X^5 + (2-x)^5 = 82 brother

nicely done. quite a marathon!

❤

The values analysed don't suit the second equation as 5th square of any number will carry the square root symbol

Nice video with all steps clear but it's too long to arrive to the answer is there other alternative methods especially short cut?? It's head cracking too long to solve any way thanks

I have a strong headache. 😂😂😂

just substitute y = 2-x and use binomial expansion

Marathon steps, but well done...short steps if possible should be tried..

Equation in power 5 should have 5 sets of answer , where as you showed only 4 pairs , what is fifth Pau of answaer

@ShareTyro2010

4 ай бұрын

If you put y=2-x, we will have x^5+ (2-x)^5 = x^5 + .... -x^5= the fifth power will drop and we will get an equation with one unknown of the fourth level

X = 5√15. Y = 75/√15.

I recommend you to skip so many trivial steps.

That’s is more challenging. It’s not easy 😂

Okey x=? y=?

Can anyone solve this x+y.xy=2 x+y:2=2

x^5+y^5=82 so there are 5 solutions Four solutions are incorrect. Find another solution

ans is 2

분 7.

После просмотра возник читерский способ решения: 1. Представить: x = m + n, y = m - n, складываем, сразу 2 m = 2, m = 1 2. Дальше раскладываем: (m + n)^5 = m^5 + 5 m^4 n + 10 m^3 n^2 + 10 m^2 n^3 + 5 m n^4 + n^5 (m - n)^5 = m^5 - 5 m^4 n + 10 m^3 n^2 - 10 m^2 n^3 + 5 m n^4 - n^5 складываем: 2 m^5 + 20 m^3 n^2 + 10 m n^4 = 82 при m = 1 получаем: 2 + 20 n^2 + 10 n^4 = 82 или n^4 + 2 n^2 - 8 = 0 подставив k = n^2, получим: k^2 + 2 k - 8 = 0 -> k = 2, k = -4 n = +V2, n = -V2, n = +2i, n = -2i 3. Дальше сами

xxxxx + yyyyy = 82 x + y = 2 xxxx + yyyy = 80 a + b = 80 a + b + a + b = 160

@wongkienloon

3 ай бұрын

a=b=160/4=40 x + y = 80 40+40=80 1+1=2

Stop calling basic algebra problems “Olympiad problems”. There is nothing Olympiad about it.

Terlalu bertele - tele

Столько лишней писанины. Просто капец

@Buravick

4 ай бұрын

Особенно после 8:53 . Неужели так сложно найти корни квадратного уравнения?)

You cannot simplify a square within the square root, it is a mistake, since that is the definition of module.. A big conceptual mistake . So the resolution is bad .

@wajidazeemfy

3 ай бұрын

Are you sure? Since squares always return a positive value, any square within square root should be simplified.