How is that result simpler than the original? Simplest form technically would be ²(1/9) but without using tetration, surely the simplest form would be 3^(-2/9).

@nguyentienquangntq

7 күн бұрын

Right!

Simply you are wasting the time by repenting the trivial steps.

@superacademy247

21 күн бұрын

Ultimate way of teaching indices in one video

Unnecessary lengthy

This is a call nay an appeal to all maths teachers. Please make your presentations shorter , avoid repetition. Your primary responsibilty , if I am not mistaken, is to make maths simpler and attractive . But many times I am forced to move away from many of the posts . A five minute presentation takes half an hour !

@nagarajahshiremagalore226

21 күн бұрын

Yes, I fully agree with your comments.

@reyb925

12 күн бұрын

At the end we dont know what the answer is. We gained no new knowledge of these manipulations, and we could have left it was it was at the beginning.

@user-nc2ts9wi2d

3 күн бұрын

Чем полученный ответ, лучше условия?

Так мало того, сама по себе задача крайне глупая.

solving very bad..to long...

Похоже, чуваку просто нравится пером по бумаге водить))) Продемонстрировал фантастическое владение степенями!

If it is a question of Math Olympiad then everyone would succeed in that exam....even myself.

Chłopie, ty to skomplikowałeś, a nie uprościłeś !... przez logarytm o podstawie 3 szybko wychodzi 3^(-2/9)

There is a faster and less tedious method

You win a Fields Medal for tedium.

@superacademy247

12 күн бұрын

You make me feel like laugh 🤣. Thanks for your support and input though

Имею плохую привычку. Начав что то смотреть, досматриваю до конца, а потомстрадаю от потерянного времени.

What is exactly the scholar level of students who have to solve this ? This solution is too long and if a student had to solve this during math Olympics, this would be a waste of time !!!😮

I have never seen such inefficiency.

@superacademy247

8 күн бұрын

It's Laws of Indices crash course

Herr professor, if your friend did this sea of ​​calculations and is going to give a value that needs to be calculated using a log or calculator, wouldn't it be much simpler to use the following scheme: 1) (1/9)^(1/9) = X 2) I raise both sides to the power 9 1/9 = X^9 0.111111 = X^9 X = ninth root of 0.1111111111 It will give the same value as yours, calculated, 0.78338 Hugs!

@superacademy247

12 күн бұрын

You didn't follow instructions: Calculators are NOT allowed! Thanks though for your support and input

@JPTaquari

11 күн бұрын

Dear Professor, your friend must have a (serious) cognitive problem, as he did not understand my solution. I followed the rules established for the Math Olympiad strictly. Here in Brazil there is a rule that says 'mathematics is always the simplest'. I'm sorry for your difficulty in developing about ten pages of paper to arrive at my result in three lines. X = SR of o.1111111 I could stop here, but, using a calculator, I calculated the root to make sure it matched the complex solution. I'm leaving your channel. Unpleasant!

@tomctutor

9 күн бұрын

@@JPTaquari Difference between an EXACT solution and a numerical approximate solution, OK in Engineering but not pure maths, To be pedantic, 1/9 =/= 0.1111.. (Come back and you will be forgiven).

@JPTaquari

9 күн бұрын

My dear, you must have some cognitive problem. Go treat yourself, man! Come back and see my development!

Super Academy,   A bit tedious process... (   Maybe the result here is a bit easier:     (1/9)^(1/9) = 1 / 9^(1/9) = 3^(-2/9) = 1/3 * 3^(7/9) = 1/3 * (3^7)^(1/9) = 1/3 * 3^(6/9) * 3^(1/9) = 1/3 * 3^(2/3) * 3^(1/9) = 1/3 * cbrt(9) * root(3; 9).     Here root(a; b) means a^(1/b) for a∊ℝ, b∊ℕ,     and cbrt(x) is a cube root of x∊ℝ.      What is the meaning of simplification in this case? I'm from Russia, and in our high school we have no strict rules for the result of simplification.

This answer we may get in one row by multiplying 1/9 by 3^7. Then we obtain (3^7 / 3^9)^9

Only ((3)^-2)^(1/9)=3^(-2/9)

@superacademy247

11 күн бұрын

When the index is negative you've not simplified. Make the exponent positive

He Teacher juan is best

3^7/9x3^(-9/9)=3^(-2/9)

Alcuni passaggi ripetuti e inutili sopratutto!

(3^(-2))^1/9=3^(-2/9)=3^(7/9)/3 much shorter

НУ И РЕШЕНИЕ?! ОЧЕНЬ ГЛУПО!

10:42 still continue to monitor

@superacademy247

8 күн бұрын

Absolute crash course

ans : 1/[3^(2/9)]

(1/9)^1/9 = 3^(-2/9) < make it simple in less than 60 sec!

@superacademy247

4 күн бұрын

I'll make a KZread short of the same video

От степени 1/9 так и не избавился)))))))

It's a litle bit complicated.

