Thank you for making free education possible to so many people. I was fortunate to have KZread recommend your channel based on some “past searches algorithm”. I have been searching for decent basic electronics series for some time and I am unsure why it took so long to find yours. At last I feel like I can settle in on your channel and prepare to do some learning with linear, progressive, quality presentations.

Very well explained, likewise all the other topics. It makes reasoning and understanding the circuitry involved so much easier than other tutorials I have seen.

Sir. Your lecture is AMAZING!!!

thanks doctor I am taking circuit one and for some reason they let a rockie teach us the introduction and the basics of all our career . if it was not for you I would of been completely lost . thanks a lot

I found it interesting with this example to put in different values for the load resistance and work out the currents and voltages with the extra loop included. If the load resistance is in the range 1 to 10 ohms, the voltage across the load resistance is in the range 3.53 to 9.68. The load resistance needs to be much larger than 6 ohms for the voltage to be close to 12 volts. (load resistance 100 ohms, voltage 11.72 volts load resistance 1000 ohms, voltage 11.97 volts)

@Ottmar555

8 жыл бұрын

That would be correct. That is the reason why a voltage divider is usually applied for measuring purposes. Let's say you have a ~1000 V voltage drop you want to measure, but your multimeter can only handle about 100 Volts. Then you could use a voltage divider to safely measure the voltage across your circuit, given known resistances. This means that a voltage divider needs to have 0 current drawn through its terminals, otherwise it won't work accurately. If you want to have a lower voltage source, you'll want to use a linear voltage or a switched-mode supply.

Thank you, Professor! Such a great explanation! ❤️ from 🇧🇩 Bangladesh

@MichelvanBiezen

2 жыл бұрын

Glad it was helpful. Welcome to the channel!

you are just amazing. i dont know what i would have done without you.i always struggled with the electrical component in physics back in highschool and i was wondering how in the world i was going to manage in college .thanks a lot i owe you a life!!

Very good explanation, all the other videos made no sense to me

Great video Sir. But how about if we got fo 4 resistors...and can I apply 10 percent method or beader current approach ..thanks v much.

Can anyone tell me how adding offset voltage to an ac signal with voltage divider and capacitor works?

BUT, if you add a load with it's own resistance, won't that be in parallel with R2, lowering the resistance for the R2- R-load equivalent?

@MichelvanBiezen

2 жыл бұрын

When a load is attached to any circuit it will definitely affect the circuit

thank q sir

Curious what would happen if we had two loads, one hooked up to the 20V node and one to the 12V node. How would the current be distributed? Presumably we would need to do KVL loop and node analysis?

@MichelvanBiezen

Жыл бұрын

Yes indeed. Each circuit needs to be evaluated using the Kirchhoff loop equations and current rules.

Hello Again Dr. Michel, my question is for a series resistors there should not be a node attached between them!! so if we have a node between them like this example will be a parallel connection not a series any more! Am I wrong?

@MichelvanBiezen

5 ай бұрын

The two resistors in this video are in series.

Hi, does the formula at the end apply for more than 1 resistor on the circuit

@MichelvanBiezen

7 жыл бұрын

You may find your answer in this playlist: PHYSICS 41.1 RESISTORS IN PARALLEL BRANCHES

by RL you mean we can replace the R2 resistor with a circuit element which needs 12 volts and 2 A to work right? (and also one which have internal resistance equal to 6 ohms???? isnt that so?

@jeffsam5495

6 жыл бұрын

we cant keep both 6 ohm resistor and RL in parallel right ? or can we?

@MichelvanBiezen

6 жыл бұрын

That is correct, except the 6 ohm is not the internal resistance but the resistance needed for the voltage divider (to place 12 volts across the load)

@jeffsam5495

6 жыл бұрын

Thank you sir :)

Why couldn't you use the voltage across R1 for the load resistance? Alternately, why couldn't you eliminate R2 altogether and just use the voltage that dropped across R1 alone for RL?

@MichelvanBiezen

5 жыл бұрын

There are usually multiple ways in which you can solve a problem

hello professor , if you have two currents in inverse direction an you still use the voltage divider?

@MichelvanBiezen

2 жыл бұрын

Yes, the direction of the current doesn't matter.

I DON'T UNDERSTAND one thing: If the voltage drop across R2 is 12V, how is it that the SAME DROP will be present when the load resistance is applied? The load resistance RL and R2 are in parallel together and hence their equivalent resistance is lower than either of them. Because of this, the current in the circuit will increase and the voltage drop across R2 will change. After analyzing this circuit, I've come to the conclusion that the relation will hold true APPROXIMATELY only when the load resistance is MUCH higher than R2

@MichelvanBiezen

6 жыл бұрын

The voltage drop across parallel branches is always equal.

@SoumilSahu

6 жыл бұрын

That is true, obviously. What I don't understand is that when the RL was absent, the drop across R2 is 12V , BUT when RL is introduced, the drop across both RL and R2 will be same, BUT IT WILL NOT be 12V. Unless, RL is either very large or the current through RL is very small(This is what I concluded through my analysis)

@MichelvanBiezen

6 жыл бұрын

Now i understand your questions, and yes, you are correct. The load you connect to a circuit will indeed affect the circuit as you indicated.

@SoumilSahu

6 жыл бұрын

Thanks for the clarification!

@knightlight1018

3 жыл бұрын

and now, How to find the resistance of RL if the given are V, R1 and R2? help please

thanks for the video ..

@MichelvanBiezen

2 жыл бұрын

You're welcome

Thank you sir

@MichelvanBiezen

3 жыл бұрын

Welcome

Thanks

@MichelvanBiezen

2 жыл бұрын

Welcome

If the power of those resistors less than 40 watts, the the power supply would burn your circuit.

you have not taught us anything about how grounding affects a circuit

why the resistors are in series? there are some nodes and wires between them no?

@MichelvanBiezen

5 жыл бұрын

if there is only one path for the current, then the circuit is in series. if there is more than one path for the current, the circuit is parallel

@karinabuhaya5878

5 жыл бұрын

@@MichelvanBiezen I understand now, thank you :)

Why not use 1 resistor in series and bring the voltage down by putting the resistor in series with the load

@MichelvanBiezen

6 жыл бұрын

This is just for the purpose of illustration, not on how you should build a circuit. However there is a purpose for this particular type of circuit.

@johansmit4071

6 жыл бұрын

Ok. Yes thanks. I know in a simple aplifier cuircuit you wil use a voltage devider

Why does it have to be connected to ground?

@Ottmar555

8 жыл бұрын

To have a convenient reference point, as far as I understand.

@allisonscanlan4144

5 жыл бұрын

Voltage is the potential difference (aka the work needed to move charge form A to B) charge wants to move to a less energy state, but can only do so if that exists which brings in the ground.

Super sir