Design of Reinforced Concrete Solid Slabs (Part 3) - Continuous One-Way Slab - Worked Example
Design of reinforced concrete slabs using BS code (Complete Solved Example - Continuous One-way Slabs). British Standards BS8110.
(تصميم البلاطات الخرسانية باستخدام الكود البريطاني (الجزء الثالث
The links of other important videos are given below:
- Stress-strain curves for concrete and steel:
• Stress-Strain Curves o...
- Analysis of RC sections according to the BS8110 code: • Understand Reinforced ...
- Design of singly reinforced rectangular concrete sections: • Design of Singly Reinf...
- Analysis of singly reinforced concrete rectangular sections: • The Capacity of Singly...
- Design of one-way slabs - Part 1: • Design of Reinforced C...
- Design of two-way slabs - Part 1: • Design of Reinforced C...
- Design of Beams - Part 1: • Design of Reinforced C...
- Design of Columns - Part 1: • Design of Reinforced C...
- Foundations Part 1: • Foundations (Part 1) -...
Пікірлер: 63
Great explanations throughout. Thank you!
Thank you so much Dr. It is very helpful. My semester of study for concrete design was just explained in less than a weeks.
@MrElgamal77
2 ай бұрын
Happy that it helped you
Thank you Dr. For these videos, please do on ribbed slab and flat slab.
استمر ياا دكتور المحتوى مفيد جدا.
Thank Dr. for this great work, kindly do vids on flat slab design.
thank you DR SHARIF
Doctor I loveeeeeee yooooouuuuu🌹🌹❤️❤️
Thank you very much sir
جزاك الله خير يادكتور نريد المزيد من المحاضرات وياحبذا اذا اشغلت مبني متعدد الطوابق
Great lecture , I have a question for the example solid slab with thickness 200 mm , does not it need a top reinforcement mesh to resist shrinkage stress ?
Please do you have a video on understanding bending moment and shear force calculation and diagram
Hi Dr.. Thank you for the much informative and valuable tutorials, one question though, from the structural analysis section, why are we using values for moments and shear, in table 3.12 from the simply supported section and not the continuous section? I thought the slab was continuous.
@ahmedalaamri5060
3 жыл бұрын
Continuous in the BS code refers to the continuity of slabs in that particular joint and not the reinforcement. To counteract the top moment and the partial fixity between the beam and the slab, BS8110 recommends certain top reinforcement at the simple end. All the best
When calculating A s-min should we take value of h as 175 or 145? Timeframe 12:11
@MrElgamal77
Жыл бұрын
175
Thanks Prof. You have made everything become so easy. I have a question please. This example you have solved, shows a one way continuous slab and its analyzed such as you have done, with the continuity in the shorter span. How about if the continuous spanning were to have been in the longer span of this same example?
@ahmedalaamri5060
3 жыл бұрын
The dominant side is always the short side and being moment is major towards that span and not the long span. All the best
@ahmedalaamri5060
3 жыл бұрын
The dominant side is always the short side and being moment is major towards that span and not the long span. All the best
@MrElgamal77
3 жыл бұрын
In one-way slabs, we do not design in the long direction. For longer span, we take only the minimum.
Salamu Alikum, would you please make some excel lecture on concrete design. thank you
Great explanations prof. You always makes things simple. I have a question on curtailment iam a bit confused on how to use c=0.15l I always use the 0.3l and disregard the 50% of c=0.15l Correct me if I may be wrong because I do that in real structures
@MrElgamal77
Жыл бұрын
What you are doing is correct and more safe.
Under "As required", "As provided" you could have explained how we arrive at those values...l got lost there..
Thanks doctor,could you please help on how to design ribbed and flat slab.
@MrElgamal77
4 жыл бұрын
I have first to prepare a video about footings.
Great work I have one question, how can I design the cantilever of one way slab?
@ahmedalaamri5060
3 жыл бұрын
You may take it as Wl2/2 or if you want to be more precise, redistribute the moment taking into account the top moment of the continuous part of the neighbour slab
Dear Dr. Sharif I confused difference between actual span/d and allowable span/d . what is actual span/d and allowable span/d ?
