If more professorstaught like you, the world would be a better place...love from south africa

@PrimeNewtons

Жыл бұрын

Thank you

At the of 75 in a retired life I am enjoying your brilliant way of teaching mathematics; best wishes for your great work (from a senior citizen of India)

@PrimeNewtons

7 ай бұрын

Many thanks!

The way you offer your classes is just fun, simple and fast.

"Those who stopped learning, stopped living."💯❤That's powerful sir. You are doing incredible work.

My brother you have explained the concept of squeeze theorem so simple thank so much pliz continue to make more videos you are a great tutor I have ever watched.

This solution was so understandable and clear. Thanks 🎉

Thank you so much for making this easier to solve and understandable

Apart from the clear way of your explanations you have a soothing voice which is just perfect. I am very glad I have found your videos. I taught math for many years.

Wow! Just exciting. Thank you sir.

You are a great help, thank you

like.. thank u sm and i would be lost without u!! big love from Iraq

Nice explanation. Easy to follow.

Great explanation.

You're just awesome my brother

THANK YOU FOR YOUR SUPPORT

Salute bro💯💯 i gained more in your tutorial

Great my brilliant sir.

We could use the sinu=u formula as you said to get 0 But I really like this method I learned it today from you ! Keep up the great work man ❤️‍🔥

Tomorrow will be my exam and i thaught squeeze theorem is easy enough but when i try to do questions i stuck up and then this video 😊 . Thanks a lot

you have a beautiful hand writing

thank u very much 👍🙏

please do more!

Good one💥

Hey brother i have one question, what would happen if i replaced x^6 with an odd power? Thx for all your videos they really help me out a lot 🙏🙏

@PrimeNewtons

Жыл бұрын

It doesn't matter because if negative x^5 will be negative and so will change the inequality signs on both sides but that would then retain the original inequality just written from right to left and you can rewrite it. So, the short answer is that nothing will happen.

that`s great🎉🎉🎉

you are brilliant 10q

Since you made a few videos using the squeeze theorem, can you please make up a video that proofs this theorem? That would be cool.

lovely lol i wish i was your student

Thanks for your lessons, why didn't you divide all sides by × from 5/× at the middle?

If it were not for the mandatory use of squeeze theorem, could you have said that sin(5/x) would go to an undetermined value between -1 and 1, which, when multiplied by x⁶ which would go to 0, would also become 0

Guy is damn smart.

Wow you are smart

❤❤

Thank you so helpful if it was x inplace of x^6 and the second question if x approaches 0 from the right or from the left could you please reply

@PrimeNewtons

Жыл бұрын

All 3 answers are 0

@o.om.m5632

Жыл бұрын

@@PrimeNewtons so if the exponent of the x is odd it don't matter as all the inequalities will stay the same all all of them will flip right?

😊

What happen if x has an odd exponent ? do we assume negative or ? depend on what value x is approaching

I dont understand only one part though: How did you multiply the entire inequality with x^6 because thats basically 0? Or its not? Maybe its allowed because its very close to 0 from the right (positive) side? Please clarify on this.

GOOD SIR WHERE CAN WE FIND YOU MAYBE TO ADRESS SOME KIND OF QUESTIONS.

@PrimeNewtons

Жыл бұрын

Message me on Twitter or email primenewtons @gmail.com

kindly do triagle of inequality

Hello Sir, I wanna if ever what if the power was odd , were we gonna change the sign since we didn't change because it was to the power of 6

@PrimeNewtons

Жыл бұрын

It will adjust in the end even if it's odd. Watch the other squeeze Theorem video. I explained it there.

Sir can you pleasee make video on proving squeeze theorem and please make a video on Weisteress Thereom with proofs

What if we have a fraction for example the limit of sin(8x)/x as x approaches 0 or the limit of sin(t)/square root of t as t approaches 0

@PrimeNewtons

Жыл бұрын

The first example is quite common. Multiply x by 8 then multiply sin(8x) by 8. So the limit is 8. For the second, do the same think using sqrt t instead of 8. You should get 0 answer.

@KingGisInDaHouse

11 ай бұрын

That first one requires a whole ‘nother one or two videos to explain. That second may require some dlc we learned in calc two…or you would at least have to come back to it after you learn derivatives and interpret it as one.

@KingGisInDaHouse

11 ай бұрын

Ok for that second one you can do it with raw limits my argument is you can say sin x0+ sin x/sqrt(x) 0 x/sqrt x because your dividing more cookies by the same number of people Now we need a lower bound argument for the squeeze theorem. The limit is positive because positive/positive is positive for my lower bound I can just use the opposite lim x->0+ -x/sqrt(x) 0 x/sqrt(x). Since x/sqrt(x)=sqrt(x) -sqrt(0)0- sin(x)/sqrt(x) lim u->0+ sin(-u)/sqrt(-u) lim u->0+ -sin(u)/(i*sqrt(x)) Lim u->0+ (-1/i)*[sin(u)/sqrt(u)] Lim u-> 0+ (-1/i)*[0]= 0

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