry

    2 жыл бұрын

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    @OldSchoolChemistry

    3 жыл бұрын

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    @jomargvelez-rivera6023 жыл бұрын

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  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Thanks Jomar! I hope your class goes well😊

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    @khushirathee89552 жыл бұрын

    concept clear .....thanku so much

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    @munira84862 жыл бұрын

    Wow! You made everything easier than what it look in my slides, thank you 💜💜

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Munira, I am so glad!! I hope it goes well for you:)

  • @charm5874
    @charm58749 ай бұрын

    Thank you so much! It was really hard to find a video where the equilibrium step had an intermediate with another reactant for the product so I was struggling to understand how to step up my equation to get a -1 exponent. I didn't give up and found your video! Thank you for giving a great example :)

  • @OldSchoolChemistry

    @OldSchoolChemistry

    9 ай бұрын

    Hi Charm, I am so glad it was helpful! I hope your class goes well. I am proud of you:)

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    @xuhaoyuan2907 Жыл бұрын

    Awesome video, really helps me.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Xu, I am so glad! Thank you for your comment:)

  • @tyneciadavis408
    @tyneciadavis4082 жыл бұрын

    wow you made this so much simplier than my professor, U taught me the basics now i can do this myself. OMG thanks so much

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Tynecia, I am SO glad! I hope your class goes well. Please subscribe if you have not already. Thanks:)

  • @baraskparas9559
    @baraskparas95592 жыл бұрын

    Good explanations, appreciated.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Thanks Barask!! :)

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    @westsideasians63875 ай бұрын

    I was really confused when my chem professor went over this during lecture a few days back, but this makes everything so clear! TYSM

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi Westside Asians, this is a complex concept. I am SO glad you understand it now. Thank you for letting me know. God bless you!!

  • @PowerrPundit
    @PowerrPundit3 жыл бұрын

    Thank you for all you do!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Leo, my pleasure. I hope your class goes well.😊

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    @OldSchoolChemistry

    Жыл бұрын

    Thank you Carolynn! It is a joy to teach chemistry to great students like you!!

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    @the25viole42 Жыл бұрын

    Thank you so much for this I learned so much

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi the25viole, I am so glad! Thank you for your comment:)

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    @MohamedKhaled-si9in Жыл бұрын

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  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Mohamed, I am so glad! Thank you for your comment:)

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    @tomasb76452 жыл бұрын

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    @OldSchoolChemistry

    2 жыл бұрын

    Hi Tomas, thank you for that kind comment. I am glad it was helpful! Good luck in your class:)

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    @alxgdg3 жыл бұрын

    Thank you so much for this video! You explained this more clearly than my prof. This is the only vid that explained it the way my prof did!

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    @OldSchoolChemistry

    3 жыл бұрын

    Hi Lexia, I’m so glad it was useful. I hope your class goes well!!😊

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    @alxgdg

    3 жыл бұрын

    @@OldSchoolChemistry I did well on my midterm exam because of this! Thank you again!!☺️

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    @OldSchoolChemistry

    3 жыл бұрын

    Awesome! I am so very proud of you. Well done🎉

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    @nalabrown48394 ай бұрын

    Omg thank you so much you explained this wayyy better than my professor did.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi Nala, I am so glad it was helpful! Thank you for letting me know. God bless you in your class:)

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    @ynl_rm34112 жыл бұрын

    Thanks a lot, this really helped

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    @OldSchoolChemistry

    2 жыл бұрын

    Hi ARM_J, I am so glad! Please subscribe if you have already:) Thanks!

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    4 ай бұрын

    Hi Majd, I am so glad you think so! Thank you for your comment:)

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    @ireenakhan2 жыл бұрын

    This was explained beautifully....... i was exhausted beacause i could not understand it now i know the concept..... Thank you ma'am💜💜💜💜💜

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    @OldSchoolChemistry

    2 жыл бұрын

    Hi Stawberry! I am so glad you feel good about it now. I am proud of your hard work! :)

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    @jacquelinegabrielaserrano61263 жыл бұрын

    wonderful and clear! thank you

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Jacqueline, I’m so glad. Thank you! I hope your class goes well 😊

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    @dreamchaser51732 жыл бұрын

    Thank you so much! This was really helpful!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Yamna, I am so glad! I hope your class goes well:)

  • @sofiabasalatahmed5040
    @sofiabasalatahmed50403 жыл бұрын

    Helped me a lot. Thank you 😃

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Sofia, I’m so glad. Please subscribe if you haven’t already. Good luck with your class!😊

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    @saxymusic79062 жыл бұрын

    oh my goodness you are like the chemistry version of professor leonard! This was so well explained!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Saxy, I am glad you think so. Thank you for your comment! :)

  • @origamigek
    @origamigek Жыл бұрын

    Oh this is so much better than this other video where he doesn't explain why stuff is ommitted or assumed, just ipse dixit.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Origamigek, I am glad you think it was helpful. Thanks! I hope your class goes well:)

  • @linahermiz7341
    @linahermiz73412 жыл бұрын

    this helped so much thank you!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Lina, I am so glad. I hope your class goes well. Please subscribe if you have not already. Thanks!

