I always knew Jesus saves, but I didn't think he'd be saving my Chemistry grade

@christisking7911

3 ай бұрын

👀💪💪💪✊✊✊🦁🦁🔥🔥🦁🦁🙏🙏♥️❤️❤️🔥🔥🔥🔥💯💯💯💯💯

@denicagovender5029

Ай бұрын

Well,he kind of looks like Jesus😂

@-_-ZENN-_-

Ай бұрын

@@denicagovender5029that was the point of the joke 🤦‍♂️

professor dave whippin out the bologna sandwich analogy makes him my favorite person ever

@user-pp1bv7yr2n

4 жыл бұрын

Fr

@arjungupta3095

2 жыл бұрын

He’s a living legend.

@ivoryas1696

2 жыл бұрын

Katie Cheng It's so intuitive yet effective Some sandwiches are just Bologna(O) and bread(H), others are double or triple decker and have a different medium like... peanut butter (Ammonia), or have different things that act as bologna but aren't or dishes that don't need it (a turkey sandwich or literally just table salt). It's brilliant!

@tontonanharian6840

Жыл бұрын

The best teacher i never tell my friends to be the excell in class. I already speedrun math to linear algebra with professor dave videos and now i came to learn chemistry

Came here from Khan Academy. Much clearer presentation than the current Khan Academy video on limiting reagents. Thank you so much!

@adarsh65kumar

4 жыл бұрын

I actually didn't understand this video, so I went to the khan academy video after reading your comment.. to see if it would be any different! Strangely enough, I understood their explanation! KA video is more detailed than this one is, I don't understand why you guys didn't like it! In any case ,I'm greatful to both these educators !

@talalarfi2888

4 жыл бұрын

i like khan academy more.. they explain it better (my opinion)

@spoicat5459

2 жыл бұрын

@@adarsh65kumar Perhaps learning the same thing from multiple teachers helps better, just a hypothesis though, it happens to me too. If I learn something from one video and don't get it clearly enough, I watch a different one on the same topic and it gives me a different perspectives on the same topic, making it a bit easier to understand.

I love you professor Dave, you know all about the science stuff and you made everything as easy as a piece of bologna sandwich ☺

@ericvaish

5 жыл бұрын

yeah yeah!!!!

@viper_3

Жыл бұрын

That's why "He knows lot about science stuffs Professor Dave explains" 🎶🎵

1 week of not understanding class into 4 minute video. thank you chemistry jesus

personally you deserve more subscribers and people need to see this.

@ProfessorDaveExplains

8 жыл бұрын

i tell myself that every day! pretty please tell your friends :)

@haidegee142

7 жыл бұрын

I agree!! Don`t worry, 1 quarter is worth more the 10 pennies. The people that subscribe seem to be very fond of you. Thanks a bunch.

@somalialnd4542

6 жыл бұрын

+Professor Dave Explains i don't understand

@Felishamois

6 жыл бұрын

+abdirahman abdilahi because more people watching this channel, which happens in my experience to be the best of its kind on youtube (yes, more appealing and discrete and comprehensive than Khan Academy), means more scientifically literate people, means better world 🙏

Limiting Reagents and Percent Yield are one of the most confusing topics for me in Chemistry. Thanks to you, I understand it better. This is really helpful for students like me. Thank you very much!

THIS IS AN AWESOME CHANNEL!! Please for the love of god don't stop making these videos! I need this so I don't fail chemistry!!!

@samisiddiqi5411

3 жыл бұрын

It's been four years. Did you pass?

@rafyraffee

3 жыл бұрын

@@samisiddiqi5411 Yes, Yes I did. XD

@thatsme6998

3 жыл бұрын

@@rafyraffee yayyyyyyyyy

I was here for my retake for a chemistry test, and I fell in love with these videos! Thank you professor Dave

Thank you Professor Dave for explaining this so well, I've got a final in a few days and need someone to actually teach me well. YOU ARE THAT MAN

literally speaking, i just stumbled across this channel looking for revisions before mah test but i was bowled over by the content and clarity of the video. u literally have earned a new subscriber... :)

Thanks to this video, I am seeing some light. The graphics add a transitioning touch to the relationships of the numbers we just can't quite see with erase markers. You are making a great difference.

Thank you so much! I wasted so much time on Kahn Academy confused as all hell, and you summed it up perfectly in less than 5 minutes!

@angeliahanaa

4 жыл бұрын

exactly!!!!!!!

This video is life saving, thanks tons for the explicit explanation.

Professor Dave has been my favorite so far, am enjoying everything.

Indeed your way of teaching is extremely easy to understand you actually deserve 10m or even more than that

This is perfect for studying for my grade 11 chemistry exam. Thank you Professor Dave!

