STOICHIOMETRY - Limiting Reactant & Excess Reactant Stoichiometry & Moles
STOICHIOMETRY - Limiting Reactant & Excess Reactant Stoichiometry & Moles - A video showing two examples of how to solve Limiting Reactant stoichiometry problems. This video also explains how to determine the excess reactant too. Stoichiometry can be a difficult concept, tune in to see how easy it can be.
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That's fucking great.. 6 minutes in before I realized you are never going to explain what I needed explained.
@LazazDimirmastermind
6 жыл бұрын
same
You explained in 12 minutes what my teacher couldn't teach in an hour. Thank you so much for making these videos!
You. Are. Amazing. After 50 videos, yours is the one that saved me, you have no idea how much I love you right now.
Omg thank you I was going into my exam clueless but now everything is so much clearer thank you!!
Chem 111 in the summer, ugh! Great example! I have a test Monday so I'll be tuning in again. Much better than my professor. Thanks!
Thanks! I really appreciate anyone who takes the time to create videos like these
@sciencepost
9 жыл бұрын
cjt0123 Thanks. It's really cool to hear that it helps. Best wishes learning.
I have a test in a few hours, THANK YOU SOO MUCH! I literally had no idea how you do this
Thank you so much! My chem teacher only did two problems on the board real quick, and then told us if we did'nt understand it, we have to look up tutorials on you tube. You are way better than her! You saved us all
Love it! and you too! I don't know why my chem teacher can't just explain this stuff in the simplest way like you did. Great job! Thank you!
@sciencepost
10 жыл бұрын
Kudos to you bro for tuning in and taking the time to learn! Love it! Here's some advice dude, never quit and always be awesome!
This was very helpful! I forgot how to calculate limiting reactants for my summer assignment and this problem was driving me insane. Thank you so much!
helped so much more than the other videos of stoichiometry! thanks!
i'm strugging big time with stoichiometry. you explain everything so well. thank you!!!!
I have been using your videos for a while now, i can truly say that i have never learned so much in a short amount of time. :) thanks Mr post
@sciencepost
10 жыл бұрын
Hey Bryan, that was a really nice compliment. Thanks. Please continue to be awesome and dominate your tests!
Kylie, thx for the compliment. There is no way to get this after 2 examples. Good job tuning in. If the video helped, please share it with a friend. Tune in again when you get lost in the sauce. Peace.
I took really long to understand this particular part but now i understood! Thanks for this video! It helped me! :)
Glad to help. The concept can be difficult to explain sometimes, but I'm glad you caught on! Congrats on learning a tricky topic.
Thanks a lot it seems like you know everything except how enlightened i am everything's just so clear to me everything makes sense
Thanks so much man! You explained everything perfectly and now I understand!
Okay, ur my hero:)))) I'm really struggling with this unit and ive looked up every video for this stuff but yours was the only one that really clicked, it was really clear through out the whole video THANKSSSSSSSS:)
Thank you very much. Excellent explanation and brilliant working.
Can't thank you enough for these videos... they have helped tremendously.
Thx for the compliment Carolyn! I try to keep it simple, and I hope you go big on your test!
This was so great! I feel so much better now that I understand it. The hot dog explanation really helped me understand the general idea. Thank You so much :)
@sciencepost
10 жыл бұрын
That's great to know that the good old hot dog analogy worked! I'm so stoked that it all has clicked. Keep up the good work and always be awesome!
@Cha27Cha
10 жыл бұрын
sciencepost Thank you! You are so kind :D
Hey Zach, thanks for tuning in, I'm truly stoked it helped. Peace.
Thank you so much! I can't believe I thought this was so hard when it is really easy! I am emailing this to my friend!
@sciencepost
10 жыл бұрын
Thanks for your feedback! I'm so glad it clicked and sharing the video!
KZread always saving my a$$ before an exam... Thanks sciencepost keep it up !
@sciencepost
9 жыл бұрын
Beto Moris I love to hear that the vids keep helping people like you out. Keep coming back for more and never quit on learning!
I wish i knew about this channel earlier in the school year! everything is starting to make sense now (only took about nine months :/)
Thank you so much! Much easier than what my instructor taught. Makes sense now. whew!
@sciencepost
9 жыл бұрын
Jeannie Gauldin Sounds like the light bulb went off. That's awesome. Keep up with it and I'm sure you'll do well.
@jeanniegauldin7397
9 жыл бұрын
Thank you. I sure hope so because I have been struggling. And you have to understand what you are doing before you can move forward in chemistry.
how did you get the 22.4l as the bottom half of the second reaction shown.. a bit confused to how you get 22.4l
thanks! I finally understand!! though it took me a minute after the video to absorb it all. nice2
Thank you very much! This was more help than my chem teacher
i find it useful to see these lecture on youtube.
So to get the 130g for the max amount of CaO made from 37.1g of oxygen... Did you multiply 64.96 (Moles of O2 x formula mass of CaO) by 2, since we are looking for the amount of O, rather than O2?
Great Video! Helped a lot.
