Thailand Math Olympiad | A Nice Algebra Challenge
Thailand Math Olympiad | A Nice Algebra Challenge
Welcome to another exciting math challenge! In this video, we'll tackle a fascinating algebra problem from the Thailand Math Olympiad. If you love solving complex equations and pushing your problem-solving skills to the limit, this is the perfect challenge for you. Join me as we work through this intricate algebra problem step-by-step. Don't forget to like, comment, and subscribe for more math challenges and solutions!
🔍 In this video:
Detailed walkthrough of a challenging algebra problem from the Thailand Math Olympiad.
Tips and tricks for solving complex algebraic equations.
Encouragement to enhance your problem-solving skills and mathematical thinking.
📌 About the Thailand Math Olympiad:
The Thailand Math Olympiad is renowned for its tough and creative problems, designed to test the limits of young mathematicians. Competing at this level requires dedication, practice, and a deep understanding of mathematical concepts.
📣 Call to Action:
Have a go at the problem yourself before watching the solution!
Share your solutions and approaches in the comments below.
If you enjoyed this challenge, give it a thumbs up and subscribe for more intriguing math problems!
Time-stamps:
0:00 Introduction
1:55 Simplifying Expression
5:25 Rationalization
7:55 Algebraic identities
11:45 Evaluating expression
13:55 Answer
🔗 Useful Links:
• Chinese | Math Olympia...
• A Nice Simplification ...
• A Nice Algebra Problem...
• A Nice Simplification ...
#matholympiad #thailand #algebra #math #algebratricks #education #problemsolving #mathematics #expression #simplification
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Thank You for Watching!!
Пікірлер: 14
Beautiful
After you derive x=(-1+sqrt(13))/6 I think it is much faster to just multiply it out and show x^2=x*x=(7-sqrt(13))/18, x^3=x*x^2=(-5+2*sqrt(13))/27, x^6=x^3*x^3=(77-20*sqrt(13))/27^2
Threw me for a sec. It looked like 272 but you meant 27^2.
Beautiful problem. I loved and enjoyed doing it.
X^6= (77- 20√13)/729
X⁶=(77-20√13)/729
Let sqrt(7)=a and sqrt(13)=b. Then, x=[a+1+a+b]/(a+1)(a+b) = 1/(a+b+ + 1/(a+1) = (sqrt(13)-1)/6. So, x^6= [4928 -1280sqrt(13)]/6^6 = [77-20sqrt(13)]/729.
Marathon problem! Nice choice and nicely solved - even though the final result isn't so pretty! Thank you.
@infyGyan
23 күн бұрын
Thanks for watching.
(x ➖ 1x+1) 1 +2^31+1 1 13^1/2^7 +3^31+1 1^1^1 1^1 /1^1 1^1^1 1^1 (x ➖ 1x+1) x^3^2 (x ➖ 3x+2)
10:20 Четыре слагаемых, в следующей записи три Куда то исчезло 3х^2, оно было последнее , и его не заменили на 1-х, а просто убрали неизвестно как
@ludmilaivanova1603
26 күн бұрын
он суммировал 3x^2 и x^3 и "сделал произведение х^2 (3-х) .
[77-20(ριζα13)]/729
(x ➖ 1x+1) 1 +3^31+ 1 1+ 1 13^1/2^7 3^31 1 1^1^1 1^1/2^1 1^1^1 1^1/2^1 2^1 (x ➖ 2x+1 ) x^3^2 (x ➖ 3x+2)