Here is another alternative way to solve it, maybe little easier. Let a = (29³ + 15³)/(29³ + 14³). Add -1 (minus 1) to both sides. So that (a - 1) = [(29³ + 15³)/(29³ + 14³)] - 1 = [(29³ + 15³) - (29³ + 14³)]/ (29³ + 14³) = (15³ - 14³)/(29³ + 14³) = [(15-14)(15² + (15)(14) + 14²)] / [(29+14)(29² - 29.14 + 14²)] = (15² + (15)(14) + 14²) / (43 (29² - 29.14 + 14²)) = (225 +210 +196)/(43. (841 - 406 +196)) = 631/(44.631) = 1/43. Therefore a = 1 + (1/43) = 44/43

Factorize the sums of cubics in numerator and denominator. Then you get the solution almost immediately.

Factorize the cubics in numerator and denominaor and you get the solution almost immediately (without substitutions)

Beautifully systematic evaluation technique

Thanks for sharing ❤

Good

Very nice. Thank you!

Can you explain it again using interpretive dance?

Я гораздо быстрее умножил всё в столбик))

It is for me an appraciated fresh-up. Much better than Sudoko. Can you please problems with derivate and integral solve. Some lim. problema too. Thank you.

@is7728

15 күн бұрын

Nice I want them too

Would you do the easy way

1.6