Oh, I think I had this question around 7 or 8 years ago on a math olympiad!

Yeah very simple problem. Got it in my 4th grade math test last year.

*drunk Fermat's Theorem

How does (x+1)*(x+1)^x become 2(x+1)^x at 1:37 ? Also, this is completely different problem than Fermat's Last theorem, isn't it?

@MetaMaths

Жыл бұрын

It is an inequality. (x+1) is greater than or equal to 2 because x is an integer by assumption. It is different from FLT, but I think I make it clear in the introduction.

**This video is too short to fit the proof**

What about x^y+y^x=z^z? And for x^y+y^z=x^z?

@rafiihsanalfathin9479

11 ай бұрын

For the first one let y=1 you get x+1=z^z so there is an infinite solution

For people that has mathematics in their blood: Maybe mathematicians got tired and accepted a very complicated path and 100 pages so that only a minimum number of mathematicians understand what the proof is. Here's a different approach to the Last Theorem on a single page: kzread.info/dash/bejne/X56ko4-topmep9o.html

Your assumption at the beginning is not clear. It doesn't explicitly state how n substitution by x, y, and z still holds for the original problem.

😳 p̷r̷o̷m̷o̷s̷m̷

Wrong again. This is the Beal conjecture. And just like I have proven the negation of Fermat's last theorem I have also provided a solution to this problem. The key is to simply consider x, y, and z as exponents. If we allow the integers A,B,C to represent the prime integers exponents 2, 3, 5 , respectively and x,y,z to represent their integer powers 14, 4, 8, respectively then by the law of exponents [(14 x 2)+(4 x 3)=(5 x 8)]=[28+12=40]. And since A, B, and C are prime then they can have no common prime factor. Therefore the Beal conjecture is false. Now. If you are saying that the base and exponent must have the same power then this is simply the Pythagorean theorem. Therefore given the law of exponents (3^3)+(4^4)=(5^5) =(3x3) +(4x4)=(5x5) =(3^2)+(4^2)=(5^2) QED

@persistenthomology

Жыл бұрын

can't tell if trolling or just reaaally dumb lol. 3^3 is not 3x3 bud.

/from Ал-тай ДіЙ :/ Fermat's Great Theorem 1637 - 2016 ! I have proved on 09/14/2016 the ONLY POSSIBLE proof of the Great Fermat's Last Theorem . I can pronounce the formula for the proof of Fermat's Great Theorem: 1 - Fermath's great theorem NEVER! and nobody! NOT! HAS BEEN PROVEN !!! 2 - proven! THE ONLY ONE!!! - POSSIBLE! proof of Fermat's last theorem !!! 3 - Fermat's Great Theorem is proved universally-proven for all numbers 4 - Fermat's Great Theorem is proven in the requirements of himself! Fermat 1637 y. 5 - Fermat's Great Theorem proved in 2 pages of a notebook 6 - Fermat's Great Theorem is proved in the apparatus of Diophantus arithmetic 7 - the proof of the great Fermat's last theorem, as well as the formulation, is easy for a student of the 5th grade of the school to understand !!! 8 - Me! opened the GREAT! A GREAT Mystery! Fermat's last theorem! (not "simple" - "mechanical" proof) Me opened : - EXIST THE ONLY ONE!!!-POSSIBLE proof of Fermat's Great Theorem Me! opened : - the GREAT! A GREAT Mystery! of the Fermat's Last theorem! (- !!! not "simple" - "mechanical" proof) Me! opened : - Pierre de Fermat - was proved! the Fermat's Last theorem! Me! opened : - my formula of my Proof is completely and absolutely identical with the words of Pierre de Fermat ! Me! opened : - the proof of the theorem - The REAL! Proof! - worth a BILLION! , - but do not! a one little-smalest-million !!!!- NO ONE! and NEVER! (except ME! ...AND!... Pierre de Fermat! - of course!) and FOR NOTHING! NOT! will find a valid proof! /Ал-тай ДіЙ/

@fullfungo

2 жыл бұрын

WTF!?

@papetoast

2 жыл бұрын

are you ok? your words make no sense

@FaranAiki

Жыл бұрын

Go solve Goldbach Conjecture, and I will be happy.