👍👍👍

Nice one. You are a good teacher.

@superacademy247

3 ай бұрын

Thank you! 😃

simple method: (x+1)^6 = 2^6 When the exponent is equal, the bases are equal x+1 = 2 and x+1 = -2 x = 1 and -3

@michaelhuppertz6738

Ай бұрын

This way you only get the real solutions only, you cannot get the complex solutions with this approach.

Thanks

@superacademy247

4 ай бұрын

Welcome

❤❤❤ thanks 💯💯💯

@superacademy247

4 ай бұрын

Welcome 😊

2^6=64 X+1=2 Rest is simpel

Let z = (x+1)/2. Then, z^6 = 1. So, z = e^(2 pi i n/6) = e^(i pi n/3), n = 0,1,2,3,4,5. So, z = 1, 1/2[ 1 + sqrt(3)i], 1/2[ -1 + sqrt(3)i], -1, - 1/2[ 1 + sqrt(3)i], 1/2[ 1 - sqrt(3)i]. Thus, x = 2z-1 = 1, sqrt(3) i, -2 + sqrt(3)i, -3, -2 - sqrt(3) i, -sqrt(3)i.