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Пікірлер: 14
@fano72Ай бұрын
Cool, I like how the sqrt 3 appears suddenly 🤓
@user-yt5nt5wv3gАй бұрын
A very very good ways of solutions. You deserve much respect. Although I am an English teacher, I follow your presency.
@learncommunolizer
Ай бұрын
Wow, thank you very much
@HambastegyАй бұрын
🙏
Ай бұрын
2. Less that 3 second with sustitution
@user-ec5ip3vp2rАй бұрын
2
@user-dq3uh6ee5wАй бұрын
2, -1+_iV3.
@mohsenkhadhraoui1790Ай бұрын
X=2
@laobernadus5743Ай бұрын
X³ = 8 X³ = 2³ X = 2
@StudentofgreatmagadhАй бұрын
Students of mathematix is here 😝 first🥇
@altvampАй бұрын
Non, numbers don't have roots.
@rogerphelps9939Ай бұрын
X = 2exp(i. theta) where 3. theta = 2npi. n= 0, 1 or 2..Simple. No need for cvonvoluted old fashioned nonsense.
@docjogi9
Ай бұрын
Sorry, Roger, I think you're not really right, cause theta must be 2npi/3 with n = 0,1, or 2. And for me the old fashioned solution is nice and necessary.
@rogerphelps9939
Ай бұрын
@@docjogi9 Absolutely right. My typo but the point of my post remains. This man is still in the 17th century.
Пікірлер: 14
Cool, I like how the sqrt 3 appears suddenly 🤓
A very very good ways of solutions. You deserve much respect. Although I am an English teacher, I follow your presency.
@learncommunolizer
Ай бұрын
Wow, thank you very much
🙏
2. Less that 3 second with sustitution
2
2, -1+_iV3.
X=2
X³ = 8 X³ = 2³ X = 2
Students of mathematix is here 😝 first🥇
Non, numbers don't have roots.
X = 2exp(i. theta) where 3. theta = 2npi. n= 0, 1 or 2..Simple. No need for cvonvoluted old fashioned nonsense.
@docjogi9
Ай бұрын
Sorry, Roger, I think you're not really right, cause theta must be 2npi/3 with n = 0,1, or 2. And for me the old fashioned solution is nice and necessary.
@rogerphelps9939
Ай бұрын
@@docjogi9 Absolutely right. My typo but the point of my post remains. This man is still in the 17th century.