@mgrn7106

2 жыл бұрын

How is college 😂😂

@electromc9295

2 жыл бұрын

@@mgrn7106 no cap you be doin this on the daily in intro chem classes

New subscriber here. Big thank you proffesor Dave for sharing these. It is indeed a big help to us students who are having hard time in understanding the world of chemistry. Peace Be with you.

this is such a great channel, thank you prof. dave!!!

Can I just say, you`re extremely helpful!! Thank you so much!! Keep up the great work, and know that you`re helping so many people, like myself. G-d bless you.

I'm a freshman in college and your videos are helping me so much!! :D thank you for these awesome videos!!!

Thank you for this. I now fully understand how to compute for the theoretical yield.

thank u i love u i was getting rly stressed out about my chem exam but this video SAVED ME all the other vids i watch sucked

Thanks for the brief refresher. I love you!

Hello Sir I am From Pakistan .Your videos are always helpful for me .Biology and chem lectures are admirable .Keep it up 😊

Probably the best thing I have ever subscribed to.. thank you.

This is enormously helpful!

Thank you for teaching me in 4 minutes what my teacher could not teach for the past few months

Great! with you Chemistry is so easy! thank you for your tutorials!

Thanks a lot for your explanations.

prof dave literally saves my life

I have an A in Chem thanks to you!! my prof honestly gives me no help

Thanks you helped me a lot !

thank you 🌸

Your explains is more than great Mr Dave 🖒🖒🖒🖒

Thank you professor dave. Because of your teaching skills my exam was easy

Awesome analogy...

you are saving my life gr11 Chem exam tomorrow and 0 idea what I'm doing

@SA-be1bn

3 жыл бұрын

howd it go?

@mohammedsulaimanmohammedal1512

5 ай бұрын

i need answers how did it go?

love ur expalnation so much..u help me a lottt, tq prof

Thanks for your explanation :)

Thank you very much professor dave 💓

fun mix of puzzles and math! this is fun! im getting the answers right as well!! woo!!! thanks dave!!!

you are a very good chemistry teacher

Thanks Prof. Dave..

woooooo hooooo I said my friends about your channel and they are just loving it!!

haha great! I use a similar example when explaining the limiting reactant to my students; sandwiches make for great examples!

I am come from Bangladesh. Really your lecture helped me

sir can you please a separate video for difficult questions of limiting reagents and tricks to solve them.

Thank you very much Sir.

Thank you for your vids prof

thank you 🌷

Great teacher

thank you so much.....

Thank you sooo much.😊☺️

Wow❤u teach well...I now understand chemistry ⚗️

thank you, professor you gave us, a clear explanation

@ChemistryTeacher-qz6vp

Жыл бұрын

This is ez stupid face try takin an art degree then tell me what's hard

Thanks!

You are amazing!!!

fantastic...How can I thank you .professor Dave

رقم افوغادرو 6.022×10²³ رقم ٦ هذا المقصود به كاربون . الكتلة المولية : العنصر × كتلته . C⁶ × 12 . عندما يحصل تفاعل كيميائي العنصر يتغير من جهة اليسار إلى اليمين اي النواتج ، لذلك يجب حساب مول جديد وهذه هي الطريقة : - قبل التفاعل الكيميائي البروبان × عدد المول / الكتلة المولية = المول . - بعد التفاعل الكيميائي المول × عدد المول الجديد / عدد المول القديم المول المحصول × عدد البروبان / عدد المول .

Very good!

thank you ssso mmuch

How do you do the last question professor dave?

thanks

Very nice explanation......in a small amounta time.... :)

thanks professor dave!

@ChemistryTeacher-qz6vp

Жыл бұрын

If I had $1 per everytime I called someone a stupid face I'd be rich

@tcg-astral

6 ай бұрын

@@ChemistryTeacher-qz6vpI think your the stupid face here 🤣🤓

Sir if u have time please try to make a video on equivalent concept in chemistry really hard to get feel and intiution of that topic I would be very very thank ful to you ( from India Telangana)

How did you get the mole in the problem???

Dammit Dave, that’s a glorious flowing mane you have

The final percent yield 89.3% is a little off because of a rounding error: 19.1 ÷ 21.42857 ≈ 89.1333% ≈ 89.2%. Don't round to sig figs too early in the process and you should be fine 😊

sophmore taking ap chem with no chemistry background. you made this much easier to understand, thank you!

Bruh how did I understand this in 5 minutes but not in a 2 hour class.😩❤️

quick question, when we getting the theoretical yield for CH3COOH, why we taking 21.4g as our final answer, not 21.42g. I went back and rewatch the sig figs chapter, but it still couldn't help me with the result. Thank you in advance for helping !

