Gene Cloning - Past Year Questions | CSIR GATE
In this video I have discussed about Gene Cloning past year questions asked in CSIR and GATE entrance exams.
Please watch Gene Cloning Part 1 here - • GENE CLONING In Detail...
In molecular biology, cloning a gene means inserting the sequence of the gene into a plasmid, which is a small piece of circular DNA that can be "transfected" into a bacterial strain, where the plasmid will replicate to many, many copies. The plasmid carries an antibiotic resistance gene, so when the bacteria are grown in the presence of the antibiotic, only those bacterial cells with the plasmid in them, can multiply.
This allows molecular biologists to easily propagate and grow vast amounts if the gene, and also to manipulate it in many ways, for example to introduce mutations to study its function, etc.
Please watch this video for more detail. If you like this video please like and share this video, and don’t forget to subscribe and click on bell icon for new videos.
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#BaaYo
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Desperately waiting for your lecture .... haven't seen the teacher as u r❤️ love 💕
Thank you Ma'am. Please continue your lectures. Best wishes for you Ma'am.
Pls come up with more such pyqs as it is very helpful and off course the way u teach is amazing, I can quickly understand the concept.
Once again not related to my subject. However Understood the entire lecture. Teaching methodology is soft and based on deep knowledge. A lot of respect ma'am from Pakistan.
@BaaYo
2 жыл бұрын
Thank you
Glad to see you
Thank you so much maam🙏❤️
Thanks a lot ma'am
Thank you so much mam...
The answer to question no 11 is Option C. From the map we can see the the total size of the vector along with the insert is 3000+2000=5000bp(1kb=1000bp). When BAM H1 and Hind III cuts the construct we get one fragment of 500bp as it was told in the question that the insert has a Hind III site at 500bp downstream from its first codon and the Bam H1 site is at the beginning of the insert. So we get a band at 500bp and another band at 5000-500=4500bp=4.5kb which is in option C. And in case of Hind III and Pst1 digestion we first get a 1500bp(1.5kb) length band as Hind III site is 500 kb upstream of the first codon and Pst1 site is at the end of the insert. And the total length of the insert is 2000bp. So the band length should be 2000-500=1500bp=1.5kb. The other band will be of 5000-1500=3500bp=3.5kb in length. In the options C justifies all these. So C is the right option.
@diksha_vlogs_N_shorts
2 жыл бұрын
Very well explained
Seeing you after 1 years
Thanku sooo much mam ❤️❤️❤️
Very nice mam
Maim you're just awesome as always and gorgeous too
Very nice ma'am 👌👌👌👌
@BaaYo
10 ай бұрын
Thanks a lot
Thnk u mam
Question no : 11 3 c
@Thesiblingshow4
2 жыл бұрын
Well done
Ma'am for GATE chemistry what should I do?.
Osm
Answer for question with gst fusion protein is option 3, that's C clone.
@BaaYo
2 жыл бұрын
perfect
Ma'am theory bii continue rhenge na
@Thesiblingshow4
2 жыл бұрын
Yes
Option c
11 no question answer C
The answer is C clone. Where h+b 0.5 and h+p is 1.5
@BaaYo
2 жыл бұрын
perfect
Last ka option 4 incorrect hoga
Ma'am aapne unacademy kyu choda
@Thesiblingshow4
2 жыл бұрын
Dec se start hoga