Пікірлер

• 
  @raymondseligman70032 минут бұрын

  Who is he? Fantastic!

• 
  @user-pi8ke6dp7r13 минут бұрын

  i can slove this problem 1 minute

• 
  @EdenPhiri-hk9oy27 минут бұрын

  Very helpful

• 
  @KUDIYARASAN-30 минут бұрын

  Great... Very focused presentation.

• 
  @kekahazra976933 минут бұрын

  Man! I really like your enthusiasm....😊....wish i had more teachers like you..... keep teaching like this.... again thanks a lot for this knowledge.......and the answer is 16....😊

• 
  @user-yb2sf8gx9y52 минут бұрын

  simplicity makes maths nice

• 
  @c15harshraj56Сағат бұрын

  Solve jee advanced( entrance exam in india) questions are really good , will surely boost ur interest in mathematics 😶

• 
  @c15harshraj56Сағат бұрын

  💚 from india

• 
  @holyshit922Сағат бұрын

  4:38 Here we have Vieta formulas so we can easily write quadratic with roots x and y

• 
  @user-jm5rj4sv7iСағат бұрын

  the future i seen it

• 
  @0day450Сағат бұрын

  thank you sir for save my life!

• 
  @AryanKumar-vo1icСағат бұрын

  nice prob

• 
  @Phelps393Сағат бұрын

  I love Math but school just discourages me from solving problems as we are , in a way , forced to cram shit for the exams.

• 
  @suleimanbashir-wh2km2 сағат бұрын

  Sir plz help me this question Find the Limit of Lim tan7x/14x as x tends to 0

• 
  @surendrakverma5552 сағат бұрын

  Very good. Thanks 🙏

• 
  @LaCodileClimbing2 сағат бұрын

  54321 =125-5

• 
  @daddykhalil9093 сағат бұрын

  7:48 where from did you get this “by inspection” genial idea??? I consider similar methods which are similar to trial-and-error methods as a weak approach, being illogical and cheap

• 
  @Pachankapatro3 сағат бұрын

  If i would've found you when i did my bachelors i would've been very happy

• 
  @legendarybalak91414 сағат бұрын

  Just some more shit why do you even need that

• 
  @aidan-ator78444 сағат бұрын

  I only would have gotten to the stage where a>absolute b😢

• 
  @lukaskamin7554 сағат бұрын

  Sorry, but I don't see a problem with D=0, x would remain positive (a²+b²)/(4a²) . Why was this case excluded? Maybe the variables wouldn't not be dustinct, but it's not obvious so far

• 
  @sad.tune.4 сағат бұрын

  Juice WRLD teaching maths😭😭

• 
  @lukaskamin7554 сағат бұрын

  11:39 could you explain how you made factoring mentally? Did you use the cross method (I've heard of it, though we have not learnt that at school where I live)

• 
  @lukaskamin7554 сағат бұрын

  I believe you overlooked a difference of 2 squares in the discriminant, you would get factorisation with less effort. Also I'm curious when it happens to solving equations x+y=S, xy=P, people on English KZread start from non-linear equation xy, thus getting a rational function that is to be fought heroically later on , while it's much easier to start from linear equation x+y, not causing any denominator to appear in the course of the solution?😮

• 
  @Animation_with_ss5 сағат бұрын

  16....thanks sir for great explaination,love from indian🤗

• 
  @okemefulachidera54405 сағат бұрын

  It’s quite an interesting maths but at the end I got confused😂

• 
  @robertpearce83944 сағат бұрын

  x,y, and z greater than zero was stated as a condition. However, that is what was supposed to be proved.

• 
  @DebelaFikadu-fn4wi5 сағат бұрын

  Thanks for ever ❤

• 
  @Scienceguy06 сағат бұрын

  Nice ❤

• 
  @rnhettema23596 сағат бұрын

  At the end you could only conclude x, y and z are not all the same, but what about x=y and x=z

• 
  @deriklytten5 сағат бұрын

  From the condition xy = z^2, if any two of them are equal, it will imply all 3 are equal...

