This should also include H3O+ as a second step! Because this reaction is performed in basic conditions, the alcohol of the para or ortho-nitrophenol formed at the end is acidic and therefore will be deprotonated by the -OH. This means we need to introduce a proton source to the system in order to reprotonate the conjugate base of OH (which is -O) and reform the desired final product.

I will be very surprised if the narrator is the original founder of Khan Academy. The subject variety, including this advanced organic problem, is beyond extraordinary. The narrator's voice doesn't sound identical to the original founder, who I remember his name is Sal.

Thanks for the great work on explaining this. Appreciate!

Nucleophilic aromatic substitution? More like "Khan Academy is such a great institution!" I can't express in words how much you've helped me over the years.

thank you, this helped me a lot!

SN1 is tipical for diazonium salts, i made two of those nice synthesis in lab

appreciable.... cleared my confusion very well😄😄🙌thanks a lot💝🙏

Thanks! Was really helpful

if you were asked to choose which group would most readily react and you had one ortho and one para would you choose the gorup that has the para or the ortho position?

Thanks a lot :)

if there was a bromine on both the ortho and para position what would be favoured the ortho the para or the di substituded compount

thankyou :)

Does it have to be -R?

is this SN Ar or SN Benzyne??

ty ty ty

Is addition elimination reaction valid for haloarenes?

In the textbook I am using for o-chem, it showed that the electrons moved to a carbon atom instead of the nitrogen atom to form a carbanion intermediate. Are both ways correct then? does it really matter?

@MaMalykPoptart

6 жыл бұрын

elle alless No it doesn’t. As long as you’re showing all of the structures that are contributing to resonance (which should be 4 resonance structures in this case), order doesn’t matter.

@stella444

6 жыл бұрын

Unf God thank you!!!!!!