Finite Fields & Return of The Parker Square - Numberphile

Ғылым және технология

Matt Parker introducing Finite Fields and re-visits the infamous Parker Square...
Extra footage & become a millionaire by winning The Parker Prize: • Become a MILLIONAIRE b...
More links & stuff in full description below ↓↓↓
The Original Parker Square video: • The Parker Square - Nu...
The paper featured in this video: arxiv.org/abs/1908.03236
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Пікірлер: 1 100

  • @numberphile
    @numberphile2 жыл бұрын

    Extra footage & become a millionaire by winning The Parker Prize: kzread.info/dash/bejne/mqJstdl7mMuqprg.html The Original Parker Square video: kzread.info/dash/bejne/k4OIwcSAXdm9qco.html Stand-Ups Maths on KZread: kzread.info Matt's Books (Amazon): amzn.to/3absFfV Matt's playlist on Numberphile: bit.ly/Matt_Videos Parker Square Merch: numberphile.creator-spring.com/listing/the-parker-square

  • @nowionlywantatriumph

    @nowionlywantatriumph

    2 жыл бұрын

    A millionaire, or a Parker Millionaire?

  • @felixlaroche8039

    @felixlaroche8039

    2 жыл бұрын

    Btw, Matt Parker got something wrong! Z mod powers of primes are *not* fields! For instance, in Z_4, 2x2 = 4 = 0, so that Z_4 has zero-divisors. Hence, since it has zero-divisors, it cannot be a field

  • @ZainAK283

    @ZainAK283

    2 жыл бұрын

    @@felixlaroche8039 Exactly - given a power of a prime, there is a finite field of that size, but it's NOT just modular arithmetic (it's a bit more complicated than that)

  • @zunaidparker

    @zunaidparker

    2 жыл бұрын

    Man I feel attacked...

  • @baronhannsz8900

    @baronhannsz8900

    2 жыл бұрын

    How do we get the article you referenced?

  • @wilkmarton
    @wilkmarton2 жыл бұрын

    I don't mind Numberphile's filler episodes, but I love it when they seriously advance the main plot like this.

  • @dexter2392

    @dexter2392

    2 жыл бұрын

    The Parker Square 2: The Parkering

  • @benwiarda23

    @benwiarda23

    2 жыл бұрын

    Underrated comment

  • @nathanielp758

    @nathanielp758

    2 жыл бұрын

    Numberphile is my favorite anime

  • @geekjokes8458

    @geekjokes8458

    2 жыл бұрын

    100pi likes!

  • @geekjokes8458

    @geekjokes8458

    2 жыл бұрын

    also, LOOOOORE

  • @dig_dus
    @dig_dus2 жыл бұрын

    That P vs NP killed me

  • @RanEncounter

    @RanEncounter

    2 жыл бұрын

    That was golden :D

  • @Saka_Mulia

    @Saka_Mulia

    2 жыл бұрын

    Had to pause for my lols to come to a side-stiched stop

  • @sgttomas

    @sgttomas

    2 жыл бұрын

    Best part 😁

  • @beev

    @beev

    2 жыл бұрын

    surely, NP should be rebranded IP - Inverse Parker.... ;-)

  • @GreRe9

    @GreRe9

    2 жыл бұрын

    +

  • @JulietKneeled
    @JulietKneeled2 жыл бұрын

    When I saw that "Parker" was a property of something in an actual, published research paper I legitimately doubled over laughing. The parker square is officially a real mathematical term!! I never thought I'd see the day.

  • @tsawy6

    @tsawy6

    2 жыл бұрын

    See, at first I was surprised, but after a certain point it's like... Damn Matt and Numberphile's fans have gotta include a significant fractions of budding mathematicians

  • @jamesonhardy2126

    @jamesonhardy2126

    2 жыл бұрын

    Same

  • @DomenBremecXCVI

    @DomenBremecXCVI

    2 жыл бұрын

    @@tsawy6 I feel like there are 10 types of mathematicians watching Numberphile; those that came here because they know maths, those that were brought into maths by Numberphile and those who forgot this comment isn't supposed to be a spin on the classic binary joke.

  • @AaronRotenberg

    @AaronRotenberg

    2 жыл бұрын

    @@DomenBremecXCVI That's a real Parker list, if I do say so myself.

  • @Deus_Almighty

    @Deus_Almighty

    2 жыл бұрын

    It's not published though

  • @SkywalterDBZ
    @SkywalterDBZ2 жыл бұрын

    In the Parker Square video, Matt said something like "In mathematics, fame is different. It's when someone looks you up once a century.". This must mean Matt is REALLY famous now.

  • @custodeon

    @custodeon

    2 жыл бұрын

    he is some hybrid of maths-famous and regular famous which is both more famous than maths-famous and less famous than celebrity-status

  • @thealkymyst

    @thealkymyst

    2 жыл бұрын

    Parker Famous.

  • @SG2048-meta

    @SG2048-meta

    Жыл бұрын

    @@custodeon TL;DR a superposition of different famousnesses

  • @tinkut8960

    @tinkut8960

    Жыл бұрын

    @@custodeon he’s a Parker square of a celebrity

  • @crisdunbar4753

    @crisdunbar4753

    Жыл бұрын

    He's on a coffee mug fer gosh sake. Millennia from now, archaeologists (probably alien) will dig them up and he'll still be famous.

