Check out the full explanation of Synthetic Division here! kzread.info/dash/bejne/eXl306eNgKe7ZKw.html

straightforward vid, thanks a lot, helped me save a litta time understanding synthetic division equations😅😅

@MathByThePixel

Жыл бұрын

Mission accomplished! Thanks for watching and commenting!

Thank you you just made my day by making synthetic division easy than long division

@MathByThePixel

Жыл бұрын

Amazing! Happy to help!

Thankyou

@MathByThePixel

Жыл бұрын

You’re welcome 😊

Thanks a lot saved my lot of timeee!!!

@MathByThePixel

Ай бұрын

That’s the goal!

Thanks you 😊 sir Love from Nepal 🇳🇵 You make it too easy

@MathByThePixel

Жыл бұрын

So happy to hear this! Thank you for the beautiful comment 💚

Thx a lot

@MathByThePixel

9 күн бұрын

Happy dividing!😎

Cheers for pointing me here, mate.

@MathByThePixel

7 ай бұрын

Happy to help! Have a blast!

Appreciate u🫶🏾

@MathByThePixel

Жыл бұрын

And I appreciate you!

Quick and easy.. Thanks!

@MathByThePixel

Жыл бұрын

Gotta love shorts!

Thank you

@MathByThePixel

4 ай бұрын

🤓👍

oh my god thank you so much

@MathByThePixel

Ай бұрын

Happy to help! Hope you enjoy this short cut!

Thank you, long division is a nightmare to deal with

@MathByThePixel

6 ай бұрын

Agreed! I avoid it at all costs!

@RayceVR

2 ай бұрын

@@MathByThePixelwhen are you not able to use it?

Thank u so much god bless you sir i was just fed up by doing it by long method❤

@MathByThePixel

7 ай бұрын

No problem! It’s always nice to save some time and steps!

At last I understood this thankyou👌👌

@MathByThePixel

2 жыл бұрын

This means everything to me! 🙏

so helpful this

@MathByThePixel

Жыл бұрын

It’s hard to go back to polynomial long division once you master this!

Your teaching is very nice 🙂☺️

@MathByThePixel

Жыл бұрын

Thank you! I hope it helps!

Tnqu brother🙇🥵

@MathByThePixel

Жыл бұрын

No problem! Happy dividing! 👌

Thanks

@MathByThePixel

Жыл бұрын

Hope it helps you avoid polynomial long division!

I'm the 1000th like ! +The video was really good, it helped me

@MathByThePixel

Жыл бұрын

I am so grateful! Blown away that 1000 people have liked this little video!

Nice method

@MathByThePixel

Жыл бұрын

Beats long division, doesn't it!

Thank you sir from india

@MathByThePixel

Жыл бұрын

I can't believe this little channel made it all the way to your beautiful country! 🙏

tq..😍

@MathByThePixel

8 ай бұрын

👍

Yea bro Thanks for the explanation😄 Love from India🇮🇳🇮🇳

@MathByThePixel

Жыл бұрын

Anytime! India is so kind :)

@madhavvashishtha8802

Жыл бұрын

@@MathByThePixel Well yes, everyone is kind here... Except the Maths teachers😅

@MathByThePixel

Жыл бұрын

Sounds like I need to move to India!

@madhavvashishtha8802

Жыл бұрын

@@MathByThePixel Yes sure! You are invited... We all are waiting for you(except the Maths teacher)😄

Can you create one for big ass numbers, 5 degrees, and the remainder is not 0?

Hey bro! You help me a lot but I want to ask you that are there drawbacks in synthetic division By the thanks ❤

@MathByThePixel

Жыл бұрын

Not really! I only use it when dividing by a linear binomial (ie. something of the form ax+b). If I am dividing by anything with a higher degree I always use long division. Hope this helps!

@krrishbeniwal22

Жыл бұрын

Thanks bro

@MathByThePixel

Жыл бұрын

Happy to help my guy

@krrishbeniwal22

Жыл бұрын

Love from India🇮🇳

@MathByThePixel

Жыл бұрын

So amazing! 🔥

Why -2

@MathByThePixel

21 күн бұрын

Using this strategy, whatever makes the binomial that you are dividing by equal to zero goes in the spot outside the L-bracket. Since we are dividing by x+2, -2 will make that zero. Therefore, we place -2 outside the bracket.

