Wind load - Internal and external pressure coefficients
This video explains how to determine pressure coefficients for the design of buildings for wind loads. Internal and external pressures are considered, although with various clauses in SANS 10160-3.
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Produced for the SD424 Structural Design course.
Copyright Stellenbosch University.
Пікірлер: 41
One of the best videos explaining wind loads and pressures for a student doing a design course... Keep up the great work!!!
@richard_walls
2 жыл бұрын
Glad you enjoyed it.
Thank you so much for the explanation! Everything is so clear!
Thanks very much for the knowledge! your efforts are really appreciated.
Thanks a bunch! This pretty much matches up with the Eurocode procedures as well.
Very useful and clear video. You're the best!
Thank you so much, this is the best explanation by far I have seen on youtube
Fantastic tutorials! Thanks
Thank you for the video. Well explained.
Thank you so much. I like the way you explain
Superb method of Explanation... thank you so much
Thank you very much. It was very informative and helpful.
Wowwww🤩 so clear explaining thank you so much
Thanks alot for the video. Very informative
Thank you your the lecture
Awesome thanks so much.
Thanks for the video. If you were to consider a case where doors are all shut. Do you assume all internal pressure coefficients to be 0?
Superb
Great video, what if there are no walls on all the sides of the building? Just the roof, more like a carport design?
Great presentation, Richard. I have a question what will change if we design an unroofed building?
@richard_walls
2 жыл бұрын
If you have no roof then you just have walls. You will design that based on wall pressured coefficients most probably, depending on the arrangement of the walls.
On behalf of all UJ 3rd Year BEng Civil Eng students, thank you!
@richard_walls
4 ай бұрын
Thanks Prof. Glad it is useful to them.
100 OF 100
Hello, what is the internal pressure coefficient for a frame without a wall, thank you
Hello, Prof I don't know if that might be a stupid question. From what you have explained we have considered the doors on the dominant wall open, how would we design if the doors are closed? Will the pressure just be the external pressure then? Don't know if my question is quite clear.
@richard_walls
Жыл бұрын
Dear Melisa. When the doors are closed they are ignored and the internal pressures treated with either (a) calculating cpi based on the windows that are open (if you know where they are, or (b) taking cpi as the more onerous (worst case) or +0.2 and -0.3. The latter is a simple approach when there are various small openings and no specific dominant areas. In complicated buildings this often applies.
I'm trying to design a 300 sq ft building and wanted to know the structural components for 250mph, 300mph and 350 mph wind loads. Is this something difficult to do or is there a software that can easily adjust the components to support the different loads?Thank you
@richard_walls
Ай бұрын
You will need a structural design for that based on the geometry of the building. There are no quick tables for such member sizing. Also those wind speeds are insane.
Is this video using eurocode 1 ? If yes what about an asymmetrical roof ?
@richard_walls
Ай бұрын
@@omarjamoussi6388 it uses SANS 10160. However, for a mono symmetric roof there are good guidelines in both codes. For a asymmetric roof you will need engineering judgement or a CFD analysis or wind tunnel test
How to calculate wind pressure downward and uplift open carport structure like cantilever
@richard_walls
6 ай бұрын
Each wind loading code has a section on canopy roofs. They provide pressure coefficients to suit. The pressure is a function of the blocking factor. You also need to apply the load eccentrically in some cases to account for uneven pressure distributions.
What if no dominant opening will occur during periods of high wind?
@richard_walls
9 ай бұрын
Guidance is provided in the code. For example, for a airplane hangar where the doors will be closed during storms that may not be considered at ULS. However, it should then be considered as an accidental case because it could happen, but some damage may be permitted.
@denorshabuchanan-willock5592
9 ай бұрын
I have be looking through the code however i am unsure if i need to use the figure Figure 7.13 Table or that cpi can be taken as the more onerous of +0.2 and -0.3. Because in my case with a portal frame, i am assuming that our structure has no dominant opening. What would be best ? @@richard_walls
@denorshabuchanan-willock5592
9 ай бұрын
Also, Thank you for responding so promptly, i appreciate it.
Master peaceless Dots
How does the internal pressure behave when there are no opening inside? i'm assuming internal pressure will cause a constant suction inside when wind is applied externally.
@richard_walls
10 ай бұрын
There are always done small openings around a structure. Simplified guidelines of -0.3 or +0.2 cover such a case to approximate details when you're not quite sure what the internal pressure is.