Wonderful explanations!

Great video, sums up a lot of ideas, thank u so much

This is so helpful. Thank you!

Helped me so much in learning this chapter thank youuu!

@nicolettesimonian2770

8 ай бұрын

why are u lying to urself

Helped me in my revision

Wonderful....... God bless you.....

for (I), wouldn't you have two compounds since both carbons are secondary carbons and so the bromine could either end up with carbon #3 or carbon #2 since they're equally stable?

very informative! thanks!

In problem D there is the formation of two tertiary carbocations. However the stabilization is the product of hyperconjugation. The position "1" with the methyl group gets stabilized by 3 C-H-bonds whereas in position "2" with the ethy group it should only get stabilized by 2 C-H-bonds since its -CH2-CH3. So im thinking that the more stable product ist the one wehre the Cl sits on Position "1". Am I thinking about this wrongly? Help or correction would be appreciated, thanks :)

@Yourmom34577

Жыл бұрын

that's what I thought haha, I'm pretty sure it (the H) adds to the less substituted

Thanks a lot ma'am .

@Hipolito-S

Жыл бұрын

😂😂

Thank you so much omg

Nice

First year thank you

Please explain how the structure came about

@max3eey

8 ай бұрын

Please ask a question that makes sense

B will be syn or anti addition?

Nice one

In G 14:10 will there be no formation of hexane ?

@nathanneu6107

Жыл бұрын

a little late, but yeah a hexane would form from rearrangement good catch lol

@ShamithPrasad25

2 ай бұрын

no cuz cyclohexane is less stable than cyclopentane if there was cyclohexane with a cation then yes with rearrangement it would turn into cyclopentane

Roci or racimic i can't see d handwriting

For B, wouldn't it also be racemic?

@Yourmom34577

Жыл бұрын

that's what I thought,

@nastasiamijucic6791

Жыл бұрын

I don't think that the C with the OH and CH3 is a stereocenter, It Is only attached to 3 different groups not 4.

@nathanneu6107

Жыл бұрын

@@nastasiamijucic6791 that was my thought also