shows how to analyze a pumping test using equations developed earlier
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Пікірлер: 13
@geoninja30945 жыл бұрын
wow, I amazed. just found profound yet practical hydrogeology channel on youtube.. thankyou for sharing and keep it up mister.
@victorkamemba50095 жыл бұрын
It is a nice information on test pumping works on groundwater development. Keep it up, sir.
@SSSISIable3 жыл бұрын
GREAT!! Thank you!
@saifal-saadi46108 жыл бұрын
very very useful , thanks
@engineerunknown8 жыл бұрын
Hey Larry, thanks for the videos. They are really making me understand hydrogeology better. I have a question about your draw-down value and subsequent efficiency calculation. Based on the graphs and the data table, draw-down at 1000 minutes is 20 ft not 90 ft, which would make the efficiency over 1. Could you elaborate on where the 90 ft came from?
@andrewtayong55793 жыл бұрын
Excellent Example. Thanks for filling my knowledge gap as a Sanitary Engineer who needed hydrology to meet the water need challenges. But how do we calculate S where there is no monitoring well?
@lcmurd1
2 жыл бұрын
Good question, Andrew. If you use the method in the video with r=well radius, you typically get a non-physical result--S>1. This is because storage in the well is not included in the solution. There are other solutions that include the well bore itself, and they should give you better results for S, but I have not tried doing this so I am not sure how well it will work. I have always used data from a monitoring well (or measurements of deformation) when estimating S. Larry
@kriskern34705 жыл бұрын
Where does the 0.183 come from in the Transmissivity equation? What is it? Thank you for your help
@lcmurd1
5 жыл бұрын
That is from combining the other numbers in the equation.
@dinofava6 жыл бұрын
what if we dont have stream nearby and dont have L? Anyway great video!
@salahnofal26915 жыл бұрын
Thank you very much ! very nice ;). I would like only to verify something please. I calculted the expected and it gave 90 ft ! so the efficiency is 1.
@lcmurd1
5 жыл бұрын
HI Salah, The calculated drawdown should be 65 ft. The observed drawdown is 90 ft. The observed drawdown is greater than the calculated drawdown because of head losses in the vicinity of the well. This causes the well efficiency to be less than 1 because it is the ratio of the calculated to the actual drawdown. Hope that helps. Larry
Пікірлер: 13
wow, I amazed. just found profound yet practical hydrogeology channel on youtube.. thankyou for sharing and keep it up mister.
It is a nice information on test pumping works on groundwater development. Keep it up, sir.
GREAT!! Thank you!
very very useful , thanks
Hey Larry, thanks for the videos. They are really making me understand hydrogeology better. I have a question about your draw-down value and subsequent efficiency calculation. Based on the graphs and the data table, draw-down at 1000 minutes is 20 ft not 90 ft, which would make the efficiency over 1. Could you elaborate on where the 90 ft came from?
Excellent Example. Thanks for filling my knowledge gap as a Sanitary Engineer who needed hydrology to meet the water need challenges. But how do we calculate S where there is no monitoring well?
@lcmurd1
2 жыл бұрын
Good question, Andrew. If you use the method in the video with r=well radius, you typically get a non-physical result--S>1. This is because storage in the well is not included in the solution. There are other solutions that include the well bore itself, and they should give you better results for S, but I have not tried doing this so I am not sure how well it will work. I have always used data from a monitoring well (or measurements of deformation) when estimating S. Larry
Where does the 0.183 come from in the Transmissivity equation? What is it? Thank you for your help
@lcmurd1
5 жыл бұрын
That is from combining the other numbers in the equation.
what if we dont have stream nearby and dont have L? Anyway great video!
Thank you very much ! very nice ;). I would like only to verify something please. I calculted the expected and it gave 90 ft ! so the efficiency is 1.
@lcmurd1
5 жыл бұрын
HI Salah, The calculated drawdown should be 65 ft. The observed drawdown is 90 ft. The observed drawdown is greater than the calculated drawdown because of head losses in the vicinity of the well. This causes the well efficiency to be less than 1 because it is the ratio of the calculated to the actual drawdown. Hope that helps. Larry