@ahmedalaamri5060
3 жыл бұрын
Allowable is the maximum allowed by the code, and the actual is whatever is happening in the slab you are solving sue to the provided thickness and reinforcement. These are reflecting the maximum allowed deflection and the actual deflection. All the best
Hi Dr. For the minimum steel, is the h not 175mm. You used 145mm
@MrElgamal77
4 жыл бұрын
Thank you. You are right. 145 was used by mistake.
any one plz how to find this As,req and spacing
When checking for deflection, what if the modification factor is greater than 2?
@ahmedalaamri5060
3 жыл бұрын
Reduce the thickness of the slab, the slab is thicker than required
@ahmedaweysmohamed6378
2 жыл бұрын
Take 2 as a modification factor
You are using BS8110 of which year ?
Good day sir, since this is a continuous structure why did you make use of simply supported moment formulas for the continuous beam
@MrElgamal77
2 жыл бұрын
I used the simply only at the end beam. This will be more safe as it gives higher +ve moment. At the connection of the slab with the end beam, we use minimum top reinforcement to consider for continuity.
from the beginning of the question you stated that diameter of bar is 10 and used that to calculate of the width of the slab. but in the middle of the calculation for reinforcement, you used a diameter of 8 (10:11) any explanation?
@MrElgamal77
Жыл бұрын
At the beginning, we assume 10 mm. Then we calculate the thickness and round it. After that, you can use any diameter provided that deflection and shear are fine. Changing from 10 to 8 or to 12 will have almost no effect.
Hi Dr. i have noted that in the calculation of reinforcement, at outer support, where the moment is 0, you have indicated that the Asmin = 189. in your previous lectures, you had indicated that the Asmin is derived from table 3.25, and in this case where fy =460N/mm2 and the section is rectangular, the minimum dimension of reinforcement is 0.13%. Upon calculation, i.e. 0.13% x 1000 x 175mm (b=1000mm, h= 175mm) you get Asmin as 227.5 mm , not 189 mm. Kindly comment. Regards,
@MrElgamal77
4 жыл бұрын
Hi Ezra. You are right. I think it was multiblied by d instead of h by mistake. Thanks.
Please what if the spans are not equal, can table 3.12 still be used?
@yaasirahmed1528
4 ай бұрын
yes , find average moments using adjacent length at interior supports
Why didn’t you use the values of the “continuous slab” instead of the simply supported
@MrElgamal77
3 ай бұрын
Because the last support is assumed simply supported. This is a conservative design and will give more positive momentum in the first span
please check the F at 9.32.You dont need to multiply the F by the length again when finding the moments since its already done at the top
@MrElgamal77
Жыл бұрын
No. You need to multiply it again by the length to get the moment. For shear, you do not.
Sr how did you get Area minimum= 188,5. 'cause i followed all your instructions but i got 227,5 can you pls make me understand
@engrxiddig
Жыл бұрын
There is a mistake
at 6:38 it says total design ultimate load = 12.08 KN/m^2. then next slide the force = 12.08 * 4.5 = 54 KN , how shouldnt it be 54 kN/m
@MrElgamal77
4 ай бұрын
Yes. It is correct. When you solve for 1 m strip, the 12.08 kN/m2 will be 12.08 kN/m. Then the resultant will be 12.08 × span (4.5)= about 54 kN
15:22 How did v =Vmax/(bd) give you 0.225??
@MrElgamal77
Ай бұрын
I do not remember. I prepared it a long time ago.
@MrElgamal77
Ай бұрын
I checked it. It = V/(bd)= 32.6*1000/(1000*145)=0.225
😚
0.0013x1000x175=227.5
@MrElgamal77
2 жыл бұрын
You are correct. The 188.5 was a mistake.
@agostinhoinocencio7013
2 жыл бұрын
@@MrElgamal77 thanks so much Sr i appreciate that
Very fast calculations not explained clearly
Thank you Dr. For these videos, please do on ribbed slab and flat slab.