But whenever I imagine a value of x the answer is not matching to real one. Please answer 😢😢😢

@MathByThePixel

9 ай бұрын

What process are you using? Are you checking factors of the constant term? That’s your first step!

what if the 0 comes before the remainder. like what if in doing synthetic division and my second answer is a 0 instead of the last one (the remainder)

@MathByThePixel

8 ай бұрын

If I’m understanding you correctly, when you were working vertically, you found zero before you hit the remainder? That just means the coefficient on that term will be zero. If you have a specific example you can share I can record a short for you to explain better!

@ankitaroy7481

Ай бұрын

​@@MathByThePixel You are so good

Now I can finish my homework

@MathByThePixel

Жыл бұрын

Now you can CRUSH your homework!

Can the same be done for degree higher than 3

@MathByThePixel

Жыл бұрын

It can! It just takes longer :)

What if x + 2 is 2x + 5 or something how do we solvs it?

@MathByThePixel

Жыл бұрын

In cases like this, most people would choose to just stick with long division as it involves some fraction work. However, you can apply synthetic division in your example by dividing everything (including the original expression and the factor) by 2 to end up with a coefficient of 1 on x first. You could then proceed with x + 5/2 as your linear factor. Note that you will then have to multiply your remainder by the 2 that you divided out in the beginning. Hope this helps!!

@jalmascogabrielle3017

Жыл бұрын

@@MathByThePixel you made it even clearer!!! Thanks!!

@MathByThePixel

Жыл бұрын

Amazing! So glad to have helped!

How did u get the 2 at x²?

@MathByThePixel

7 ай бұрын

Since we started with a cubic (degree 3) and divided by a degree of 1, the result will be a trinomial with a degree of 2!

Bro listen I got a doubt, x²-x-4 ryt all the degrees are reduced and y doesnt 4 have an X Plz explain dude 😢😢😢😢😢

@MathByThePixel

8 ай бұрын

Think of the 4 as having an term of x^0 attached to it!

What if the divisor is -1/2?

@criziamaerosas6999

7 ай бұрын

can you do an example video of this but the divisor is -1/2?

@MathByThePixel

6 ай бұрын

It should work the same way, just with messier subtraction. Sorry I haven't had the time to put something together like this. It's been on my video list for some time now!

does it work all the time?

@MathByThePixel

9 ай бұрын

As long as you are dividing by a linear binomial with a coefficient of 1, you should never have an issue doing things this way. Things look a bit different when this isn’t the case.

@ghostffx8658

9 ай бұрын

​@@MathByThePixelthanks!

@MathByThePixel

9 ай бұрын

@ghostffx8658 anytime!

Thanks brother

@MathByThePixel

4 ай бұрын

No problem!

Y did it turn to negative 2?

@MathByThePixel

2 жыл бұрын

When we use synthetic division, you take the value that makes the binomial equal to zero. So in this case, for x+2, x=-2 will make it equal to zero. From there we add. Another way is to just keep the +2 and subtract!

@lorcanzo2498

Жыл бұрын

@@MathByThePixel ahh thanks

@MathByThePixel

Жыл бұрын

@@lorcanzo2498 Anytime!

I'm can't understand

@MathByThePixel

Жыл бұрын

Here's a full length video that will probably help! kzread.info/dash/bejne/eXl306eNgKe7ZKw.html

What do you do if the remainder is non zero? For example: x²-4x+3 divided by (x-1) will get you: 1 | +1 -4 +3 + | +1 -3 -|------ × | +1 -3 +0 And the result will be x-3 with a remainder of 0, so we can express this like (x²-4x+3) ÷ (x-1) = (x-3) and you can change this to look like (x²-4x+3) = (x-3)(x-1) But if we try x²-4x-2 divided by x-1 we get 1 | +1 -4 -2 + | +1 -3 -|------ × | +1 -3 -5 And the result will be x-3 with a remainder of -5. What do you do now? Do you just say that (x²-4x-2) ÷ (x-1) = (x-3) -(5/(x-1))? We can change this to look like (x²-4x-2) ÷ (x-1) = (x-3) -(5/(x-1)) (x²-4x-2) = (x-3)(x-1) -5 But now we don't have it in the form of [Polynomial] = [factor][factor] because we have a -5 in there!

@MathByThePixel

Жыл бұрын

It looks like there was an error in your table! When adding -4 +1 you should get -3. This will in turn force your remainder into being zero. This will always happen if you find a factor like you did when you chose (x-1). Make sense?

@xXJ4FARGAMERXx

Жыл бұрын

@@MathByThePixel yeah I corrected that part, re-read it

@MathByThePixel

Жыл бұрын

You are correct to express the remainder in that way! Check out this video where it shows you how to express a reminder when dividing polynomials kzread.info/dash/bejne/dHlkstB6ibu1pZM.html