Solving a Tricky Exponential Equation | Math Olympiad Challenge

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Join us as we tackle a tricky exponential equation from the Math Olympiad! In this video, we break down the problem, explore different approaches, and guide you through the step-by-step solution. Perfect for students preparing for math competitions, educators looking for challenging problems, or math enthusiasts eager to learn more. Don't forget to like, share, and subscribe for more exciting math challenges and solutions!
Topics covered:
Exponential equations
How to solve exponential equations?
Algebra
Properties of exponents
Algebraic identities
Synthetic division
Rational root theorem
Exponential Equation
Math Olympiad preparation
Math Olympiad training
Exponent laws
Solving cubic equation
Quadratic equation
Discriminant
Complex solutions
Real solutions
Timestamps:
0:00 Introduction
0:30 Properties of exponents
2:12 Algebraic manipulations
4:40 Solving Exponential equation
5:48 Substitution
8:23 Solving cubic equation
11:42 Quadratic equation
13:15 Solution
13:25 Verification
#matholympiad #exponentialequations #mathchallenge #problemsolving #mathcompetition #mathtutorial #olympiadmathematics #mathematics #learnmaths #mathenthusiast
#algebra
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Пікірлер: 6

  • @mohammedsaysrashid3587
    @mohammedsaysrashid3587Ай бұрын

    A wonderful introduction.👌.....x=-2 is a real solution

  • @user-kp2rd5qv8g
    @user-kp2rd5qv8gАй бұрын

    Let a = 2^(2x+4). Then, the given equation is written as a^3+2a^2=3. This has a=1 as the only real solution. So, 2x+4=0 > x = -2.

  • @tunneloflight

    @tunneloflight

    Ай бұрын

    multiplicity 2 for each

  • @roberttelarket4934
    @roberttelarket4934Ай бұрын

    (8^t, 4^t, 2^t) > 0. If integers: 1 + 1 + 4 = 6. x = -2 does the trick. May be other roots.

  • @StaR-uw3dc
    @StaR-uw3dcАй бұрын

    x=-2