  • @QuantumHistorian
    @QuantumHistorian2 жыл бұрын

    It's so rare, and incredibly delightful, to see a grown man beaming with joy at what is literally a consequence of being mocked in front of an audience of millions.

  • @landsgevaer

    @landsgevaer

    2 жыл бұрын

    He is a meme. I would be happy too...

  • @warasilawombat

    @warasilawombat

    2 жыл бұрын

    Honestly I think it’s quite sweet that they named it after him.

  • @almoglevin

    @almoglevin

    2 жыл бұрын

    But affectionally mocked.

  • @broadleyn

    @broadleyn

    2 жыл бұрын

    Well, self-mocked, but yep. Matt is awesome.

  • @josephjennings7932

    @josephjennings7932

    2 жыл бұрын

    All this mockery just earned him a place in mathematics for posterity.

  • @saraqael.
    @saraqael.2 жыл бұрын

    8:33 Kid: “Mom can I have P vs NP“ Mom: “No, we have P vs NP at home“ P vs NP at home: Parker vs Non-Parker

  • @elementalsheep2672

    @elementalsheep2672

    2 жыл бұрын

    The Parker P vs NP

  • @EcceJack

    @EcceJack

    2 жыл бұрын

    @@elementalsheep2672 that's the one! 😂

  • @fariesz6786

    @fariesz6786

    2 жыл бұрын

    brilliant

  • @aplanosgc6963

    @aplanosgc6963

    2 жыл бұрын

    The better version

  • @Twisted_Code

    @Twisted_Code

    2 жыл бұрын

    let me just quickly validate this joke... done

  • @WMTeWu
    @WMTeWu2 жыл бұрын

    Everybody seem excited that "parker" has been mentioned in real, published research paper - but I think most of you underestimate how exited the authors of the paper are, that their paper has been featured in real, published Numberphile video.

  • @nomekop777

    @nomekop777

    2 жыл бұрын

    It's basically numberphile bait

  • @mati.benapezo

    @mati.benapezo

    Жыл бұрын

    And we got tricked.

  • @sakkikoyumikishi
    @sakkikoyumikishi2 жыл бұрын

    Also: "They're all non-Parker - because they work." *dies inside*

  • @Triantalex

    @Triantalex

    4 ай бұрын

    ??

  • @wecantry4393
    @wecantry43932 жыл бұрын

    Parker square video was one of the most fun video I've ever watched. I never thought how a simple mathematical puzzle can be so enchanting.

  • @goldnutter412

    @goldnutter412

    2 жыл бұрын

    1/7 is a cool number with 6 recurring digits and the 0 is the FP function How many are there for 1/49 ? 😎

  • @veggiet2009

    @veggiet2009

    2 жыл бұрын

    @@goldnutter412 but not in integer fields

  • @goldnutter412

    @goldnutter412

    2 жыл бұрын

    14:48 there's 13 ? really ? 🤣 This seems right to me for personal reasons hahaha also distribution wise you wouldn't expect, but possibly suddenly another group appears wayyyy up there in the giant numbers.. hm

  • @TECHN01200
    @TECHN012002 жыл бұрын

    I love how mathematicians use Parker as an adjective meaning "almost works"...

  • @dexter2392

    @dexter2392

    2 жыл бұрын

    If the large mathematical community finally caught it... Parker will be a legend.

  • @pvic6959

    @pvic6959

    2 жыл бұрын

    idk if I would be happy or sad if my name was given that definition. On one hand, my name has become an ACTUAL property in math. Like in a published paper - it will live on forever. but on the other hand, the property my name describes is "doesnt work" LOLOL

  • @Relkond

    @Relkond

    2 жыл бұрын

    Matt Parker is a comedian. Some of the best jokes in life are where things almost work. I’m sure he’s elated.

  • @TECHN01200

    @TECHN01200

    2 жыл бұрын

    @@pvic6959 At the very least, they have a sense of humor...

  • @brandonthesteele

    @brandonthesteele

    2 жыл бұрын

    I would be tremendously honored to have my name used in math in any capacity. Matt seems pretty jazzed about it.

  • @olifantoliver
    @olifantoliver2 жыл бұрын

    Everytime he said "Non-Parker.. because.. it's working" you can see in his eyes, a part of him dies. :D

  • @simonmultiverse6349

    @simonmultiverse6349

    2 жыл бұрын

    It's fame... don't knock it!

  • @loturzelrestaurant

    @loturzelrestaurant

    2 жыл бұрын

    @@simonmultiverse6349 Anti-Science is on the Rise. Uneducation causes Muffled Logic to be be more and more accepted, so casual B.S. is getting more and more popular. People embarass themselves all the time now by claming NASA is faking the Sun, the moon is a hologram, the Earth is flat, Aura and Chakra are kinda Science, so trust me bro, i know we are all immortal - oh, and one last thing: Koalas are Fake; they are ALL CGI. All.

  • @SillyMakesVids

    @SillyMakesVids

    2 жыл бұрын

    A part of him becomes Parker.

  • @loturzelrestaurant

    @loturzelrestaurant

    2 жыл бұрын

    @Irony What a silly comment, Irony.

