How much latent heat is this cooing coil removing?
Your air handling unit has the following conditions:
Airflow = 1,000 cfm
Coil EAT = 95F db / 78F wb
Coil LAT = 50F db / 49.5F wb
Answer:
First, determine the grains per pound of dry air for each condition.
EAT = 117.4 Grains / Lb of dry air
LAT = 51.6 Grains / Lb of dry air
Second, plug into this equation.
Q(L) = CFM x 0.68 x dw
Where dw = the difference in grains/lb of dry air
Q(L) = latent heat in BTU/hr
Conversion factor (at sea level, standard air conditions) = 0.68 = 60 min/hour x 0.075 lb/ft3 x 1076 Btu/lb x 1 lb/7000 grains
Q(L) = 1,000 x 0.68 x (117.4 - 51.6) = 44,744 BTU/hr
Answer = 44,744 BTU/hr of latent heat removal.HVAC-TV KZread channel: / @hvac-tv
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