Finding Vertical and Horizontal Asymptotes of Rational Functions
This video steps through 6 different rational functions and finds the vertical and horizontal asymptotes of each. A graph of each is also supplied. On the graph, the function is a black solid line and its asymptotes are green dashed lines.
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I HAD NEVER UNDERSTOOD THIS EVER UNTIL NOW. THANK YOU.
@sarahjanetanedo1100
2 жыл бұрын
Hahahahhaha me too 😂😂
OUR EXAM'S ARE TOMORROW. ITS 3AM AND I LOVE U
@thanossmith1126
5 жыл бұрын
Same
@evanyoung6993
4 жыл бұрын
I have a test tomorrow 😳
@andaleebkhanmarwat7589
3 жыл бұрын
I like you because your question,s is so easy
@chris-8597
3 жыл бұрын
Mine is in 30 minutes lol
@kieronrana5233
3 жыл бұрын
good thing it wasn't an english exam
Dude you are amazing i didn't get it till i saw this. God Bless You sir.
dude i love you for this no place has vertical and horizontal together thanks a lot
You're the best! I've watched too many tutorials on this, they're all confusing af
my man saving my points at school.
Thank you so much! Best tutorial on this topic I've found yet on youtube :)
thnk you im gonna cry
@theeargasmchannel
5 жыл бұрын
Honest mood
Thank you. Every other source was explaining this so poorly. You nailed it.
Dang he should earn 1m subscribers than 1k something. This dude teaches greaterthan my professor!
YOU ARE ABSOLUTELY AMAZING!!!!!! after searching for hours I come across this masterpiece and it literally saved my life. I cannot thank you enough..
u just explained that better than anyone on the internet and i love u for that
Just to add, I also enjoy your guitar picking and the songs in your videos!! Thank you!
Thank you for teaching this clearly! Really understood it better! 😊
Thank you! James This will help me to get quickly V.A and H.A in MCQ without wasting time on differentiating....
Thanks for you video! Great explanation ! I understood everything thanks to you!🙏
amazing video! super clear and easy to follow
Couldn’t explain it clearer, great job on demonstrating these examples, I was able to understand on mute due to my location at the time I couldn’t turn up the volume
Thank you so much for showing this example of asymptotes. It made learning so much clearer. I am now looking to solve Oblique asymptotes, but cannot find your video for that? Do you have one? Also, I am so thankful you have the Vertex and other functions in your teaching videos. Your videos will get me through this college algebra!! Thank you again.
Excellent video. So helpful and succinct!
thank u!! Finally someone covered all the examples!
@hsmathsolutions
3 жыл бұрын
Glad it was helpful!
Thanks ... you taught this topic very well 👌
Thanks I’m so grateful!!
DUDE YOU ARE AMAZING YOU JUST SAVED ME!
U have no clue how easy you made life for me. THANKYOUUU.
@hsmathsolutions
3 жыл бұрын
I'm glad I could help!! :-)
Thank you man. You save my life.
Thank you so much! Much more helpful.
Thank you, James!
Thank you soo much for this video dude. Really helpful
Thanks so much for the video! Have my Maths exam in 2 days and I didn't understand this until now!
Easy, well explained and a nice variety, thanks man!
Very clear explanation. Many thanks sir
Thanks, this actually HELP a lot
Thanks, I finally got it, thank you sooooo much!!!
Thank you James!
wow the only video i understood. thank you
thanks so much. That was very helpful. ✌
This video is simply very helpful for my homework
Thank you for this sir!
Very helpful, appreciate it.
Great explanation!!!!!
thank you this helped me a lot in my calculus
Best video ever may you stay blessed bro✌🏻
thanks for wonderful explaination buddy♥️ easily i understand it, i love it bro
Please Tell How to Plot this on Graph
Amazing explanation
Thanks! U are the best
THIS VIDEO SAVED ME
Thank you so much!!!
How do you know how to graph these lines (functions) within the multiple vertical an horizontal asymptotes?
We give values to hole equation or only x-3 for graph
It became too easy now really Thank you soooooooooooooo much ❤️❤️
Thank you so much sir!!!!
Dude after so long I got a high score in my math worksheets thanks to youuu
@hsmathsolutions
3 жыл бұрын
Awesome! I'm glad I could help!
Yeah it's my summative exam tom and this is the Coverage for summative assessment. Gen. Math: asymptote problem solving involving rational equation(motion and number problem), exponential equation, exponential inequality, exponential function, logarithms and logarithmic properties. Pre cal: Systems of Non linear equation Series and sequence Sigma notation Fundamental identities
@hsmathsolutions
3 жыл бұрын
For your non-linear systems needs... kzread.info/dash/bejne/mZx_pqmCeNjWibg.html
Thank you very much
Thanks alot, brother!
@hsmathsolutions
2 жыл бұрын
You're welcome. Glad it helped!
Thank youu soo much ♥️♥️
4:48 I have a question, if shouldn't you factor out the numerator and the denominator first and cancel out (x+2), which would be a hole?