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    @AndreBotero50 Жыл бұрын

    WOW!! This was such an amazing video!!! You are such a slay teacher :)

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Andre, I am so glad it was helpful. I hope your class goes well!

  • @Sia-wz1fv
    @Sia-wz1fv5 ай бұрын

    it was really cool thanks for explaining so well😇

  • @OldSchoolChemistry

    @OldSchoolChemistry

    5 ай бұрын

    Hi Sia, I am so glad it was helpful. Thank you for your comment!

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    @deenaawad7892 жыл бұрын

    You saved me and my sister!!!! ❤️❤️❤️

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Deena, I am SO glad:) I hope the rest of your class goes well!

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    @michaelwoodward85942 жыл бұрын

    Great video! I could tell you got flustered near the end as students were trying to break into your room! :) If it wasn't for them distracting you, this would have been a flawless explanation for this complex rate law question.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Thanks Michael;)

  • @Mfohdh4
    @Mfohdh45 күн бұрын

    thank you so much !!! i was really struggling with this but now i am concetually clear about this. this is going to help me in jee exam

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 күн бұрын

    Hi Meet Modh, that make me so happy! Thank you for letting me know. God bless you on your exam:)

  • @Alexis-kd9tm
    @Alexis-kd9tm2 жыл бұрын

    Thank you for this awesome explanation! I watched my professor's lecture video and read our chem book a few times but was still not getting it. So just to clarify, we set the forward rate and reverse rate equal to each other and we solve for the intermediate. Then, what we solve for the intermediate, we will plug that into the overall reaction rate.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Perfect! You've got it. Good luck☺

  • @yahyafaiz1614
    @yahyafaiz16143 жыл бұрын

    Fantastic. Thank you

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    You’re welcome:) I hope your class goes well!

  • @mulima
    @mulima2 жыл бұрын

    Very helpful ✊🏿

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Thank Mulima. Please subscribe if you have not already. Have a great day!😊

  • @CutiePieDIY
    @CutiePieDIY2 жыл бұрын

    THANK YOU SO MUCH

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi dieah - you are welcome. Thanks for watching:)

  • @malakwaelmamdouh8178
    @malakwaelmamdouh81782 жыл бұрын

    thank you

  • @omkarmote8980
    @omkarmote898011 ай бұрын

    I am a Neet aspirants from India and this was helpful. Thank you mam

  • @OldSchoolChemistry

    @OldSchoolChemistry

    11 ай бұрын

    Hi Omkar, I am so glad. God bless you in your endeavors!

  • @isntethan
    @isntethan3 жыл бұрын

    Thank you very much.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    You're welcome.💕 I hope your class goes well!😊

  • @charisshanklin2628
    @charisshanklin262810 ай бұрын

    Thank you so much for this 😭

  • @OldSchoolChemistry

    @OldSchoolChemistry

    10 ай бұрын

    Hi Charis, You are so welcome! I hope your class goes well:)

  • @Alexis.j3nni
    @Alexis.j3nni2 жыл бұрын

    Wow! Thank you!!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Jenni, thanks for your comment! Please subscribe if you have not already. Thanks!!

  • @zira380
    @zira3803 жыл бұрын

    Thank u for such a really nice explaination🥺💜

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    I hope your class goes well!!😊

  • @zira380

    @zira380

    3 жыл бұрын

    @@OldSchoolChemistry thank u🥰 today i'll do my exam. It's about rx mechanism and catalyst. Wml🙏

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    🙏 💕

  • @sanam5348
    @sanam5348 Жыл бұрын

    God bless youuu!!! Thankss

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Sanam, You are welcome. God bless you too:) Thank you!

  • @user-ts8rc7cn1r
    @user-ts8rc7cn1r2 ай бұрын

    Merci beaucoup

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 ай бұрын

    Je t'en prie!