Ugh, this was hard to swallow! Slow mathematics (credits for this), just to get a result, that doesn't simplify, while the real solution doesn't need any calculation ( 1 / 3^(2/9) or 1 / 9rt(3²) ). To get close to the decimal result (0.78338103693727233...), I've tried some (2) manual Newton steps with a bad, but easy to calculate, starting value (1): N(x) = 7/9 x + 2/(27x^3.5) N(1) = 7/9 + 2/27 = 23/27 x = 23/27 = 851/999 = 0._851_ is still far away, so let us take a second step with some approximations: We need to calculate 7/9 * 23/27 + 2/(27 (23/27)^3.5) = 161/243 + 2/(27 x^3.5). Our greatest problem for manual calculation is this x^3.5. But we know, that x^4.5 = sqrt(x^9) ahould greater than the solution for (1/9)^(1/9), 1/3, let's say 1/2 (just a guess!). What we need, is x^3.5 = x^(7/2) approx.= (1/2) / x = 27/46. => 2/(27 x^3.5) approx.= (2*46)/(27*27) = (92/3)/243. Thus: N(23/27) approx.= 161/243 + (30 2/3) / 243 approx.= 161/243 + 30/243 = 191/243. (I've rounded down, because we expect to overshoot). This value of x_2 = 191/243 approx.= 0.786008 is a pretty good (rational) approximation...

@rainerzufall42

10 күн бұрын

LOL, just put in into Wolfram Alpha, it's even better than the real N(23/27) = 0.7923865... But this is a good approximation as well!

@rainerzufall42

10 күн бұрын

Okay, half of it was the correction, that I've made through rounding: N(23/27) approx.= (191 2/3)/243 = 0.7887517...

Un poco más y me duermo

It took a long period of time to solve the simple equation,you just make us confused about your simple, topic, what a good teacher. You deserved no subcriber indeed.😀😀😀

@superacademy247

8 күн бұрын

Glad it helped!

Tenightrootovnine 😂

wowww

making something out of nothing ! 9 is simply 3^2 so the question becomes 3^(-2/9) which can be written with rational denominator if desired by putting (7/9 - 1 ) instead of (2/9). olympiad? ha!

@superacademy247

9 күн бұрын

Do it here! Olympiads want to see action.

@festinbulbus

9 күн бұрын

@@superacademy247 whatever that means...?

You kill the soul of maths that is time

😮

(9)⁹ ans

wowwww

@superacademy247

20 күн бұрын

Thanks 😊

Is this an eye exam?

@ndjibukabengele973

12 күн бұрын

😂😂😂

Stöpslerei!

Where are you from bro?

@superacademy247

13 күн бұрын

I'm from Kenya

Why r u creating controversy 😮😮

400 par ka ganit nahin samajh me aa raha

Почему не показал как из 3^7 получил 2187?

@superacademy247

11 күн бұрын

3^7=3x 3x 3x 3x 3x 3x 3=2187 Straight forward

@user-cd9om1qu2n

10 күн бұрын

@@superacademy247 Это был сарказм.

@superacademy247

10 күн бұрын

Okay 👍

You are taking all the roads to complicate rather than simplfying. It takes only two steps to simplfy it.

@superacademy247

10 күн бұрын

Show us the steps!

@Ali-yr7ep

8 күн бұрын

@@superacademy247 Simply (1/9)^(1/9) = (1/3^2)^(1/9) = 3^(-2/9) = 3^(-(9-7)/9) = 3^(7/9). 3^(-9/9) =(⁹√3⁷)/3 = (⁹√2187)/3

@Ali-yr7ep

8 күн бұрын

this is from @tomctutor

😮 demasiados pasos redundantes, este ejercicio es para hacerlo más corto....esto fue muy latero

@superacademy247

10 күн бұрын

It's precision guided method to a perfect solution

1/3

So long Only three steps solution like

I am disagree. Answer is 1/3^(2/9) or 1/ 9√9

@superacademy247

6 күн бұрын

But you should rationalize the denominator to achieve complete simplification

Simply (1/9)^(1/9) = (1/3^2)^(1/9) = 3^(-2/9) = 3^(-(9-7)/9) = 3^(7/9). 3^(-9/9) =(⁹√3⁷)/3 = (⁹√2187)/3

A7A

I understand that the idea is to show how to use the different properties of powers. That's Ok. But I mean you rodount too much. I might say you show a way how to complicate something simple. Anyway, who teaches, learns.

It is not fair It is a joke You are sure, it is good math ?

I feel bad for your students if you're a teacher 😂😂😂 why don't you make it easier and simple . for such easy question 😢

@superacademy247

8 күн бұрын

This is a crash course. One question teaches all indices properties

@raymondiradukunda75

8 күн бұрын

@@superacademy247 thanks

@superacademy247

5 күн бұрын

Welcome

Is also wrong... The correct result is 0.00000000258 while this gives out 0.783381...