• 
  @rnhettema23594 сағат бұрын

  @@deriklytten thanks for the explaination

• 
  @aidan-ator78444 сағат бұрын

  ​@@deriklyttenvery thankful for pointing that out.🎉

• 
  @marcelojabuti36196 сағат бұрын

  Fake Math Eddie Murphy😂😂😂😂

• 
  @josephubi90966 сағат бұрын

  16, never learnt this and I am a mechanical engineering graduate

• 
  @kassuskassus62636 сағат бұрын

  Sir, you are really the Rambo of the mathematics ! 🤗🤗🤗

• 
  @franolich37 сағат бұрын

  None of the proofs given so far explain where the sqrt(3) comes from. The following approach gives some insight... Lemma: ab + bc + ca ≤ a^2 + b^2 + c^2 with equality iff a=b=c Proof: ab + bc + ca ≤ a^2 + b^2 + c^2 <=> a^2 + b^2 + c^2 - ab - bc - ca ≥ 0 <=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca ≥ 0 <=> (a^2 - 2ab + b^2) + (b^2 - 2bc + c^2) +(c^2 - 2ca + a^2) ≥ 0 <=> (a-b)^2 + (b-c)^2 + (c-a)^2 ≥ 0 This last statement clearly holds since the LHS is the sum of non-negative terms. Further, LHS=0 iff a=b=c Theorem: Let T be the area of a triangle with sides a,b,c. Then 4.sqrt(3).T ≤ a^2 + b^2 + c^2 with equality iff the triangle is equilateral. Proof: By Heron's formula: T = sqrt(s(s-a)(s-b)(s-c)) where s = (a+b+c)/2 => T^2 / s = (s-a)(s-b)(s-c) => (T^2 / s)^(1/3) = ((s-a)(s-b)(s-c))^(1/3) Using the triangle inequality, it is easy to show that (s-a), (s-b) and (s-c) are non-negative. Therefore one can apply AM-GM: (T^2 / s)^(1/3) ≤ ((s-a) + (s-b) + (s-c)) / 3 = s/3 with equality iff (s-a)=(s-b)=(s-c) ie a=b=c => T^2 / s ≤ s^3 / 27 => T ≤ s^2 / 3.sqrt(3) => 4.sqrt(3).T ≤ (a+b+c)^2 / 3 => 4.sqrt(3).T ≤ (a^2+b^2+c^2 + 2(ab+bc+ca)) / 3 By the lemma: => 4.sqrt(3).T ≤ (a^2+b^2+c^2 + 2(a^2+b^2+c^2)) / 3 => 4.sqrt(3).T ≤ a^2 + b^2 + c^2 with equality iff a=b=c, ie an equilateral triangle.

• 
  @robot83247 сағат бұрын

  I really like the way you are explaining those problems , thnak you

• 
  @johnsound17787 сағат бұрын

  I love this guy.....Thank you very much💚

• 
  @panagiotisvlachos61147 сағат бұрын

  A whole blackboard, in which the solution of the problem is included: THESE ARE PURE MATHEMATICS!!🤪 Good day from Greece!!

• 
  @cureyourcuriosity21327 сағат бұрын

  41 seconds ago...First

• 
  @user-hr6ex6np7t7 сағат бұрын

  First view and comment!!!

• 
  @NightCraft-17 сағат бұрын

  What?

• 
  @user-ie2cy6kc3t7 сағат бұрын

  Oh…thanks so much 😭🤍🤍

• 
  @AadiSrivastava-sp9zn8 сағат бұрын

  is it important to say that x = K + d (where d ≥ 0 )

• 
  @AadiSrivastava-sp9zn8 сағат бұрын

  because i solved it without doing that and got my answer

• 
  @AdityaSingh.9628 сағат бұрын

  2^2^2= 2^4= 16

• 
  @user-ts8rc7cn1r8 сағат бұрын

  thanks a lot will smith😊

• 
  @omograbi8 сағат бұрын

  This channel has turned into a witchcraft one that summons beasts

• 
  @ELITEDRAGONYT8 сағат бұрын

  This guy needs more popularity truly underrated

• 
  @masscreationbroadcasts8 сағат бұрын

  That intro looking like a teaser ☠️

• 
  @amirrozenmanmalach37718 сағат бұрын

  Whats a tens digit

• 
  @boringextrovert67194 сағат бұрын

  Second digit from the right

• 
  @user-es8yj8eq3k9 сағат бұрын

  Hello teacher Ask for an exercise lim x_a sinx-sina/cosx-cosa