  • @Triantalex

    @Triantalex

    4 ай бұрын

    false :D.

  • @alancash6420
    @alancash64202 жыл бұрын

    I look forward to seeing Matt being awarded the Inverse Fields Medal

  • @LeonardChurch33

    @LeonardChurch33

    2 жыл бұрын

    Would that involve paying $15,000 for damages done to the field of mathematics?

  • @tobiaswilhelmi4819

    @tobiaswilhelmi4819

    2 жыл бұрын

    I would much more like to see a Parker Medal for mathematical innovations that almost work.

  • @MattMcIrvin

    @MattMcIrvin

    2 жыл бұрын

    The Parker Finite Fields Medal

  • @cookieninja2154

    @cookieninja2154

    2 жыл бұрын

    The medal for math that doesn't work but you gave it a go.

  • @simonmultiverse6349

    @simonmultiverse6349

    2 жыл бұрын

    @@MattMcIrvin Damn! You got there before me!

  • @feudiable
    @feudiable2 жыл бұрын

    The 6x6 table says 3*2 = 1 mod 6, but I guess that is a parker-one.

  • @Minihood31770

    @Minihood31770

    2 жыл бұрын

    The Parker Times Table

  • @cybisz2883

    @cybisz2883

    2 жыл бұрын

    Lol, I caught that too. Seems closeups of that table were edited out due to the mistakes in it.

  • @laurihei

    @laurihei

    2 жыл бұрын

    Plus he also circled that one when circling all the ones in the table ':D

  • @simonmultiverse6349

    @simonmultiverse6349

    2 жыл бұрын

    Can we have a Parker Timetable, (not "Times Table") where the trains almost but not quite arrive at the times they're supposed to?

  • @laurihei

    @laurihei

    2 жыл бұрын

    @@simonmultiverse6349 I think we already have that :D

  • @helpme6599
    @helpme65992 жыл бұрын

    It's been 5 years, but Matt Parker is still Matt Parker.

  • @yourguard4

    @yourguard4

    2 жыл бұрын

    Matt Parker + 5 years = Matt Parker ? :D

  • @2D_SVD

    @2D_SVD

    2 жыл бұрын

    And that's great!

  • @Ravendragon52

    @Ravendragon52

    2 жыл бұрын

    Matt Parker is officially invariant wrt time

  • @proloycodes

    @proloycodes

    2 жыл бұрын

    88th like!

  • @idahogie

    @idahogie

    2 жыл бұрын

    And I'm still non-Parker.

  • @HopUpOutDaBed
    @HopUpOutDaBed2 жыл бұрын

    Finally someone explaining P vs. NP in a way everyone can easily understand.

  • @Triantalex

    @Triantalex

    4 ай бұрын

    false.

  • @agar0285
    @agar02852 жыл бұрын

    I love the fact that "Parker" defined as "not working" is an actual term in a math research. I just started laughing so much, this was awesome.

  • @user-zn4pw5nk2v

    @user-zn4pw5nk2v

    2 жыл бұрын

    6:50 ( left square 3;2 )(seen the meme, just was about to comment on the Parker square, and was informed that it's actually a Parker Parker square. The circle later really helped )

  • @RaiinWing

    @RaiinWing

    2 жыл бұрын

    lets gooo you watch numberphile too

  • @agar0285

    @agar0285

    2 жыл бұрын

    @@RaiinWing Hi rainwing 😀

  • @Triantalex

    @Triantalex

    4 ай бұрын

    ??

  • @YosmHere
    @YosmHere Жыл бұрын

    For those who might've missed a pun at 8:38: P v/s NP (Which in video is used as a short form for Parker v/s Non-Parker) is actually one of the seven millenium problems by the Clay University. Each problem worth a million dollars. That means if you solve it you'll get a million dollars.

  • @P3dotme
    @P3dotme2 жыл бұрын

    I think I'm going to start saying "don't go trivial" randomly to people.

  • @goldnutter412

    @goldnutter412

    2 жыл бұрын

    Just answer any complex question with relativity Meaning of life ? relativity (or 369)

  • @MrAlRats

    @MrAlRats

    2 жыл бұрын

    For String Theorists, every sequence of "Why" questions leads ultimately to the answer "String theory".

  • @goldnutter412

    @goldnutter412

    2 жыл бұрын

    @@MrAlRats but they have to be "strings" of physical matter, with 2 dimensions 😅

  • @karlwaugh30
    @karlwaugh302 жыл бұрын

    For finite fields of prime power orders there was some confusion in this video. The integers mod 49 or 4 or 8 etc don't produce finite fields of those orders. It's just that there do exist other finite fields of those orders with different structure to them. Eg. In Z mod 4 the multiples of 2 are 2x1 = 2, 2x2=0, 2x3=2 and 2x0=0 and so there is no inverse for 2.

  • @samuelthecamel

    @samuelthecamel

    2 жыл бұрын

    The true Parker Finite Fields

  • @MrSamwise25

    @MrSamwise25

    2 жыл бұрын

    Thanks for pointing this out! :)

  • @probablyapproximatelyok8146

    @probablyapproximatelyok8146

    2 жыл бұрын

    And I think the way you can get finite fields of prime power order p^k is by adding zeros of particular polynomials to the finite field Z/pZ, much like you can add i (one of the zeros of x^2 + 1) to the real numbers to get a new, bigger field: The complex numbers

  • @djyotta

    @djyotta

    2 жыл бұрын

    I was thinking that finite fields of order of "powers of primes" could be things other than Z mod (p^r), but note that the paper says: Finite Fields and Rings - which implies to me that they're claiming that magic squares of squares don't just work in (most) finite fields of the form Z mod (p), but also some rings of the form Z mod (p^r) where p is prime...

