x = 4-x 2x = 4 x =2

In x^4=(x-4)^4 both sides of the equation are positive for all x. Taking the 4th root of both sides and consider all possibilities for LHS and RHS: ++, +-, -+, --. The solution is -x=x-4 or x=-(x-4) => x=2 is a real root. If you are looking for complex conjugates, then the factor theorem and (x-2)(x^2-4x+8)=0.

@Halimamessaoudi-vl3dp

7 күн бұрын

yes this correct

Just the idea that the half of 4 will give the ±x is enough to solve this

Good

i ❤ Mathematics

👌👌👏👏

Тут так сложно решать не надо. Вариант решения, это использовать свойство отрицательных чисел умножаемых на самого себя становиться положительным числом. Не сложно увидеть, что в данном примере Х=2, так как 2-4=-2. А -2 в четвёртой степени это 16. There is no need to make such a difficult decision here. A solution is to use the property of negative numbers multiplied by themselves to become a positive number. It is not difficult to see that in this example X = 2, since 2-4 = -2. A -2 to the fourth power is 16.

You lost the 4rth root? You should have 4 solutions but you missed an opportunity to do another perfect square: (X^2 - (x-4)^2) You squared the right side but could have treated this a perfect square instead. Do you agree?

@massimoarmillotta2705

11 күн бұрын

No. That equation has degree = 3, not 4. The degree of an equation is the maximum power of x when the equation is reduced at its minimum form. If you try, you'll see that x^4 will disappear

@joseeoliviero6078

11 күн бұрын

I understand now. Thanks

Can we take the fourth root in the first step?

@Iloveminecraftverymuch

14 күн бұрын

Why not?😊

@JohnMayer-ql5fd

14 күн бұрын

@@Iloveminecraftverymuch Why?

@cosmolbfu67

13 күн бұрын

yes but we'll get one solution x^4=(x-4)^4 take 4th root x=|x-4| x=x-4, x=-x+4 So x=2

@massimoarmillotta2705

11 күн бұрын

No. This equation has degree = 3, not 4 as I told before. The degree is the maximum power of X when the equation is reduced at its minimum form. If you make calculations, you'll see that x^4 will disappear

Надо сначала вычислить дискриминант, а потом делать вывод о решении квадратного уравнения. Все хорошо, но не рационально решено банальное квадратное уравнение. Зачеркивание в алгебре допускается при уничтожении слагаемых с разными знаками, а вот при сокращении дроби необходимо писать результат, даже если это 1.

X#0 chercher les racines 4eme de l unité 1;-1;i et -i du in l appelle a une telle racine Résoudre ax = x-4 du premier degré....

Help (x+y)^x^1/2=(x-y)^y^1/2

16

Professor, as the X has power of 4, shouldn't the equation have 4 solutions?

@massimoarmillotta2705

11 күн бұрын

No. This is a 3rd degree equation. The degree of an equation is the maximum power of X when the equation is reduced at its minimum form and that one is not the minimum form.

@user-hz5ne2rl5e

10 күн бұрын

@@massimoarmillotta2705 He's right. There are 4 roots to the equation in the power of 4. x=2 are two repeated roots. x=2-i and x=2+i are two complex conjugates.

@massimoarmillotta2705

10 күн бұрын

This is not a power of 4 equation but 3. So there are only 3 solutions

@snarkybuttcrack

10 күн бұрын

@@user-hz5ne2rl5e x=2 is not a repeated root

@user-hz5ne2rl5e

9 күн бұрын

@@snarkybuttcrack You are correct. It's not a repeated root. I made a mistake, not checking it if it is.

X= 2.

Not 4 me!

Х = 2, поясню почему: 2^4 = (2-4)^4. Обе части получились 16

@rabotaakk-nw9nm

8 күн бұрын

А где два мнимых корня? 😮

@alexeyevgenevich9821

8 күн бұрын

@@rabotaakk-nw9nm кстати, мнимые корни в школьную программу по математике не входили, по крайней мере, когда я учился

@rabotaakk-nw9nm

8 күн бұрын

​@@alexeyevgenevich9821Кстати, это - Ваша проблема.

Dude what kind of mushrooms you’re using square root of -16, seriously? Answer is 2

I don't like maths🤢......🤮

@user-yg2qr8ph2j

15 сағат бұрын

becouse you are stupid