  • @angelcastaneda9482
    @angelcastaneda9482 Жыл бұрын

    We should just play your videos in class. Thank you for everything

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Angel, That is a very gracious comment. Thank you!! I hope your class goes well;)

  • @arciasuresh2830
    @arciasuresh28304 ай бұрын

    thank you so much for this! also you look like courtney cox!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    4 ай бұрын

    Hi Arcia, what a nice compliment. Thank you. I am glad the video was helpful;)

  • @milesgiehtbrock8510
    @milesgiehtbrock85102 жыл бұрын

    Exam tomorrow!!! Thank you!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    I hope it went well!!!

  • @milesgiehtbrock8510

    @milesgiehtbrock8510

    2 жыл бұрын

    Just got out of it. There wasn’t a question about this LOL

  • @gloriousposers
    @gloriousposers Жыл бұрын

    For step 1, why did you say to write the overall equation when we dont use it? thank you for all you help btw

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Because it shows us what is not included in the final reaction - the intermediates and/or catalysts. Those cannot be in the final rate law. Thanks!

  • @beatrizrosete2827
    @beatrizrosete28279 ай бұрын

    Hello. What happened to that k constant at the bottom at 6:20 you didn't include it. Did it just disappear or ?(:

  • @OldSchoolChemistry

    @OldSchoolChemistry

    9 ай бұрын

    The k1 and k-1 just all become one k in the final rate law. They are simply each a number that combine to make one final number at the end. I should have written that k-1. Honestly, it does not matter as long as you write k on the final rate law. I hope that helps. Thanks Beatriz!

  • @mackenziesoltis4936
    @mackenziesoltis4936 Жыл бұрын

    I want to give you a hug

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Mackenzie, I am so glad it was helpful. I am sending a hug and smiles:)

  • @lamiatahsin6368
    @lamiatahsin63683 жыл бұрын

    Can you be my professor?? Literally, this was such a helpful video TY!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Lamia, I’m so glad it was helpful. I would love to have you in my class! 😊

  • @ayleenc.205
    @ayleenc.205Ай бұрын

    Why did we solve for Cl? I thought we did not include the intermediates into our overall rate law? Thank you!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Ай бұрын

    Hi Ayleen, we solved for Cl so we could then SUBSTITUTE for Cl and remove it from the overall rate law. I hope that helps. Thanks!

  • @shafiurrehman9897
    @shafiurrehman98972 жыл бұрын

    How we can plot Langmuir Adsorption Isotherms and what data is necessary for that??

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Shafi, I am sorry I am not familiar with Langmuir Adsorption Isotherms! Good luck:)

  • @lilysam3523
    @lilysam35233 жыл бұрын

    How do you know if its 1st order, 2nd order, etc, if it is not given?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Lily, If given reaction mechanisms you count the total coefficients on the reactants for the reaction order in the forward direction. If you only have one reactant with a coefficient of 1 then the reaction order is first order for the forward direction. I hope that helps! Thanks:)

  • @justyouraveragecupofjoe9812
    @justyouraveragecupofjoe98122 жыл бұрын

    Hi, so I am a student taking his MCAT soon. That has nothing to do with my question, I just wanted to announce it because... I am in literal hellfire. Anyways, I was wondering how the rate law is the law for the fast reaction mechanism and not for the slow step or even the overall step? I hope you understand what I am asking. Essentially, why find the rate law of the fast step only, or am I missing something? Thank you in advance.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Just Your Average Cup of Joe: Great job preparing for the MCAT! It will be worth the pain:) You only find the fast step rate laws (both forward and reverse) if there are 2 conditions met. 1. The slow step comes after the fast step. And 2. The slow step includes an intermediate. If both conditions are met then you must solve for the intermediate by setting the forward and reverse fast step rate laws equal to each other. You then substitute that solution into the intermediate species in the slow step rate law. I hope that helps!

  • @potatoman6770
    @potatoman67702 жыл бұрын

    What if you have two slow steps?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    HI potato man, you will only have one slow step, the slowest step. Everything else will be at least slightly faster. The slow step determines the overall rate of the reaction because the reaction cannot go faster than the slow step. I hope that helps!

  • @mr.rabbit7288
    @mr.rabbit7288 Жыл бұрын

    Hi, this is a really helpful video! I just would like to ask, shouldn't it be K1[NO2Cl]=K-1[NO2][Cl]+K2[NO2Cl][Cl], since the second slow step is also consuming Cl.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Mr. Rabbit, there is only multiplication and division in rate laws, no addition or subtraction. Thank you for your comment!