  • @johanrichter2695

    @johanrichter2695

    2 жыл бұрын

    Yes, that is a very important point, hope they correct that.

  • @ugu8963
    @ugu89632 жыл бұрын

    I'm feeling the need to hear the word "Parkericity" "Hey how about the Parkericity of that field ?"

  • @prashantadhimal

    @prashantadhimal

    2 жыл бұрын

    Parkerness?

  • @annie4424

    @annie4424

    2 жыл бұрын

    This. This needs to become a thing.

  • @mond256

    @mond256

    2 жыл бұрын

    Why not have degrees of Parker for how far off from working it is

  • @Games_and_Music

    @Games_and_Music

    2 жыл бұрын

    Margin of error is now called "Parker approximation".

  • @NoNameAtAll2

    @NoNameAtAll2

    2 жыл бұрын

    @@Games_and_Music approximation is already Parker property (Parker action?) Parkerximation?

  • @illesizs
    @illesizs2 жыл бұрын

    "Every real number has a buddy real number, where if they multiply together, you get 1." 1: "Am I a joke to you?" 0: "Yes."

  • @pulsefel9210

    @pulsefel9210

    2 жыл бұрын

    1 is such a lonely number. so powerful they wont even let it have its proper title of prime of primes.

  • @Sibula

    @Sibula

    2 жыл бұрын

    @@pulsefel9210 You could even say that one is the loneliest number

  • @neopalm2050

    @neopalm2050

    2 жыл бұрын

    -1:

  • @BizVlogs

    @BizVlogs

    2 жыл бұрын

    1? One’s buddy number is 1. 0? Zero is the same as n (limit as n goes to zero). So its buddy number in that case is 1/n (limit as n goes to 0).

  • @allanolley4874

    @allanolley4874

    2 жыл бұрын

    It is after all an ancient mathematical proposition that one is not a number but the unit first enunciated by Aristotle. If 1 is not a number then 0 is right out.

  • @iah7264
    @iah72642 жыл бұрын

    "Return of the Parker square" This is probably the most clickbaity title possible, for numberfile fans ;)

  • @Neefew

    @Neefew

    2 жыл бұрын

    Is it clickbait if it's true?

  • @SheldonBird

    @SheldonBird

    2 жыл бұрын

    It's the only reason I clicked instantly

  • @simonmultiverse6349

    @simonmultiverse6349

    2 жыл бұрын

    Return of The Pink Parker?

  • @simonmultiverse6349

    @simonmultiverse6349

    2 жыл бұрын

    ...featuring Peter Parker? (different superhero, I know)

  • @alfieomega

    @alfieomega

    2 жыл бұрын

    it did reappear, not as main focus though more like a cameo old character in the new series

  • @shawon265
    @shawon2652 жыл бұрын

    Matt Parker: You cannot find a whole number inverse of an integer. 1: I will pretend I didn't see that.

  • @purrplaysLE

    @purrplaysLE

    2 жыл бұрын

    1*1=1

  • @ragnkja

    @ragnkja

    2 жыл бұрын

    Unless it’s the identity. Just like the only non-negative number with a non-negative additive inverse is 0.

  • @floyo
    @floyo2 жыл бұрын

    5:13 The finite field with 49 elements is not actually the integers mod 49 (Z/49Z), because 7 has no inverse. The construction of this field is more complicated.

  • @jaredbitz

    @jaredbitz

    2 жыл бұрын

    For the curious - to actually construct that finite field, consider the set of polynomials with coefficients modulo 7. You can get a field with 49 elements by taking all polynomials of the form ax + b, and then doing arithmetic on them modulo x^2 - 3 (again all the coefficients are modulo 7). 7 choices for a and 7 choices for b make 49 elements, and you can never multiply two polynomials to get zero because x^2 - 3 doesn't factor modulo 7. You can get finite fields whose sizes are higher prime powers (i.e. 7^n) by doing arithmetic modulo some irreducible polynomial of degree n.

  • @FireSwordOfMagic

    @FireSwordOfMagic

    2 жыл бұрын

    Same with any number that isn't a prime.

  • @danielyuan9862

    @danielyuan9862

    2 жыл бұрын

    @@jaredbitz why modulo x^2-3 and not x^2?

  • @danielyuan9862

    @danielyuan9862

    2 жыл бұрын

    @@jaredbitz no wait, it's because you can imagine x=sqrt(3)

  • @user-fd1ux4ly1e

    @user-fd1ux4ly1e

    9 ай бұрын

    @@jaredbitz , or for people who don't know how to do that with finite fields, but do know how complex numbers work, imagine that i is the square root of 3 mod 7, and consider things of the form a + bi where a and b are in Z7.

