The Six Trigonometric Ratios - Trigonometry
@MathTeacherGon will demonstrate knowledge about the definition of trigonometry and the six trigonometric ratios. Also, he will try to find the six trigonometric ratios given a right trianlge.
The Six Trigonometric Ratios of Right Triangle
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Law of Sines (Sine Law) - Solving Problems Involving Oblique Triangles
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#trigonometry
#sixtrigonometricratios
#trigoratios
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#cosine
#tangent
Пікірлер: 142
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle.
@sherraineclarite9344
3 жыл бұрын
Given right triangle ABC, as you right triangle. Side a=6, b=8 and c= 10 Find the six trigonometric ratios of the given right triangle sin∅ = 6/10 cos∅ = 8/10 tan∅ = 6/8 csc∅ = 5/3 sec∅ = 5/4 cot∅ = 4/3
@aignerlouis
3 жыл бұрын
Given right triangle ABC, C as your right triangle. Side a= 6, b= 8, and c= 10. Find the six trigonometric ratios of the given right triangle. sin= 3/5 cos= 4/5 tan= 3/4 csc= 5/3 sec= 5/4 cot= 4/3
@beaaraojo2893
3 жыл бұрын
Given right triangle ABC, C as your right triangls. Side A = 6 ; Side B = 8 ; Side C = 10 • A N S W E R S • sinθ = 3/5 cosθ = 4/5 tanθ = 3/4 cscθ = 5/3 secθ = 5/4 cotθ = 4/3
@Celery_da_Gulay
3 жыл бұрын
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. Sin= 6/10 or 3/5 Cos=8/10 or 4/5 Tan=6/8 or 3/4 Csc=10/6 or 5/3 Sec=10/8 or 5/4 Cot=8/6 or 4/3
@alelimaylapira9400
3 жыл бұрын
Given right triangle ABC , C as your right triangle. Side a=6 , b=8 and c=10. Find the six trigonometric ratios of the given right triangle. sin = 3/5 cos = 4/5 tan = 3/4 csc = 5/3 sec = 5/4 cot = 4/3
Thanks sir, im getting sick of modules that are giving confusing and unsimplified information.
@MathTeacherGon
3 жыл бұрын
Oww ..btw welcome .
@anxiety5413
2 жыл бұрын
Right? Me too
Helpful Sir! As always
Thank you Sir!
Thanks sir this was interesting session 👍
U r so a great teacher tnx
Yeyyy thanks a lot sirrr
Thank u and good sir
Thank you po sir❤.
Thank you so much, sir!
@MathTeacherGon
Жыл бұрын
welcome po
THANK YOU SIR IT REALLY HELPS ME ALOT!!💕💕
@MathTeacherGon
3 жыл бұрын
Welcome po...😊😊😊
thank you so much Sir!
@MathTeacherGon
3 жыл бұрын
Welcome po...❤️
thank you sir!
@MathTeacherGon
3 жыл бұрын
Welcome po...
thank you so much sir!!!!
@MathTeacherGon
2 жыл бұрын
Oww... Welcome...😊😊❤️🇵🇭
salamat po sir👍
thank you so much po magagamit ko to sa exam bukas
Thank you, Teacher Gon! Marami akong natutuhan dahil po sayo.
@MathTeacherGon
2 жыл бұрын
Welcome.. please share this video to your friends.
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sinθ = 6/10 or 3/5 cscθ = 5/3 cosθ = 8/10 or 4/5 secθ = 5/4 tanθ = 6/8 or 3/4 cotθ = 4/3 Thank you po sir! 💕
Salamat po
Thank you so much po, sir Gonzaga!!
@MathTeacherGon
2 жыл бұрын
whooa... welcome...😊
Thankyou so much sir
@MathTeacherGon
3 жыл бұрын
Welcome po...
Finally thank you po sir, hindi na po ako mahirapan sa math
@MathTeacherGon
2 жыл бұрын
welcome po. keep on learning
Thanks po!
@MathTeacherGon
3 жыл бұрын
Thank you din po..
thank u po sir
Thanks sir. You are good at explaining it and I can understand it so easily keep up the good work Sir 👍👏
@MathTeacherGon
2 жыл бұрын
wow..thank you
@kimxx885
2 жыл бұрын
@@MathTeacherGon Apply trigonometric ratios To solve right triangle given the length of the hypotenuse and the length of only one leg. Meron kapo bang topic neto sir?
Thank you a lot
@MathTeacherGon
3 жыл бұрын
Welcome...😊😊😊❤️
@kamosmith_
3 жыл бұрын
@@MathTeacherGon if the question states figure x and y on a triangle and support the answer with Pythagoras... Then it also states Hence Sin= Cos= Tan= Cosec= Sec= Cot= Do I still apply the same knowledge I'm getting from this video? 💯Trigonometry is interesting
Thankyou so much sir
@MathTeacherGon
3 жыл бұрын
Welcome
Done watching. Thank you po, Sir! (Galileo)
thank you po sir!
