How To Calculate Theoretical Yield and Percent Yield
This chemistry video tutorial explains how to calculate the theoretical yield and percent yield.
Introduction to Moles: • Introduction to Moles
How To Calculate The Molar Mass:
• How To Calculate The M...
How To Convert Grams to Moles:
• How To Convert Grams T...
How To Convert Moles to Grams:
• How To Convert Moles t...
Moles to Atoms Conversion:
• Moles To Atoms Convers...
Grams to Molecules Conversion:
• Grams to Molecules and...
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Grams to Atoms:
• How To Convert Grams t...
Moles, Atoms, & Grams Conversions:
• How To Convert Between...
How To Balance Chemical Equations:
• How To Balance Chemica...
Stoichiometry - Basic Introduction:
• Stoichiometry Basic In...
Avogadro's Number:
• Avogadro's Number, The...
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Limiting Reactant Problems:
• Limiting Reactant Prac...
Excess Reactant Problems:
• How To Find The Amount...
Theoretical & Percent Yield:
• How To Calculate Theor...
Percent Yield - More Examples:
• How To Calculate The P...
Percent Error:
• Percent Error Made Easy!
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Percent Composition By Mass:
• Percent Composition By...
Empirical Formula Problems:
• Empirical Formula & Mo...
Empirical Formula - Hydrated Compounds:
• How To Find The Empiri...
Combustion Analysis:
• Introduction to Combus...
Stoichiometry Practice Test:
• How To Solve Stoichiom...
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Not only did you saved me in high school, but now your videos continue to help me in university. Thanks for sharing the knowledge!
Thank you. You and Melissa Maribel really helped me in Chem this year. It's been killing me, hell it's been my worst class, but your making it somewhat bearable. Thank you again.
This video just helped me SO much with my lab report, I tried asking my teacher about this and she wasn't being very clear
This is *very* confusing. Can you do some more examples?
@yungwells6549
3 жыл бұрын
He basically found the no. of moles for the limiting reagent. Then multiplied by the number of limiting reagent moles by the molar ratio (for this question it was 1:3, my question was 1:1 to so it remained the same) then multiply by the molar mass of the product to give you the mass. He basically joined all the steps which confused me too. But I did it in 1,3 parts (2 part question) and it was easy for me. 1)Find no of moles of limiting reagent n = m/Mr 2)Check the molar ratio (1:1 it remains the same, if not multiple or divide according to the ratio) which gives you the number of moles of the product. 3)Find the molar mass of the product 4)Mass = no. of moles x molar mass, so multiple them to get your theoretical yield. 5)Calculate % Yield using the formula. You probably know by now but this may help someone else.
@basharibrahim2193
2 жыл бұрын
Thanks a lot bro 😊 I have exams tomorrow I was just told to learn this wish you success
I Just the way you do your work on this channel. Who can't understand like this sure? I had to create a channel due to your inspiration.
Hope i can get a great mark in the chemistry exam on coming Monday
@murk.mp4760
3 жыл бұрын
@FlappyBird Codes ikr medicine is so useless lmao
@bobsandwich2712
3 жыл бұрын
How’d you do?
@tunea4424
2 жыл бұрын
C'mon man. How'd you do?
@suhad1016
2 жыл бұрын
@@tunea4424 no one replies when anyone asks “how was the test “💀💀
@lanremoses5291
2 жыл бұрын
Me too pray for me yall
This helped me so much!! THANK YOU!!
Hi your videos really helped me from my freshman year to now my senior year, however i was wondering if there's a video that could help me solving this question : If 250 ml of 0.54 M HCl produced 1.01g H2O, what is the percentage yield of the reaction? CaCO3 + 2HCl --> CaCL2 + CO2 + H2O
Got my chem final Wednesday kinda nervous but this help
#Bhautikkanani Nice. ...!! Crystal clear explanation which very very help full in practical of synthesis of organic.....👍👍👍
Can I ask isn't it suppose to be 4O2 not 5O2??
how did you identify the limiting reactant and excess reactant? like the solving process???
@matiasignaciorocco3667
Жыл бұрын
say you have A+B=C, A is 15 and B is 10, there B would be the limiting reactant and A the excess reactant, I am not sure I was completly clear but hope it helped
There’s no need for converting grams to moles in this particular question. The ratio of C₃H₈ to CO₂ is 1 : 3 so 30 g of C₃H₈ will produce a theoretical yield of 3 x30g or simply 90g. To calculate percent yield do (70/90) x 100% = 77.8%. Same answer
If the problem includes a given value of temperature, do I disregard it or not?
@zachseaman4335
Жыл бұрын
If this is gen chem, probably disregard it. Implications of temperature on reaction rates are in Analytical chem courses. In that case, one may use temperature to calculate a different theoretical yield.