  • @namduong8437
    @namduong84372 жыл бұрын

    The fact that you still have the mug at 7:52 makes me super happy to follow math community

  • @advaykumar9726

    @advaykumar9726

    2 жыл бұрын

    3 blue 1 brown

  • @stardustpan
    @stardustpan2 жыл бұрын

    PARKER SQUARE LES GOOOO

  • @KSJR1000
    @KSJR10002 жыл бұрын

    This is the most clear explanation of N vs NP I've ever seen.

  • @chimiseanga9054
    @chimiseanga90542 жыл бұрын

    Correction: only "integers mod a prime" is a field, not "integers mod a power of a prime". There are finite fields of size "power of a prime" but they are not a quotient of the integers.

  • @keineangabe8993

    @keineangabe8993

    2 жыл бұрын

    Thank you! I didn't think they would miss such an obvious mistake..

  • @mbartelsm

    @mbartelsm

    2 жыл бұрын

    It was a Parker-explanation

  • @kijkbuis8575

    @kijkbuis8575

    2 жыл бұрын

    These are the Parker finite "fields"

  • @Sam_on_YouTube
    @Sam_on_YouTube2 жыл бұрын

    I tip my hat to the author of this paper. Well done.

  • @JanxakaJX
    @JanxakaJX2 жыл бұрын

    Matt Parker is a great teacher and quite funny too. I love seeing him here.

  • @MrQwefty
    @MrQwefty2 жыл бұрын

    He gave it a go, he tried, and finally he's achieved infamy in actual mathematical research! Kudos to you Matt

  • @davidwilsch4668
    @davidwilsch46682 жыл бұрын

    Z mod 49 and Z mod 25 are NOT fields. There exist fields with 49 or 25 elements but they aren't simply integers modulo some number.

  • @davidkalichman

    @davidkalichman

    2 жыл бұрын

    THANK YOU for pointing this out. An uncharacteristic error from Matt :(

  • @IamBATMAN13
    @IamBATMAN132 жыл бұрын

    The P vs NP reference killed me

  • @ImaginaryMdA
    @ImaginaryMdA2 жыл бұрын

    The Parker prize needs to become a reality, surely!

  • @nielskorpel8860

    @nielskorpel8860

    2 жыл бұрын

    For all maths research whose results do not accomplish what they aimed for,... ...but which do make some headway towards it, which gives an insight into the subject, which explores useful perspective on the subject, or which studies the hardship of proving what you are trying to prove,... ... so that maybe one day we can make more informed maths research that DOES achieve what it was trying to do. In other words, for all the disappointing, unglamorous near-misses which might eventually lead to actual results. Not a bad thing to have a prize for, actually. If this approach of near misses does at some point answer the question whether the integers are parker or not, then it actually becomes a serious proposal: the approach worked.

  • @camicus-3249

    @camicus-3249

    2 жыл бұрын

    @@nielskorpel8860 Basically, "Give it a go"

  • @EdwardCree
    @EdwardCree2 жыл бұрын

    "What about _infinite_ rings?" Well, if a magic square of squares "works" in ℤ, then it must also work modulo n ∀ n∈ℕ. However, in some of those ℤₙ, the square may have repeated entries that weren't there in ℤ; in particular we know that this must be the case for all n for which ℤₙ is Parker. (As the paper points out, and as you mention in the extra footage, a solution in ℤ would imply there are only finitely many Parker rings.) Thus those rings give us constraints on any possible solution in ℤ; for instance, ℤ₆₇ being Parker implies that a magic square of squares in ℤ cannot have all nine numbers distinct modulo 67, because otherwise it would imply a solution in ℤ₆₇. It's the Parker rings, and _only_ those rings, which help us by cutting down the search space for ℤ; Parker rings are _useful_ because they help us identify what _won't_ work, and that can be valuable in itself :) Hope that helps Matt feel a little better about his eponymy.

  • @shaftahoy
    @shaftahoy2 жыл бұрын

    14:46 'Parker' being in Comic Sans is the cherry on the top of this video.

  • @numberphile

    @numberphile

    2 жыл бұрын

    ;)

  • @rubenlarochelle1881
    @rubenlarochelle18812 жыл бұрын

    "Technology has moved on since", showing a 3D-printed version of what he once wrote on brown paper.

  • @smallishkae
    @smallishkae2 жыл бұрын

    “If you’ve got a number, I dunno… a.” Can’t wait to see that one out of context

  • @ferraneb
    @ferraneb Жыл бұрын

    5:04 Just to clarify the the integers mod a power of a prime do NOT form a field in general (for example, 7 does not have an inverse mod 49). It is only the case when the power is 1 (that is, the integers mod a prime). There exist finite fields of size p^k for p prime and k > 1, but they are constructed differently.

  • @user-vn8kw9sm3k
    @user-vn8kw9sm3k2 жыл бұрын

    It's not true that integers mod 49 (or any non-trivial prime power) form a field. For example, 7 doesn't have an inverse mod 49. I think Matt got confused by the notation F_{49} for a finite field with 49 elements.

  • @bootesvoidband
    @bootesvoidband2 жыл бұрын

    I’m waiting for the OEIS entry for Parker Numbers

  • @babel_

    @babel_

    2 жыл бұрын

    A308838, the Orders of Parker finite fields of odd characteristic, aka the list shown ignoring 2. The "state of the art" has improved and it was shown 243 is a Parker finite field.

