You got the right answers but when resistors are in parallel. The formula will be (1/2 +1/6)^-1 and for current division you u put the total parallel equivalent over the resistor. Times the source current. That's way you see that there's let current flowing throu the 6ohm resistor since it's larger.

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@kentrell7702

5 ай бұрын

The current of the 3 ohms is rather 7A… I’m sure that was just an oversight

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@richardkel7787

8 ай бұрын

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@dougtougaw7681

5 жыл бұрын

Glad to help!

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@dougtougaw7681

3 жыл бұрын

So glad to help! Good luck in your class.

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Why doesnt the resistor 5ohms make any difference? Why is it idle? So cant we just remove that one from the circuit?

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in 4 example, what if I need to find voltage on 8 Ohm? I need to take 8 Ohm or 10 Ohm?

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Sir! Can you please do videos on single phase ac circuits and complex problems in it

shouldn't I2 equal to Ix in the second example since they are in the same loop ?

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Resistors are in parallel. Don't they combine different since they are not is series ?

The current of the 3 ohms is rather 7A… I’m sure that was just an oversight

good!

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3 and 7 resistor are parallel

giving 10^2 out of 10 :D thx

Why is that we take R2 instead of R1 to solve for I1 in this case and vice versa?

@dougtougaw7681

5 жыл бұрын

Nick, Think about it this way: Current will always tend to follow the path of least resistance. If we make one path harder to follow, then more current will flow along the other path. That's why R2 appears in the numerator of I1: The larger R2 is, the larger I1 will become. Similarly, increases to R1 will increase I2, all else being equal. Hope that helps!

At 3:00 minutes (second problem) why is only 5 ohms and 2 ohms adding together but 5 ohm and 3 ohm are not added?

@-.____________________________

5 жыл бұрын

Because the 5 and 3 are in parallel. You add together resistors that are in series (on same line)

In question C why 6A is divided by 2 i didnt got that?

@dougtougaw7681

5 жыл бұрын

The 6A is being divided by two completely equal paths, each of 8ohms. By symmetry, half of the current flows into each path. Or, you could use the current division equation, which says that Ix=6A*(8/(8+8))=6*(1/2)=3A.

What is the current source in the middle in the ciruit?

@hii1479

4 жыл бұрын

What if*

hi..i still cant get why we put 20 ohm as numerator in last equation..

@dougtougaw7681

6 жыл бұрын

When using current division, the numerator is always the resistance of the branch we are NOT considering. Here, we want the current in the rightmost branch, so the numerator is the resistance of the left branch.

@sakaiyuji3074

6 жыл бұрын

Doug Tougaw Thank you mate :)

Can we use source transformation in this?

@dougtougaw7681

4 жыл бұрын

Yes, you definitely could. It might be more work than using current division, but it will give the same answer. One of the best parts of circuit analysis is that you can use many different tools to obtain the same (correct) answer to a given problem.

Thank you