@hsmathsolutions
7 жыл бұрын
Thank you for your question. In that example, the numerator is prime and will not factor; thus no terms will cancel out. But you are right, if it did cancel, there would be a hole instead of an asymptote. Also, you can take a look at the graph for confirmation.
@joycexie8537
7 жыл бұрын
Ohh.....I see it now! There would be a middle term if the numerator were to be factored into (x+2)(x+2) I was not looking carefully XD Thanks for replying.
love u helped alot
thanks so much sir
Thank you so much
THANK YOU
Fyi x^2+1 can be factored, but it's factors are not on a real number graph.
Thank youuuuu ♥️
I wish it could help me. Thank you!
what makes the fraction rational?
May god bless you... Amen!!!
Why did you equate the denominator to zero in case of vertical asymptot?
Thank you
Thank youuu!!!!
I mean in 1:55 why is the curve on the Quadrant 1 and not on Q2? Then the curve on Q3 not on Q4??????
Hi! can i attach the youtube link of your video to the self-learning modules of our department in order for the students to learn more from the contents of this video aside from the modules that will be distributed to them? Thanks a lot.
@hsmathsolutions
4 жыл бұрын
Lemuel Castillano Yes. Sounds good.
Thanks ❤️
Professor, good morning. You no longer posted math classes. I haven't received notice of his posts in a long time. (Brazil-RJ)
Outstanding
Thank u sir
nice work
thanks dude
On 1:55 why is the curve on the upper right corner? Cant it be facing the left? And the other one to its right???
@iateallmypasta885
4 жыл бұрын
lexine potter 🗿
I LOVE YOU.
Thank you I was so lost
this is brillliant
What about vertical and horizontal shifts
Not me getting ready for my.exam on the bus
Nice video
i hope u r our math teacher, cos we just finished midterm exam, and no one passed the examination ☹️
We just not gonna talk about how he's doing all his math in pen?
Well explained 👍👍
@hsmathsolutions
3 жыл бұрын
I'm glad it was helpful! :-)
@Biswajit_G
3 жыл бұрын
@@hsmathsolutions sir I just checked most of your video all are very well explained.❤️❤️ Love you Sir from India ❤️
@hsmathsolutions
3 жыл бұрын
I'm glad you are watching my videos and finding them helpful! Be sure to share them with your classmates!!
i don''t understand one thing, my professor uses limits to find them and no matter how many videos i look up they all use this method, am i missing something?
Ty
love you
Nice shortcut
Tack!!!!!
Thnxxx
what if the function doesn't have a denominator? fx= x+3x+7??
@hsmathsolutions
2 жыл бұрын
If the function doesn’t have a denominator, then there will be no asymptotes. Vertical asymptotes arise from division by zero. Without a denominator, there cannot be division by zero. Horizontal asymptotes arise from comparing the degrees of the numerator and denominator. Again, if there is no denominator, then there is no horizontal asymptote. Hope that helps!
Thanks from pakistan
05:41 Actually, there's one more asymptote in this example: y = x² + x + 1. If you add it to your graph, you will see that the branches of the curve approach this parabola as `x` increases/decreases without bounds. 06:18 Well, at least not in the plane of the graph ;>
@AadityaChawla-bc4ic
3 жыл бұрын
I don’t understand can you please elaborate.
@bonbonpony
3 жыл бұрын
@@AadityaChawla-bc4ic Start with the rational function from the video: `y = (x³+2) / (x-1)`. Divide out the numerator `x³+2` through the denominator `x-1` (e.g. using polynomial long division) to get the polynomial part `x² + x + 1` and the remainder (which is still rational) part `3/(x-1)`. In other words, you get the following decomposition: y = (x³+2) / (x-1) = x² + x + 1 + 3/(x-1) Now observe what happens when `x` increases (or, for that matter, decreases) without bound: the denominator `x-1` in the last term (which is still rational) gets bigger and bigger, which means that you divide the numerator `3` into more and more parts, so each such part gets smaller and smaller, i.e. the entire fraction shrinks to 0, leaving just the polynomial part `y = x² + x + 1`, which is a formula of a parabola. This means that as `x` gets bigger and bigger (either positive or negative), the graph of this function starts looking more and more like a parabola `y = x² + x + 1`. Here's a graph that demonstrates it: www.desmos.com/calculator/kjs0e3ivya Notice how the blue curve approaches the red parabola as `x` gets more and more negative. But when `x` becomes more and more positive, approaching `x=1`, the curve gets farther from the parabola and starts approaching the vertical asymptote (which is a straight line) instead, `y` going towards `-∞`. Then it returns on the other side from `+∞` and starts diverging from the vertical asymptote and getting closer and closer to the parabola again as `x` increases even further (as well as `y`, going towards `+∞` again). You can also turn the green graph on or off to verify that these two formulas, `y = (x³+2) / (x-1)`, and `y = x² + x + 1 + 3/(x-1)`, are indeed the same function. Also try zooming the graph in/out with your mouse wheel to observe how the graph approaches the straight vertical line as well as the parabola as `x` gets bigger (disregarding its sign) without bounds.
@himlolo
2 жыл бұрын
You like mlp you don’t know math
@bonbonpony
2 жыл бұрын
@@himlolo Oh yeah? Then try me.
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