Tutorial for actual yield from scratch..? Please..! Thank you (if) in advance.
thanks a lot! this really help me
Professor Organic Chemistry Tutor, thank you for showing How to Calculate the Theoretical and Percent Yield in AP/General Chemistry. From the video and other reasons, the Actual Yield in a reaction is ordinarily less than the Theoretical Yield. Putting it another way, the Percent Yield is expected to be less than 100. This is an error free video/lecture on KZread TV with the Organic Chemistry Tutor.
Suggestion for A video; please make chemistry videos from the syllabus of IIT JAM exam.. One of the toughest exams in India.. Please..
@pkstudy349
Жыл бұрын
I think he already uploaded everything, look up any jee topic you want
Good video
Hope I can get great marks in chemistry test tomorrow
Can someone answer my assignment When 1.87g of aluminum reacts with 9.65g of copper(II) sulfate ( CuSO4), 3.65g of Cu was produced what is the percent yield of Cu If anyone got an answer Find this Person Hamada Maruteru
Can a percent yield be more than 100?
@ycremkiraguh8596
3 жыл бұрын
No
5:35
how did he get h20 when making the reaction
@theningsquared
10 ай бұрын
it's combustion, combustion produces water and carbon dioxide
Thank You.
THIS IS MY BESTIE FR YAAAS KING IM NOT FAILING TMR
Hello, can you please solve this question because I can’t understand how to solve it. The overall equation for one method of manufacturing hydrogen from methane is: CH4 + 2H20 -> 4H2 + CO2 In one batch, 5.12 tonnes of hydrogen is obtained from 13.6 tonnes of methane. What is the percentage yield of hydrogen for this batch? A)37.6 B)42.5 C)54.4 D)75.3
@RLN579
Жыл бұрын
Are you sure it's the percentage yield they're asking for, and not the Theorectical Yield? If its the latter, the perc yield is 13.72%, and the theoretical yield is answer choice A.
@kaiwoodlen730
Жыл бұрын
@@RLN579 it word for word on the text book
@jaeshiki
11 ай бұрын
the answer is D
what is the theoretical yield of Zn(s) + 2 AgNO3(aq) --------------- 2 Ag(s) + Zn(NO3)2(aq) NEED HELP.
@mohammedbadi3081
3 жыл бұрын
do u still
@dustincayron4640
3 жыл бұрын
@@mohammedbadi3081 nahh but thank you bro
ok so i’m super confused and i don’t know how to do this question i got for homework... sodium reacts with chlorine to form sodium chlorine. calculate the theoretical yield of sodium chloride, in grams, when 28.4g of chlorine reacts completely with sodium.
@haas9649
3 жыл бұрын
Hi, I know this is like super late and you probably got the answer by now, but first you need to write the chemical equation of the sum (Na+ Cl2 -> NaCl) and then balance it (2Na +Cl2-> 2NaCl), after that you just need to find the moles of Cl on the reactant side (moles= given mass/ molar mass, so that would be moles=28.4/35.45= 0.801 moles of Cl2) now that you've found the moles. You just need to use the mole ratio and find the moles of NaCl (the balanced equations says that 1 mole of Cl reacts to give 2 moles of NaCl, so 0.801 moles of Cl gives 2(2 moles of NaCl in the balanced equation) x0.801 (moles of Cl that youve found) which gives 1.602 moles of NaCl, from there on its just finding the mass of NaCl which im sure you can do on your own. Note: You dont have to use the method i used for the mole ratio, use which ever method you know best.
@nebulablitz1518
3 жыл бұрын
@@haas9649 you didnt start if off with hello there, disgraceful if you ask me
@haas9649
3 жыл бұрын
@@nebulablitz1518 ah shit. I'm ashamed of myself. I shall do better from here on.
@raniariffat8094
2 жыл бұрын
@@haas9649 hey, won’t it be 28.4/71 instead of 28.4/35.45? since there is a two subscript with chlorine. 🤷♀️
Good
When calculating you should say multiply by 100%, because mathematically that is incorrect. 0.50 x 100% = 0.50 instead 0.50 x 100. I say this because a lot of people will put the percent when multiplying and get the wrong answer because 100% is equivalent to 1.
He saves me every test but bros mic is picking up to much sound I can hear every mouth movement
i have a gcse tm and this is on it #sendhelp
Thanks for saving me from extra
Why tf did I take honors chem when I’m only in geometry rn 🥵
9:30
*homework* something that teachers to kill us (if you sit in the back you can get away not doing it)
Real shit
@murugananthamthangavalu4141
3 жыл бұрын
tf
@ahaadhussein3490
3 жыл бұрын
Ikr? You need a filter
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This left me disoriented tbh
This unit is so annoying bro omg