A lightboard video explaining the Iodoform reaction - Methyl Ketone Sodium Hydroxide and Iodine
Жүктеу.....
Пікірлер: 4
@Cricicek2 ай бұрын
Great explanation!
@CVPQ5 жыл бұрын
In the final step I draw out the Iodoform and the carboxylic acid with the proton present - this is the final product but not the result of the arrows I have drawn which would leave the acid unprotonated (negative charge on the oxygen like in the title slide at the very beginning)
@aszasq315025 күн бұрын
i'm a bit confused, can someone explained why the OH- ion attack the hidrogen first and then attack the keton? why wouldn't the OH- ion attack the keton right away? the carbon attached to the oxygen should be quite parsially positive no?
Пікірлер: 4
Great explanation!
In the final step I draw out the Iodoform and the carboxylic acid with the proton present - this is the final product but not the result of the arrows I have drawn which would leave the acid unprotonated (negative charge on the oxygen like in the title slide at the very beginning)
i'm a bit confused, can someone explained why the OH- ion attack the hidrogen first and then attack the keton? why wouldn't the OH- ion attack the keton right away? the carbon attached to the oxygen should be quite parsially positive no?
Best explain, Thank you!