  • @mr.rabbit7288

    @mr.rabbit7288

    Жыл бұрын

    @@OldSchoolChemistry Hi, thank you so much for your reply. I am still a little confused over the subject, since an article published in Chem Libretexts does indeed involve addition. If you have time, could you please look at it? The name of the article is here: 4.12: Steady-State Approximation. Thank you so so much

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    That is new to me! Thanks for the info so I can look into it.👍

  • @ufcreloaded4823
    @ufcreloaded48233 жыл бұрын

    Can u elaborate on why slow step is rate determining step ? Do we neglect the time consumed by fast step?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi UfC, pretend 4 students are simultaneously doing 4 different tasks. Everyone is released when each task for all 4 people is finished. Pretend the third person takes the longest to complete their task. Everyone gets to leave when person 3 is finished, the other 3 people sat and waited because they finished their tasks sooner. That is not a perfect analogy but at least gives you an idea of the rate determining step. You are correct, the time for the fast step is negligible in comparison to the slow step. I hope that helps ! Please subscribe if you haven’t already.😊

  • @ufcreloaded4823

    @ufcreloaded4823

    3 жыл бұрын

    @@OldSchoolChemistry Thank you mam.

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    😊👍

  • @everythingbuthair
    @everythingbuthair3 жыл бұрын

    if the rate determining step is the second reaction, will the first fast reaction always be in equilibrium like this?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Tess! It is nice to hear from you again. Yes! The fast step preceding the slow step is always in equilibrium. Thanks😊

  • @everythingbuthair

    @everythingbuthair

    3 жыл бұрын

    @@OldSchoolChemistry ok noted! thank you again for all your help and content that got me through the semester. i can't wait to start watching your ochem videos in a few weeks to prep for my class this fall!!!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    I’m so proud of your hard work!!

  • @izyhew1081
    @izyhew10812 жыл бұрын

    Hi madam.May i know how many elementary steps in the reaction? Is the reversible reaction considered as 1 elementary step? Since are there k1 and k-1 , i confuse if the reversible reaction has 1 or 2 elementary steps .anyway, thank you for the explanation in the videoo ,it helps me a alot!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    Hi Izy, it is considered one elementary step that is reversible and reaches equilibrium. I hope that helps! Thanks:)

  • @Harrykesh630
    @Harrykesh6308 ай бұрын

    I can't help but notice that professor looks like Courtney Cox from friends

  • @OldSchoolChemistry

    @OldSchoolChemistry

    8 ай бұрын

    Hi Harikesh, that is a kind comment. Thank you. I hope your chemistry class goes well:)

  • @abyyisse
    @abyyisse3 ай бұрын

    i love you

  • @payne7792
    @payne7792 Жыл бұрын

    Just perfect!want you here in India💜.where you from mam?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Payne, thank you for your comment! I would love to visit India. I am from the United States of America.💗 God bless you in your home!

  • @payne7792

    @payne7792

    Жыл бұрын

    @@OldSchoolChemistry thank you for keep eye on me.How can I touch with you personally if I have any doubt....?

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    @@payne7792 You can leave a comment in KZread. Thanks!

  • @payne7792

    @payne7792

    Жыл бұрын

    @@OldSchoolChemistry okay thank you mam!

  • @OldSchoolChemistry

    @OldSchoolChemistry

    Жыл бұрын

    Hi Payne, I’m glad this was helpful. I’m in the USA. Grinds to you in beautiful India!

  • @potatoman6770
    @potatoman67702 жыл бұрын

    *screams internally*

  • @OldSchoolChemistry

    @OldSchoolChemistry

    2 жыл бұрын

    I know - there is a lot to digest in this. Go over it slowly, practice, and make it make sense in your mind. Good luck!

  • @bisratamare3265
    @bisratamare32653 жыл бұрын

    REPENT and be BORN AGAIN believing on Messiah Lord Jesus, nothing more important, today is the day of salvation and Jesus can show you the truth, its not blind faith you can see it for yourself if you truly seek like promised. John 3:3 unless a man be born again he cannot see the kingdom of God / Luke 13:3 unless you repent, you will all likewise perish ⚠️❤️⚠️❤️

  • @OldSchoolChemistry

    @OldSchoolChemistry

    3 жыл бұрын

    Hi Bisrat, I’m a believer and love Jesus.💕

  • @bisratamare3265

    @bisratamare3265

    3 жыл бұрын

    @@OldSchoolChemistry Amen! 🙏 ❤️ ‼️‼️