  • @terraqueo89
    @terraqueo892 жыл бұрын

    This is one of the best gags of this channel lol

  • @TheSummoner
    @TheSummoner2 жыл бұрын

    5:09 - Is he implying that the integers mod 49 are equivalent to the finite field of order 49? Because as far as I know this only work for primes, for prime *powers* the multiplicative structure is actually different.

  • @Vodboi

    @Vodboi

    2 жыл бұрын

    Yea, just noticed that, in Z_49 you have 7*7=0, and a field doesn't have zero divisors, so its not a field. I guess he kinda confused it with the fields of order equal to that prime power.

  • @pianissimo7121

    @pianissimo7121

    2 жыл бұрын

    I am a bit confused, does a Z7 field for example, have 0 in it? Cause 0 doesn't have a multiplicative inverse does it?

  • @AGLubang

    @AGLubang

    2 жыл бұрын

    @@pianissimo7121 Yes. All fields must have a 0. The rule for multiplicative inverse doesn't include 0, as with usual real numbers, rationals, etc.

  • @dabluse3497

    @dabluse3497

    2 жыл бұрын

    @@pianissimo7121 In fields, zero is a special number that follows different rules. In every field, 0*a=0, for any a in the field, and 0 is the only number that doesn't have a multiplicative inverse, because a field needs 0 to work. That's true in the real numbers, complex numbers, and any other field. Hope that clears it all up.

  • @Vodboi

    @Vodboi

    2 жыл бұрын

    @@pianissimo7121 The statement of being a field is that: "Every nonzero element has a multiplicative inverse", where zero is defined as the element satisfying 0+x=x+0=x for all x in the field (in other words, 0 is the additive identity). So yes Z_7 has the elements {0,1,2,3,4,5,6}, where all but 0 have multiplicative inverses

  • @PopeLando
    @PopeLando2 жыл бұрын

    8:09 I am made up, and enormously proud of you, Matt! Edited: doubly proud of your joke at 8:33 🤣🤣

  • @WGSen
    @WGSen2 жыл бұрын

    I am in love with this whole saga

  • @antezante
    @antezante2 жыл бұрын

    This was great, having in-depth math on a higher level than usual! Please do more of this!

  • @codelerias
    @codelerias2 жыл бұрын

    I love it when they bring back season 1 characters!

  • @ModeDecay
    @ModeDecay2 жыл бұрын

    I wish there was a compilation of every time Matt says "big fan..."

  • @rubenlarochelle1881
    @rubenlarochelle18812 жыл бұрын

    Parker and non-Parker being used in an actual paper was an hilarious twist ahahahah

  • @argentvixen
    @argentvixen2 жыл бұрын

    This is about right. We had the "Mould effect" so now Matt is just catching up to Steve with the "Parker property". I assume this is the omen that Matt will catch up with a million subs soon. 😘

  • @cereal_chick2515
    @cereal_chick2515 Жыл бұрын

    This is one of the greatest character arcs I've ever seen!

  • @davidharmeyer3093
    @davidharmeyer30932 жыл бұрын

    I burst out laughing when you put "P vs. NP" as an overlay on the screen for Parker vs. Non Parker fields

  • @johnchessant3012
    @johnchessant30122 жыл бұрын

    Important note (for anyone who, like me, is going to spend a few hours looking into this): The finite field F_(p^k) is NOT the integers mod p^k. For example, F_9 = {0, 1, 2, i, 1+i, 2+i, 2i, 1+2i, 2+2i} where i = sqrt(-1).

  • @redapplefour6223

    @redapplefour6223

    2 жыл бұрын

    well you know for pedantry that it's actually that i^2 = -1, thats the technical definition

  • @StoicTheGeek

    @StoicTheGeek

    2 жыл бұрын

    Darn I just went and typed all that out less clearly and then I saw your comment!

  • @StoicTheGeek

    @StoicTheGeek

    2 жыл бұрын

    Please also not that the field F_(p^k) has character p ie. np = 0 for all n in the field

  • @leftaroundabout

    @leftaroundabout

    2 жыл бұрын

    @@redapplefour6223 that's not the technical definition either. Or, well, it is part of the definition, but of the technical definition of the _multiplication operation_ in ℂ, not of i. The imaginary unit can't be defined like this. (Note that e.g. in the quaternions there are three distinct values that all fulfill this equation!) To make it a technical definition, you need to first define ℂ as a 2-dimensional vector space with unit vectors 1 and i, and only then equip it with the multiplication that has this property, in order to form a field.

  • @redapplefour6223

    @redapplefour6223

    2 жыл бұрын

    @@leftaroundabout right, thanks! makes sense that that's how that works. so are field extensions are just unit vectors in disguise?

  • @vindj2391
    @vindj23912 жыл бұрын

    14:10 i don't know why but seeing those parkers pop up on the screen cracks me up

  • @kwanarchive
    @kwanarchive2 жыл бұрын

    It would be hilarious if Parker vs Non-Parker becomes an elemental part in solving the P vs NP issue.

  • @mathieudehouck9657
    @mathieudehouck96572 жыл бұрын

    This amazing 1 in the column of 2. Made my day Mr Parker. Thank you.

  • @user-gh2fd8kg6v
    @user-gh2fd8kg6v2 жыл бұрын

    This guy has such comical facial expressions, he would probably do well in comedy movies if he did acting.