@valeriejackson7416

Жыл бұрын

its 3 sig figs so you wouldn't add the 2

someone please help why didn't we multiply ammonia with 2/17? because according to the equation its 2 moles of ammonia reacting right?

so for the same reaction, if i change the masses of the reagents, could the limiting reagent change? or is it always the same for the same reaction?

@ProfessorDaveExplains

5 жыл бұрын

yep it totally depends on how much you have of them!

Am I missing something or is the first conversion factor at 2:37 totally not equal to one?

Legend...

عاد يا بروفيسر ديف انت الزيك منو 😍..تتعلى ما تتدلى

Professor Dave is the best of the best... oooops

Khan academy took 20 minutes to explain what you did in 4 and yours is still better 💀

Do you HAVE to find out how much of both reactants can react with each other to subtract and find the excess.

@noelliekouedan6743

4 жыл бұрын

Well like the amount of excess

when converting to moles in the ex. in 1:45, why can't I convert between the substances after I have just the first substance in moles? and also why do I get different result while doing it in comparison to just calculating it separately? 10g NH3* 1 mole NH3/ 17g NH3= 0.588 moles NH3 0.588 moles NH3* 1 mole CO2/ 2 moles NH3= 0.294 moles CO2 --------while calculating separately will give me 0.227: 10g CO2* 1 mole CO2/ 44g CO2= 0.227 moles CO2

@user-me1pw6zh1w

10 ай бұрын

ok so the answer is because if I do that, I will get the amount of the other substance in moles that will theoretically react flawlessly with the first substance and not the actual amount of the substance. I don't know if anybody needs it but there you have it

holy shit bro ty

At, 3:59 is the chemical CO , Carbon and Oxygen or Cobalt?

@ProfessorDaveExplains

6 жыл бұрын

CO is carbon monoxide! All elemental symbols have just one capital letter, so cobalt is Co.

Molecular mass of ch4n2o is 16+24+16= 54 g/ molecular but how did 60.1g is multiplied with .227 moles ?? Please explain how did 60.1 comes

@ProfessorDaveExplains

6 жыл бұрын

it's the molecular mass, you miscalculated it.

Where were you the whole year good sir...

This is great work, but unfortunatley it would be nice if the problem showed how the understanding of dimensional analysis played a role. But other than that it helped me get to an answer!

@ProfessorDaveExplains

7 жыл бұрын

i have a separate clip on dimensional analysis, take a look!

Hi, professor Dave. May I ask you why the answer of the question is 89.3, not 90? I thought sig fig would be 1 since the one with the fewest sig fig is 100 (1 sig fig). Sorry if the question is too silly :( and I very apprieciate your well-made videos.

@jiinjung1445

4 жыл бұрын

if anyone else could reply to me, I would also very apprieciate.

Sir please please I beg your pardon infinite please video on equivalent concept in chemistry

why did you round two sig fig, when calculating?

@ProfessorDaveExplains

7 жыл бұрын

no reason, just to keep it tidy

Well i don't know how much he really knows since he reads off a prompter

if during the experiment, you only included 97% of grams of 1 of the reactants, would you still get the same substance you’re expecting? only that, you wont get the theoretical yield amount in grams? OR the whole experiment would be wrong because the expected substance wont happen?

@adr5617

3 жыл бұрын

oh wait!!! i think, we can still get the same substance for as long as we have the reactants necessary. the change in grams in the reactants does not affect the expected substance, only the amount in weight afterwards. please tell me if im right or wrong, Prof Dave. :) if im right or wrong, why or why not

@aldunlop4622

Жыл бұрын

@@adr5617 That’s right. Change the amount of inputs only affects how much of the product you get. In the bologna example, no matter how much you change the amount of bologna or bread, you always end up with bologna sandwiches.

how did you get the 0.454 moles of NH3?

@ProfessorDaveExplains

5 жыл бұрын

that's just seeing how much NH3 would react with the CO2 given the stoichiometric ratio

Guys pls someone explain how to find the actual yeild if not given

thank u chemistry jesus

Thank you, chemistry jesus

@ChemistryTeacher-qz6vp

Жыл бұрын

Shut up stupid face

Nicely done, you did not show which was the limiting reactant but it's CO

@ProfessorDaveExplains

7 жыл бұрын

i put a box around it!

@blinkeverlast718

4 жыл бұрын

but both ch3oh & co equate to 0.357 mol. im confused why you chose co as the LR. need clarification on this one prof. dave. thanks in adv.

Hows the limiting CH3OH not CO?

@ceeces

3 жыл бұрын

Idk

Prince Jemuel Labitad BSCE-1A

The molar mass came out to be 64 g/mole for CH3COOH, what did I do?

@ProfessorDaveExplains

5 жыл бұрын

I dunno! You must've counted wrong. You can email me your calculation if you want.

@aydencook03

5 жыл бұрын

Whoops, I see