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An Introduction to Explosions and Explosion Safety by Prof. K. Ramamurthi,Department of Mechanical Engineering,IIT Madras.For more details on NPTEL visit nptel.ac.in
An Introduction to Explosions and Explosion Safety by Prof. K. Ramamurthi,Department of Mechanical Engineering,IIT Madras.For more details on NPTEL visit nptel.ac.in
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Very good series of videos! Thanks for sharing
Very informative information. Thanks for sharing.
Very very very good information about the topic
Is there any institution in india providing short term course on blast analysis (theory+software) ?
Some people may be confused at 25:00, so here is the derivation if you are following this course: Force = rate of change of momentum let density be denoted as D, volume as V (so mass m = D.V) Where, momentum change d(momentum)= momentum at left - momentum at right velocity of sound in medium = a0, increment to velocity is = dv velocity at left = a0 + dv velocity at right = a0 => d(momentum) = m(a0 + dv) - m(a0) = D.V.(a0 + dv) - D.V.(a0) = D.V.dv Also volume V = Ax = A(a0.dt), where x = distance travelled by wave in time dt = a0.dt so, d(momentum) = D.V.dv = D.(a0.dt)dv Rate of change of momentum = d(momentum) / dt = D.a0.dt.dv / dt = D.a0.dv Force = Force to left - Force to right = pA - (p + dp)A = -A.dp equating Force to rate of change of momentum (Newton's second law) -A.dp = D.a0.dv and the rest can be done easily.
Wouldn't the speed of the wave be x+at not x-at? After all we are moving to the right. If the wave starts at x=5 and phase shifts a*t the new start position of the sine wave would be x+at or 5+at.
@dharmajitkumar8889
6 жыл бұрын
as you can see from pink, graph at at =5 & x=5, y =0. now sin(x-at)=0 & sin( x+at)=sin10
Great
35:40 Explains the steep front of a shock wave.
Can you put these videos into order. It's very hard to find lectures in chronological order.
Which reference books should be refer?
@narkambam7241
Жыл бұрын
"Explosions and explosion safety" by K Ramamurthi
Books to follow
@abdel-rahmanhussein6550
Жыл бұрын
You got any books , bro ?
@narkambam7241
Жыл бұрын
"Explosions and explosion safety" by K Ramamurthi
41:22
Just started watching these lectures. Please don't remove. I am into sales and we sell all kind of doors from normal steel doors to blast resistant doors. Wanna know more about Blast. By the way, I am a science graduate.
Infinitesimals should not be proportional to non infinitesimals , a is for acceleration - not speed, etc... It appears that someone has "exploded" this poor man's notation :/ Otherwise this is an excellent lecture ;) It would be nice to see the non-linear PDE for propagation of displacement from equilibrium at high compression ratios with heat and velocity diffusion (aka viscosity) terms added derived and some solutions and their properties discussed. The adiabatic wave equation without the diffusion terms has an exact solution that can be found using separation of variables.
@l0_0l45
2 жыл бұрын
This "poor man" is a world expert in this subject. The notation "a" is for velocity of sound in a material, and "c" is for fluid velocity, and "Ma" is for Mach Number, and if an "intelligent man" like you would have studied fluid mechanics, gas dynamics, or any subject from thermofluid engineering you would have been aware of this notation.
@l0_0l45
2 жыл бұрын
I know you have made the comment 3 years back, so I am posting it for anyone who sees it later(many people take this course every year through NPTEL) Also, if your issue was at 25:00, then it is actually derived as: Force = rate of change of momentum let density be denoted as D, volume as V (so mass m = D.V) Where, momentum change d(momentum)= momentum at left - momentum at right velocity of sound in medium = a0, increment to velocity is = dv velocity at left = a0 + dv velocity at right = a0 => d(momentum) = m(a0 + dv) - m(a0) = D.V.(a0 + dv) - D.V.(a0) = D.V.dv Also volume V = Ax = A(a0.dt), where x = distance travelled by wave in time dt = a0.dt so, d(momentum) = D.V.dv = D.(a0.dt)dv Rate of change of momentum = d(momentum) / dt = D.a0.dt.dv / dt = D.a0.dv Force = Force to left - Force to right = pA - (p + dp)A = -A.dp equating Force to rate of change of momentum (Newton's second law) -A.dp = D.a0.dv and the rest can be done easily. The notation is consistent with what is seen in gas dynamics.
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