@MathTeacherGon
3 жыл бұрын
Welcome Yra...
Side A= 6, B= 8, and C= 10 sinØ = 6/10 sinØ = 3/5 cosØ = 8/10 cosØ = 4/5 tanØ = 10/8 tanØ = 5/4 cscØ = 10/6 cscØ = 5/3 secØ = 10/8 secØ = 5/4 cotØ = 8/6 cotØ = 4/3
Thank u po sir!
@MathTeacherGon
3 жыл бұрын
Welcome 😊😊😊
Thank you po sir! ^^ sin θ = 6/10 cos θ = 8/10 tan θ = 6/8 csc θ = 10/6 sec θ = 10/8 cot θ = 8/6
Thank you po
@MathTeacherGon
3 жыл бұрын
Welcome po...😊
how to identify the different sides of the right triangle without reference angle
thank you po sir godbless po💜
@MathTeacherGon
3 жыл бұрын
Welcome po…
Thank you po sir
@MathTeacherGon
3 жыл бұрын
Welcome po..
Hello, sir. Thank you for this tutorial, btw may Correction lang po, baliktad po ang COSECANT ( 5:50 ). It should be hypotenuse/opposite since reciprocal siya ng SINE.
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sine∅ = 6/10 cosine∅ = 8/10 tangent∅ = 6/8 cosecant∅ = 10/6 secant∅ = 10/8 cotangent∅ = 8/6 simplified: sine∅ = 3/5 cosine∅ = 4/5 tangent∅ = 3/4 cosecant∅ = 5/3 secant∅ = 5/4 cotangent∅ = 4/3 thank you po sir.
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. sinθ = 6/10 or 3/5 cosθ = 8/10 or 4/5 tanθ = 6/8 or 3/4 cscθ = 10/6 or 5/3 secθ = 10/8 or 5/4 cotθ = 8/6 or 4/3
Given right triangle ABC, C as your right triangle. Side a = 6, b = 8 and c = 10. Find the six trigonometric ratios of the given right triangle. sinθ = 3/5 cosθ = 4/5 tanθ = 3/4 cscθ = 5/3 secθ = 5/4 cotθ = 4/3
sir what if ang given is cot and u have to solve for the other 5?
Sin∅=3/5 Csc∅=5/3 Cos∅=4/5 Sec∅=5/4 Tan∅=3/4 Cot∅=4/3 Thank you po sir
Sir thank you po Answer ko po Sine=6/10 Cosine=8/10 Tangent=6/8 Cosecant=10/6 Secant=10/8 Contangent=8/6
@MathTeacherGon
3 жыл бұрын
Thank you Louie
and how about po sa example yung opp. and hyp. ay may . exm. 1.4 like ganun po same po sa isang triangle may dalawa or isang may . i cocompute po ba yun?
Thank God, finally i understand something in math 😂
@MathTeacherGon
2 жыл бұрын
wow..thanks for the appreciation...😊🤗
sir ask q lng po wat if may degrees na nasa loob po ng triangle sa magkabilang dulo po yung sa taas an sa baba ng right pero may no. lang po sa labas like this in ur example...i cocompute pa po ba yun?
thank you...how can I go about solving an equestion where theta greater or equal to360°
@nicolegracedg.corpuz6295
3 жыл бұрын
As for my understanding there couldn't be a theta or angle that is greater than or equal to 360° because a triangle is only equivalent to 180°
@Dellia_valerie
2 жыл бұрын
For example meron kang given angle na 390°, same lang sya ng 30° 390°-360°=30°
I love you sir
@MathTeacherGon
Жыл бұрын
thankkkk you for the love ..
Thank you, Sir! (Galileo) ♡♡♡
@MathTeacherGon
2 жыл бұрын
wow..nanuod..😊
Sin ø =3/5. Csc ø =5/3 = 1 2/3 Cos ø =4/5 Sec ø =5/4 = 1 1/4 Tan ø =3/4. Cot ø =4/3 = 1 1/3 Hello Sir, ngayon ku lang tlga naintindhan po lahat. Pa correct po kung tama po ba sagot ko lalo na Csc ø, Sec ø & Cot ø? Wait ko po sir para macorrect ko po. LET Takers po ako this coming March 2023. Thank you so much Sir :)
Hello po sir. Di po ba dapat baliktad yung ratio ng cosecant? Hyp/opp dapat?
@MathTeacherGon
3 жыл бұрын
Opo yun po ang correction dyan..
