U know the teacher be cookin when they make an educational vid in this format. Honestly love paper users.

Would appreicate if if on later videos you did the calculations and not just gave the answer. The math is the only hard part for me, and so I didn't learn anything

Well explained. Thank you very much 💕🙏

This was so helpful. Thank you!

im confused where did you get 4 in p4?

Wow, i'm so grateful with your contain, it helps me a lot, thank you so much

For anyone confused about the last part. First he solved for k given experiment 1. Given rate equation: Rate= k[P4]^2. First isolate k: K=rate/[P4]^2. Then plug in experiment 1 data which is k=(3.19*10^-4)/(0.0110)^2 = 2.636 = 2.64. Then plug in 2.64 to the original rate equation to look like this: Rate = 2.64*[P4]^2. Question c is asking to solve for the rate given P4 and H2 concentrations. Plug in both (H2 will end up being just 1 since H2^0 = 1 which is why I didn't write it before). The equation should look like this: Rate = 2.64*[0.242]^2. This equals 0.155. Thanks!

thanks, this really helped

Thank you so much I understand now

Do you have a video explaining the units? I’m confused on that part.

@adwelllibbohole717

2 жыл бұрын

Me too

Me taking chemical kinetics class this semester and not getting nothing in the lectures and understanding everything here makes me wanna question my life

Hello good presentation

Pls can u do the calculations and not just give us the answers.l didn't get how u arrived at the answer

Can you please explain with some clarity