  • @EM-pb7lk

    @EM-pb7lk

    2 жыл бұрын

    He does math related stand-up

  • @elevown

    @elevown

    2 жыл бұрын

    Well he does do stand up about math lol

  • @danielleanderson6371

    @danielleanderson6371

    2 жыл бұрын

    He's really the Jim Carrey of math(s) educators.

  • @yousorooo

    @yousorooo

    2 жыл бұрын

    Matt Parker is a comedian after all

  • @abhijiths5237

    @abhijiths5237

    2 жыл бұрын

    Mallu spotted 😂

  • @gordonwiley2006
    @gordonwiley20062 жыл бұрын

    We tease because we love you, Matt. Your enthusiasm is infectious. I consider myself, to be a Parker Person.

  • @matheusspable
    @matheusspable2 жыл бұрын

    Ok. When you get named in a paper that actually delivers, and sets a new standard for maths... This is amazing.

  • @nopetuber
    @nopetuber2 жыл бұрын

    I've been following these channels forever and I'm like, look at you Matt! Congrats!

  • @cgibbard
    @cgibbard2 жыл бұрын

    Polynomial rings typically aren't fields, but you can make fractions of them (rational functions) and those will be a field.

  • @JM-us3fr

    @JM-us3fr

    Жыл бұрын

    True, but those aren’t _finite_ fields. You have to mod an irreducible polynomial to get a field.

  • @certainlynotthebestpianist5638
    @certainlynotthebestpianist56382 жыл бұрын

    That's absolutely insane! Parker is not only a scientist, but also a living meme - we know that for quite some time. But the fact, that he's not just an ordinary walking meme (albeit this in itself is something to be proud of), but a meme which is included in scientific papers. Incredibly amazing!

  • @jd9119

    @jd9119

    6 ай бұрын

    Are mathematicians scientists? And if so (or not so), what exactly are the criteria we're using to define what a scientist is?

  • @fregattenkapitan

    @fregattenkapitan

    6 ай бұрын

    ​@@jd9119they do research in universities in a scientific field. Difficult to be more of a scientist....

  • @jd9119

    @jd9119

    6 ай бұрын

    @@fregattenkapitan Except scientists usualy apply the mathematics to another discipline.

  • @MeTalkPrettyOneDay
    @MeTalkPrettyOneDay2 жыл бұрын

    Truly the most troll-y way to get something professionally named after you. I love it.

  • @Astromath
    @Astromath2 жыл бұрын

    A Numberphile video with Matt Parker AND a Stand-Up Maths video on the same day? Nice!

  • @henrygreen2096
    @henrygreen20962 жыл бұрын

    I actually find the the fact that Parker is rare a really cool thing. Sure they “don’t work” but they got people talking first, and there aren’t that many

  • @danielbergman1984
    @danielbergman19842 жыл бұрын

    This video made me happy! Not that any other Numberphile video makes me otherwise, but this one's special. Congratulations Matt!

  • @yoyoyogames9527
    @yoyoyogames95272 жыл бұрын

    awesome stuff as usual, thanks so much for making these sorta vids i love them

  • @julesbrunton1728
    @julesbrunton17282 жыл бұрын

    I've always enjoyed how the multiplication symbol is the addition symbol nudged over 45° and the division symbol is the minus symbol with some dots or recently also just pushed over at an angle /

  • @falquicao8331
    @falquicao83312 жыл бұрын

    The sequel we always knew we needed

  • @baguettegott3409
    @baguettegott34092 жыл бұрын

    This made me so happy. I can't believe this is actually in the paper - what a wonderful thing the community has created here.

  • @DemoniteBL
    @DemoniteBL2 жыл бұрын

    I just love the fact that "Parker" is a term accepted by most if not all mathematicians.

  • @DiracComb.7585
    @DiracComb.75852 жыл бұрын

    Being diagnosed with Parker finite-fieldness is a truly heartbreaking event, my condolences.

  • @cyaneya
    @cyaneya2 жыл бұрын

    This was soooo interesting, thank you Parker for being very knowledgeble and funny. I wish i was able to sit with you with a glass of beer and just ask basic questions about math, which i'm terrible at, and the answers would be probably unexpected. Yeah, thanks again!

  • @asdfghyter
    @asdfghyter2 жыл бұрын

    15:26 I love that the previous video is in the citations for this paper!

  • @EmC_98
    @EmC_982 жыл бұрын

    10:58 nice surprise seeing myself in a Numberphile video!!

  • @mohamedaminekoubaa5231
    @mohamedaminekoubaa52312 жыл бұрын

    a small mistake at 5:04. It only works for prime numbers. If you take a power of prime numbers, it is not modular arithmetic anymore. So basically if you are working in the finite field with four elements, 1+1 is still 0 just like the field with two elements, but you have an extra element x which satisfies x^3=1.

  • @Megalopros
    @Megalopros2 жыл бұрын

    15:25 hey...brady's name is on a paper now (if this has already happened before i didn't notice) (also...it would technically be better if the link was archived since stuff on youtube can disappear)

  • @ancbi
    @ancbi2 жыл бұрын

    Love seeing the KZread url put in as a reference in the paper.

