Math Olympiad | Find the Perimeter & Area of the Triangle | VIJAY Maths
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Пікірлер: 7
Nice explanation
Thanks, classic
Thanks
whoaa
Since 41 is prime it has unique solution.So hypotenuse is (41^2+1)/2=841 Other side is (41^1-1)/2=840 We can find area and perimeter. 2m,m^2-1,m^2+1 is Pythagorean triplet. I used 2m/2,(m^2-1)/2,(m^2+1)/2. 1,
a = k = 41 → b = (k^2 - 1)/2 = 840 → c = (k^2 + 1)/2 = 841 → area ∆= 420(41) = 17220 = x; perimeter ∆ = a + b + c = 1772 (this way is well knowned since the Old Greek Plato 🙂)
180°ABC/41=4.16 2^2.4^4 1^1.2^22^2 1^1^1^2 1^2 (ABC ➖ 2ABC+1)