Current Dividers Explained!
This physics video tutorial provides a basic introduction into the current divider circuit. It explains how to calculate the current flowing through each resistor in a two resistor parallel circuit using a simple formula given the total current entering the circuit. It also includes examples with a parallel circuit with three resistors and one with four resistors in parallel. The voltage across each resistor in a parallel circuit is the same and the currents flowing through each branch must add to the current entering the circuit based on kirchoff's current law / junction rule. This video contains plenty of examples and practice problems for you to master this concept.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
How To Solve DC Circuits:
• How To Solve Any Resis...
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Voltage Divider Circuit:
• Voltage Divider Circui...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
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KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Norton's Theorem - Circuit Analysis:
• Norton's Theorem and T...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
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Final Exams and Video Playlists: www.video-tutor.net/
Been using his videos for all my uni classes and honestly what an absolute genius. It really takes a lot of skill explain EVERYTHING so clearly and concisely. Absolutely impressed.
You deserve much more credit than you're given. You have helped me with nearly every subject I've taken in a very sensible and cohesive manner. Keep doing what you do!
@G12eem
Жыл бұрын
Which subjects do you study?
@kennedymukwakwa
8 ай бұрын
Can you please come teach us at the university of Zambia 🙏
How Current Divider Formula is derived: In parallel, the voltage across the two resistors is the same. Thus, V1 = V2. And we know V1 = I1 * R1 & V2 = I2 * R2. Thus, I1 * R1 = I2 * R2. Also, Sum of I (in) = Sum of I(out) as in Kirchhoff's Current Law, thus, I (total) = I1 +I2. We know have two simultaneous equations: I1 * R1 = I2 * R2 .................... (i) I(total) = I1 + I2 ..................... (ii) If you sustitute I1, you get the formula to find I2: I2 = I(total) [(R1)/(R1 +R2)] If you sustitute I2, you get the formula to find I1: I1 = I(total) [(R2)/(R1 +R2)] Hope this helps!
@vanshkhoshya3297
4 жыл бұрын
Thanks
@memesop8812
3 жыл бұрын
Who asked for it
@raed9152
3 жыл бұрын
@@memesop8812 STFU he is trying to give more help
@arki3134
3 жыл бұрын
@@memesop8812 your mom
@memesop8812
3 жыл бұрын
@@raed9152 toh muhmelele uska usko bhi return me help ho jayegi
The most comprehensive CDR tutorial video yet! You generally explained at every inch and all of the plausible techniques we can use other than merely CDR!
This is probably the best hands-on explanation I've seen.
@DanielInfrangible
3 жыл бұрын
Fact
@paarthjagga7287
3 жыл бұрын
Facts
This is probably the best hands-on explanation I've seen. THANK YOU SO MUCH!
It is so simple when it is explained masterly by you! Thanks!
Thank you so much guys. You don’t know how much your videos mean to me . Sometimes I feel so sick..like I can’t understand anything..but your videos help me understand that..I’m not actually dumb. Thank you so much 👏
Such a wonderful way of presenting this. Great job!
Duuude, thank you so much My teacher literally gave me the wrong formula for this, i knew that something was wrong because the value for each individual resistor didn't add up, but I didn't know why. You just saved me
For anyone wondering an easy formula that works to find the current at any point in a parallel resistor circuit is: I(n) = I(T) * [ R(eq) / R(n) ] Where I(n) is the current through the resistor n I(T) is the total current before the parallel split R(eq) is the equivalent resistance of all in parallel which is just 1/R(eq) = 1/R(1) + 1/R(2) + 1/R(3) ... R(n) is then the resistor you want to find the current I(n) flowing through. This works for 2,3,4,...,∞ parallel resistor circuits.
You explained way better than what my lecturer is teaching in class.
Thank you so much for such a simple, easy on-point explanation.
La mejor expresión que he podido encontrar y la más fácil, gracias hermano eres un verdadero profesional tus explicaciones son verdaderamente entendibles.....Felicidades....
So anyway...I have this “self-teaching” pdf on electronics and it complicates this WAY too much on the basic level....👍👍 to you! Thank you!
I've seen this guy teach all the subjects im studying , i can tell from his voice
After 2:14 it all clicked for me thank you. The intuitive method also was very very useful in grasping the concept and application. 👍🏻👍🏻
The thumbnail video alone made more sense than what my professor tried teaching in half an hour. Thank you! It's clear now.