@superacademy247

19 күн бұрын

Go through it over and over again

Unnecessarily a mental fellow

Oi!

El final es de pena

Boring démonstration and too complicate

좀 어리석은 풀이다

Правильнее назвать это видео "усложни", а не "упрости".🤭Степень девятки 2/9≈1/3, т. е. искать надо значение, близкое к ³√3.

@superacademy247

Күн бұрын

You're required to rationalize the denominator

@zawatsky

Күн бұрын

@@superacademy247 и в чём смысл? Я не могу точно посчитать без калькулятора ⁹√9, такое огромное число - тем более. %)

@superacademy247

Күн бұрын

But you have seen how I smartly simplified the denominator?

@zawatsky

Күн бұрын

@@superacademy247 что это даёт? Вы можете ловко жонглировать апельсинами, это будет означать лишь что вы играетесь с едой - не более...

Don't wrote the same expression twice...You bore me with that..

Repite...repite y repite las igualdades.!! Interminable !

@superacademy247

Күн бұрын

To emphasis

(1/9) ^(1/9) = (9)√(1/9) = (9)√0.111111...

@tomctutor

9 күн бұрын

Sorry wrong 1/9 =/= 0.1111.. does not matter how many 1's you stick on

Зачем это все?

@superacademy247

12 күн бұрын

In the name of Math competition 😄

@sergenjamkepo6467

11 күн бұрын

​@@superacademy247 Ok😀 it' a joke

oh no, it only got worse

@superacademy247

8 күн бұрын

Laws of Indices 101

Quanta complicação!!

STOP WRITING 9 LIKE q!!!

Muchal kak koshka mishku

@superacademy247

7 күн бұрын

Unfortunately Google translate has failed on your comment

Что-то очень длинное и ни к чему хорошему не приведшее.

@superacademy247

8 күн бұрын

It ended rationalizing the denominator. You see the denominator is now beautiful and readable

This is not a solution! 🤕

@superacademy247

4 күн бұрын

It's because the denominator is successfully made rational

What a terrible approach ... You should start by stating what “simplify” mean - radical on top, and the smallest integer on the bottom. This is the objective. This objective leads to the next logical question - what should we multiply top and bottom by, to get rid of the radical at the bottom? What we have at the bottom is 9^(1/9) which is the same as (3^2)^(1/9). And what want to see instead is (3^9)^(1/9) because it simplifies to 3. Since 9=2+7, all we need is multiply the top and bottom by (3^7)^(1/9): 1 / (9^(1/9) = (3^7)^(1/9) / ( (3^2)^(1/9) * (3^7)^(1/9) ) = (3^7)^(1/9) / (3^9)^(1/9) = (3^7)^(1/9) / 3 This is it. By clear reasoning you arrive to the plan and to the answer IMMEDIATELY, in couple of minutes. Instead of going through seemingly random transformations for 13 minutes, with no clear sense of purpose, arriving to the final answer what seems almost by accident. You give your students no help in solving similar problems on their own. Thanks god I had great math teachers who taught me - before taking a pen and starting to write - think first, state your objective, articulate the plan, and only then start writing.

@superacademy247

8 күн бұрын

I like your last paragraph. Where do you come from?

@vadim64841

8 күн бұрын

@@superacademy247former USSR. It was our high school math teacher.

@superacademy247

5 күн бұрын

Thanks 👍💯 . I read about USSR in history books in high school

To much exaggerated and complicated

@superacademy247

10 күн бұрын

Indices 101

Бред

You are half mad...

вялотекущая шизофрения....

Very poor method..

@superacademy247

5 күн бұрын

Why do you think so?

Too much repetition

@superacademy247

4 күн бұрын

To emphasis

Painful to watch.

@superacademy247

8 күн бұрын

This is a crash course

Yours is no good process, I think.

@superacademy247

10 күн бұрын

It's because that's the result required. Military grade method

Very botingand is very boring

This is a complete waste of time

@superacademy247

4 күн бұрын

Give us a formula of rationalizing the denominator without waste of time

Sehr witzig??????

@superacademy247

15 күн бұрын

Funny and beautiful. Thanks 👍💯 for your support

USELESS

Are you that desperate to make a youtube video that you would make one to waste everybody's time? C'mon man - get with the program.

Wasting my time.

@superacademy247

7 күн бұрын

It's Laws of Indices crash course

Very very poor maths teaching,every time रिपीटेशन ।it is frustrating and boring method।please don't allow this teacher in future।

I stopped watching this halfway through because i couldn't stand how slow he was going. You don't have to repeat every step. Its a video. If somebody can't follow then they can replay it til they can. Good god, man you're driving people away by your horrible presentation. Awful! And I like math.

Are you a mad???

@superacademy247

11 күн бұрын

nko na matata!

@timirbiswas3834

10 күн бұрын

No he is not a mad....but he is capable of driving all his students mad !!!

@superacademy247

10 күн бұрын

@@timirbiswas3834 Absolutely!

I Fell asleep because of your verboseness. 🥱