Thank you so much, helped me pass my test
THANK YOU SO MUCH BRO! HELPED A LOTTTTTTTTTTTTTTTTTTT.
umm, quick question. O2 started in Liters, how did it end up in grams? and is 22.4L converted from 16g?
That's a great compliment. Keep up the learning, tune into my other videos if needed. Peace.
This is a really helpful video!! thanks a lot!
Perfect example with HOTDOGS! Thnx bro
great explaining! very clear thanks so much for the help :)
this helped so much bless your kind soul
What do you add together get the ending number
Stoked to help. Best wishes on your final.
You sir, are awesome. Thank you very much!!!
how did you know what numbers to put in for the balancing
Great explanation!
thank you so much!! this was really helpful!!
Thank you for the video is was a GREAT help!
@sciencepost
10 жыл бұрын
That's awesome to hear. This topic is not easy. If you just got it, that is sweeeeet.
You are totally welcome! Keep up the great effort!
helped me alot! thanks! great explanation
this helped me so much , thank you :)
Great video!
if i were to find the difference between the E.R. and the L.R. then reverse the molar conversion step would that give me the amount of E.R.?
Yea I found the video! You're very helpful thank you
wow this helped me a lot ....tnxxx a lot dude
great video keep it up
Thank you so much! You just saved me! If I ever have a pop quiz on this, I'm sure that I'll ace it! Thank you!!! ^_^
THIS VIDEO SAVED MY LIFE
@sciencepost
10 жыл бұрын
So cool to hear!
Haha, I already understand this, but the hot dog thing is really clever and easy to understand!
wait, howd you get the 24.33 and the 22.4?
You really saved my ass, man. Thank you so much.
what do u do to find the answer of 49.1????
how exactly do you find the amount of the excess reactant that is unreacted? it is one of my chemistry problems..
6:03 how did u get 40.3 for MgO?
Where did u get liter equivalent of o2
only at STP (Zero degrees Celcius, 1 atm) though correct??
thank you very much!! now i can pass my chemistry final! haha
Im stoked it worked bro!
Shouldn't 130 in the last problem have a decimal point afterwards to keep three significant figures in the answer?
Awesome! Do well on your test.
How Do i use this when doing grams to mole to mole to grams
No you are awesome! Really sweet observation!
Thanks for the help! My Chem Teacher won't kill me now!
@sciencepost
9 жыл бұрын
Mr. Independence EDM That's good news!
@sciencepost
9 жыл бұрын
Mr. Independence EDM Check out my stoich playlist kzread.info/head/PLNc_BreVXbmoiQaQnunBX5CvZL7-aM1XQ
@user-rn5lb3gr6z
9 жыл бұрын
I Know!! Huh!
where did the 40.3 come from?
I would like to know is how did you get 22.4L of O2 when you just only know the Litters of O2. Is there a method to get 22.4L of O2 of just having Liters of O2 and nothing else? I'd like a response, this really helped me a whole lot in understanding this section of chemistry, it's just that part that I asked just confused me a little.
I may be looking at this wrong but how are you getting 22.4 if Oxygen has an atomic mass of 16.00? This should mean that the first conversion is 1molO2/32gO2, right? Please elaborate on your conversion. Thank You.
7:27 how u get 22.4?????
since O2 is alone wont it be like 2 mol O instead of just 1 mol O2?
Great review, thanks ;)
Thanks helped a lot!
this is great!
this helps alot!!!
Need a bit more explanation ! How did you get 24.3 g , 40.3g and 22.4 ? How would we know that ? Reply please .Regards
Lol! I love hearing this kind of stuff. Keep up the learning.
how can we find it? or it would be given during MCAT exam?
Hey bro, thanks for the keen eye. In the first example, oxygen was given in liters so I used 22.4L per mole. Hope that helps.
Why didn't you put 31.9988=32g (16x2) on Oxygen like what you did on Mg 24.3g (6:08 part of the video)
How do i balance the equation?
man thank you so much!
Thanks this helped alot now im not gonna fail my test tomorrow
So how does O2 go from 32.0 g to 22.4 L? Would be nice to show that to us newbies
Picture this, when you are given a length in feet, such as 6 feet, and are asked to convert to inches, what do you do? You would use a conversion factor such as 12 in = 1 ft. The key is that you need a conversion factor! When you are given the volume of a gas in liters, such as 20 L as the video shows, you need to convert that out of Liters and into moles. In order to convert it, you need a conversion factor.
wait don't u have to convert liters to grams on the second stochiometry problem
@bobyay932
3 жыл бұрын
there is a stoichometry formula used to convert L to grams
Hey Mollie. I'm proud of you for your desire to learn and I'm stoked my teaching style matches your learning style. Best wishes on your exams. Tune in again.
Glad to teach you
@Alexis Rivera that would only work if it was in grams, but its 20L. The conversion factor between moles and litres is 22.4L/mol at STP. however, the question did not specify that the O2 was gaseous, or that it was at STP, thus the question is done incorrectly. Just little things, but watch out for things like that on a test.
Thank You! well explained!
@sciencepost
9 жыл бұрын
Lizbeth Caceres I'm glad it helped. Thanks for the feedback.
this was helpful :)
Why is the 2 placed, can't it just stay as one