@cheatyhotbeef2636
Жыл бұрын
but the thumbnail is wrong though
That's what I really searched for. Thanks man❤
i spend all day in this channel because i have exam after few hours and realy thanks man i appreciate ur effort
What an amazing video. God bless you 🙏.
You're really on the next level
Gracias hermano usted no enseña para que uno aprenda solamente, usted enseña para hacer expertos ....😀 muchas gracias hermano ...
Excellent CDR tutorial 💯
Thanks for the (1/r1) / ((1/r1) + (1/r2) + (1/r3)) form. That seems to me the most self-explaining form of the relationship.
Neat and clean. Thanks
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Thank you very much. Was a great help
This guy is really wonderful ever since
thanks man this make sense
Thanks for sharing it
thanks. this was so helpful.
how can i thank you mate !!!! you really made it easy for me to understand . may you prosper in life . love from pakistan
Great video thanks.
I cannot begin to tell you useful this tutorial is. My McGraw hill textbook is so confusing😅
You make everything easy
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The best explanation thanks
Thank you so much.
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thank you chemistry teacher
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Thank you.
alright finally got it!
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Short and sweet❤
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Hey man, something i noticed with this video that messed me up for a while is that the equation in the thumbnail is actually wrong and is inconsistent with what you say and show in the actual video. In the thumbnail you write “I1= R1/(R1+R2) *Is” meanwhile the actual equation should have R2 in the numerator instead of R1 when solving for the current I1 at R1. Other than that typo, great video
@ceeb830
Жыл бұрын
I searched up the rule on Google while doing my hw and used this thumbnail because OCT has lots of credibility with me, it really messed me up for a while 😅
@jadynjc
Жыл бұрын
@@ceeb830 glad i'm not the only one who did that lol
@lance4377
5 ай бұрын
Hes correct but it only applies to 2 resistors. The one with the improper fractions is more universal
legend, thanks cobba
Thank you
THE GREATEST OF ALL TIME ###
Good .......excellent 👍🏻
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How can I resolve a problem with bridge circuit using this method, and the voltage divider method. I want to calculate the Vx and Ix
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kindly explain how are we supposed to know which formula should be used as there r 2 diff formulas
Give this guy a nobel prize
Amazing , but i hope you explain thevenin's theory
So does the current automatically divide itself in the correct way to be available to loads with different resistances?
Thanks
I'll send you my diploma once I've graduated, you deserve it at this point
A much easier way to do this is by finding the total resistance, then find the voltage accross the parrellel resistors, and then just use I=V/R to find the currents
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@fiona.e1026
3 жыл бұрын
2 million now
Thankyou
Thank you so much, but were would you connect the load
@VultureGamerPL
3 жыл бұрын
We assume it's connected to both ends. It doesn't have to be drawn everytime.
Nice lcm trick
Thanks to you i could be a good engineer
Please what if you have résistance in both parallel n circuit
So whats the general formula?
Y tu Inglés esta muy clarito hablas perfecto el ingles....thanks...
What about when we have some in parallel and some in series
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There’s a mistake in the thumbnail for the equation containing 2 resistors! Should be I1 = I(R2/(R1+R2))
Why you put r2 in the first situation instead of which it need I1 and in the second situation you put r2 when he asks you for I2
What a god!
why did he use 1/R1 in the second example instead of R1 alone?
@shr3anko31
3 жыл бұрын
That's a special case for only two resistors
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Ohww wiw ❤
why do you have different formula for different circuits? arent they both parallels? can you apply the second formula to the first circuit?
@aybuke2534
5 жыл бұрын
Yes,you can apply.
@mavihs26
4 жыл бұрын
@@aybuke2534 how
sir what if we are to take two sources of amps going to one resistor?
@thomasgarity1737
2 жыл бұрын
sum together the current sources because of kcl
Pls derive the current devider rule and to make this video different
bro tomorrow is my exam and you helped me alot today// thanks
app names please
Topics which you study in university we study it in 11th grade in India
What if there are 2 independent current
How come I see people say the equation is total current*(total resistance/resistor x)? Here you have total current*(resistor x/total resistance.
@AndrewChedid
5 жыл бұрын
the first formula I*Rt/Rx is for conductance, here he is doing the inverse of resistance which is the same as the I*Rt/Rx. He just did it as I*(Rx)^-1/(Rt)^-1.
your thumbnail is incorrect, at least for the two resistors in parallel
@eddiesayo
Ай бұрын
made you click thou?