Sir paano po kapag adjacent ang hinahanap if hypotenuse lang ang meron?
I don't got it 😶
Paano ba kunin ang angle
Pno po ung basic concepts and terms
Sir, the ratio of cosecant theta is hypotenuse/opposite....... But you wrote riverse 😅
Mag PowerPoint presentation ka po sana para mas makita po ng maayos :)
Paano makuha hypotenuse and adjacent my 35 opposite kasi Ako and teta 30°
is the cosecant really still opp./hypo. or is it hypo./opp.?
@MathTeacherGon
3 жыл бұрын
Sorry thats an error.. hyp/opp..
@dealwithit5248
3 жыл бұрын
oh i see, thank you sir :DD
sir gon, baliktad po dapat ung sa cosecant. correct me if im wrong po. god bless!
paano po kunin ung sin 20°?
Answer kopo sinθ = 6/10 cosθ = 8/10 tanθ = 6/8 cscθ = 10/6 secθ = 10/8 cotθ = 8/6
@MathTeacherGon
3 жыл бұрын
Lowest term mo ito nak.
@josaiahmendoza1887
3 жыл бұрын
3/5 4/5 3/4 5/3 5/4 4/3 Eto po sir
hi po sir, paano po kung given yung cos A = 12/13 tas find the six trigonometric functions of B daw po. Yung value po ba ng adjacent is 12 at hypotenuse ay 13? Need pa po ba hanapin yung value ng Opposite side to answer angle B 😄
@MathTeacherGon
3 жыл бұрын
Yes po.. you need to find the hypotenuse para maging cosB
Sir Sana sa susunod Tagalog nalang hehe
@MathTeacherGon
3 жыл бұрын
Okie dokie... Halos lahat po ng videos natin ganun..
Hi guyz, pwede ko bang malaman kung saang school kayo nagaaral.😊
@studycorner7924
3 жыл бұрын
Hello sir!
@victorytchannel9040
3 жыл бұрын
Visayas State University sir♥️
@itsjuswahsckrs
3 жыл бұрын
Apec schools
@victorytchannel9040
3 жыл бұрын
@@itsjuswahsckrs anong course kinuha mo buddy?
@itsjuswahsckrs
3 жыл бұрын
Grade 11 palang po ako ngayon pasukan pero lilipat nako hehe
Done po
@MathTeacherGon
3 жыл бұрын
Welcome po
CHO or COH? Alin po yung tama?
@fafary7820
2 жыл бұрын
Ayon pinalitan na,okay na po
@MathTeacherGon
2 жыл бұрын
CHO.typographical error
exam tom sana maka 40+/50 D:
@MathTeacherGon
3 жыл бұрын
Keep it up.
@pheo1299
3 жыл бұрын
@@MathTeacherGon good news sir 48/50
@MathTeacherGon
3 жыл бұрын
@@pheo1299 WOW CONGRATS
Sin ø =6/10. Csc ø =5/3 Cos ø =8/10. Sec ø =5/4 Tan ø =6/10. Cot ø =4/3 Thank you po sir 😁
Sir pede nyo po ba gawin yung katulad ng first triangle then yung adjacent po may number and yung sa part po na may symbol na theta may degree tapos hahanapin po yung a.
@MathTeacherGon
3 жыл бұрын
Sige po gagawa po ako bukas tutukan mo po sa channel ko po
@trxiem9200
3 жыл бұрын
Thankyouu sirr aabangan ko po yann✋
@MathTeacherGon
3 жыл бұрын
Pero try mo n din yung videos sa playlist ko...ng Trigonometry baka nandun din hinahanap mo po
@trxiem9200
3 жыл бұрын
Yes sir pero yan po kase last item nahihirapan po ako,pero thankyou den po dahil nasagutan ko yung mga naunang item dahil din sa mga vids mo po❤️
@trxiem9200
3 жыл бұрын
I'm still waiting sir😭
ang cosecant po sir baliktad po
thank you po sine∅ = 6/10 cosine∅ = 8/10 tangent∅ = 6/8 cosecant∅ = 10/6 secant∅ = 10/8 cotangent∅ = 8/6 simplified: sine∅ = 3/5 cosine∅ = 4/5 tangent∅ = 3/4 cosecant∅ = 5/3 secant∅ = 5/4 cotangent∅ = 4/3
Thank you po sir❤
@MathTeacherGon
3 жыл бұрын
Welcome cherry.
Thank you po sir
@MathTeacherGon
3 жыл бұрын
Welcome po
Done po
@MathTeacherGon
3 жыл бұрын
Welcome po.
Thank you po sir
@MathTeacherGon
3 жыл бұрын
Wow..welcome po..