  • @RedStinger_0
    @RedStinger_02 жыл бұрын

    Thank you Parker for taking one for the team.

  • @alastairdouglas1737
    @alastairdouglas17372 жыл бұрын

    Imagine in 100 years and students are asking why Parker means “something that almost works but isn’t quite there”

  • @koenth2359

    @koenth2359

    2 жыл бұрын

    They probably ask: Grandad, what does shoddy mean? - That's an ancient word for Parker.

  • @eathonhowell7414
    @eathonhowell7414 Жыл бұрын

    This is the equivalent of how Gary Larson is now credited as naming "the spiny bits on the end of a Stegosaurus" the Thagomizer because before him nobody had a name for it. It was done as a joke and then someone saw value outside of it being funny.

  • @alienworm1999
    @alienworm19992 жыл бұрын

    8:00 I read the title of the video and knew what I was getting into, but I didn't realize they did poor Matt THAT dirty with the section title

  • @arnauarnauarnau
    @arnauarnauarnau2 жыл бұрын

    Wow this is so cool! Awesome sequel to parker square. Can’t wait for part 3 in a few years

  • @Frownlandia
    @Frownlandia2 жыл бұрын

    Maybe a Mathematician gets to be upset when their name is associated with a kind of failure, but a Standup Mathematician is just happy to setup a punchline.

  • @RuyLopezTheSicilian
    @RuyLopezTheSicilian2 жыл бұрын

    P vs NP has just been solved 😂😂

  • @calebcopeland6425
    @calebcopeland64252 жыл бұрын

    It brings me joy that the Parker Square has left the numberphile bubble and ventured into general mathematics and is being used in published research papers

  • @video99couk
    @video99couk2 жыл бұрын

    Many years from now when you're pushing up the daisies, at least you will be forever remembered having had a mathematical property (even a duff one) named after you. Quite an honour.

  • @shirou9790
    @shirou97902 жыл бұрын

    5:17 that's not exactly true, the integers mod 49 do not work as a finite field. However there is indeed a finite field of 49 elements, which can be constructed as 1st-degree polynomials over the integers mod 7. In fact [Theorem 1] the integers mod n are a field if and only if n is prime, and [Theorem 2] there exists a finite field with n elements if and only if n is the power of a prime p (constructed as polynomials over integers mod p)

  • @andrewharrison8436

    @andrewharrison8436

    2 жыл бұрын

    Ahhh - useful comment. Since 2 is a prime and powers of 2 crop up in computers this creates lots of possibilities once you realise the fields are more complex than just mod n. Now I need to look up polynomials over integers as fields - well that's this afternoon gone.

  • @mxpxorsist

    @mxpxorsist

    2 жыл бұрын

    It's a parker field.

  • @twohoos

    @twohoos

    2 жыл бұрын

    Correct, the powers of primes correspond to extension fields, i.e. ordered n-tuples of elements of the base prime field. It's analogous to how the complex numbers may be viewed as ordered pairs of real numbers.

  • @shirou9790

    @shirou9790

    2 жыл бұрын

    @@twohoos Yeah exactly. Now that I think of it complex numbers are essentially polynomials modulo x²+1, which is really similar to the way we construct finite fields of order p^n.

  • @rickdoesmath3945
    @rickdoesmath39452 жыл бұрын

    I think convergence almost everywhere should be called parker convergence.

  • @meeDamian
    @meeDamian2 жыл бұрын

    This is the greatest video I've watched this year by far 👏🏻👏🏻👏🏻.

  • @rosuav
    @rosuav2 жыл бұрын

    11:51 Maybe I'm too accustomed to seeing numbers in different forms, but adding those numbers mod 29, I just mentally read 28 as -1.

  • @shanathered5910
    @shanathered59102 жыл бұрын

    Finite field F₄ isn’t technically integers mod 4, it’s a bit more complicated than that. Example: 2² = 3, it’s not mod 4 because 2² = 0 mod 4. This is true for all non-prime order fields.

  • @shanathered5910

    @shanathered5910

    11 ай бұрын

    I also showed that integers mod 4 has zero divisors and therefore NOT a field

  • @XtReMz98
    @XtReMz982 жыл бұрын

    Well. I can only guess that Matt Parker’s ego went from finite to non-finite after being established as an (in)famous legend of mathematics! I love this guy!

  • @tth-2507
    @tth-25072 жыл бұрын

    5:15: No, the Integers mod 49 (or any other non prime) do not form a field. It is true, that finite fields exist exactly for the powers of primes, but the higher powers are of a different from.

  • @jimschneider799
    @jimschneider7992 жыл бұрын

    I'm sure this has already been noted, but... @1:05, there is a glaring exception to your assertion that ALL real numbers have a multiplicative inverse, and that is zero.

  • @wompastompa3692
    @wompastompa36922 жыл бұрын

    6:17 3×2 mod 6 = 1 Nice moduParker arithmetic.

  • @eatingsfun
    @eatingsfun2 жыл бұрын

    I can't wait to watch this video

  • @SigmaSixSoftware
    @SigmaSixSoftware2 жыл бұрын

    I haven’t started the video yet and this is the best explication of fields I’ve heard

  • @jolle938
    @jolle9382 жыл бұрын

    What a coincidence I was wearing my Parker Square shirt today!

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